There are 98 persons in a room, from these persons 13 are both eye blind and 12 are one eye blind.

M4maths Previous Puzzles

01 Nov 2010 Group of blind person

There are 98 persons in a room, from these persons 13 are both eye blind and 12 are one eye blind.
Minimum number of persons with both the corrected eye required to make the total number of eyes a perfect
cubic number are

OPtion

1) 28
2) 30
3) 29
4) 27
5) 26
6) 31
7) 32
8) 35
9) 58
10) 45

Solution

Total eyes of 73 persons = 73*2 = 146
Total eye of 12 persons = 12*1 = 12
Total no of eyes = 158
Extra eyes required = 216 (nearest cubic number) – 158
= 58, therefore 29 extra persons are required.

Correct Option: 3 Best Solution (0)