k : k^2 :: k^2 : 8 product of all real integral values of k is?

M4maths Previous Puzzles

11 Nov 2010 Find the product of possible value of K?

k : k^2 :: k^2 : 8
product of all real integral values of k is?

OPtion

1) 1
2) 2
3) 6
4) 14
5) 5
6) 0
7) 8
8) 16
9) 9
10) 10

Solution

According to the given condition k^4 = 8k
On solving, we get k = 0, 2
product of possible value of k is 0*2 = 0

Correct Option: 6 Best Solution (5)