A dice is thrown once. Find the probability of getting a number greater then 2.

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19 Oct 2010 Fine the Probability?

A dice is thrown once. Find the probability of getting a number greater then 2.

OPtion

1) 1/3
2) 2/3
3) 1
4) 3/4
5) 1/2
6) 3/5
7) 5/6
8) 1/6
9) 4/5
10) 2/5

Solution

Total possible cases = 6
Numbers greater than 2 on the dice = (3,4,5,6)
So Probability of getting a number > 2 =4/6=2/3

Correct Option: 2 Best Solution (7)

Md Intshamuddin   13 years AGO

P(n>2)=N(E)/N(S)=4/6=2/3

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Gunaseelan   13 years AGO

There are four choices out of 6.
Probability =(4/6)=2/3

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Pargat Pal Singh   13 years AGO

The all possible outcomes of throwing a dice are 1, 2, 3, 4, 5 and 6. So number of all
possible outcomes is 6.
Let E be the favorable outcome. The outcomes favorable to E are {3,4,5 and 6}.
The number of outcomes favorable to E is 4.
So,
P (E) = Number of outcomes favorable to E / Total Number of outcomes
= 4 / 6
= 2 / 3

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MP    13 years AGO

4/6=2/3

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SUDESHNA SEN   13 years AGO

Probable no. of outcomes=6.
A: getting a number greater than 2.
So, outcomes favourable to A= 4.
Therefore, probability of getting a number greater than 2= 4/6= 2/3.... Option 2)

Like? Yes (1) | No   

kamal   13 years AGO

Probable no. of outcomes=6.
A: getting a number greater than 2.
So, outcomes favourable to A= 4.
Therefore, probability of getting a number greater than 2= 4/6= 2/3.... Option 2)

Like? Yes (1) | No   

Prabir Sen   13 years AGO

Probable no. of outcomes=6.
A: getting a number greater than 2.
So, outcomes favourable to A= 4.
Therefore, probability of getting a number greater than 2= 4/6= 2/3.... Option 2)

Like? Yes (1) | No