M4maths Previous Puzzles

23 Jul 2009 arrange the boys

Names of 10 friends are
RAHUL, MOHAN, AKBER, SUNIL, LALIT, AASHU, GOKUL, IMRAN, KANIK & SUMIT
These names are arranged in increasing order according to a coded method.
If out of these 10 names
RAHUL is coded as 7
GOKUL is coded as 8 and
IMRAN is coded as 6
then in this coded language MOHAN is

OPtion

1) 5
2) 6
3) 7
4) 8
5) 9
6) 10
7) 1
8) 2
9) 3
10) 4

Solution

A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26
For RAHUL sum of positions of alphabets = 18+1+8+21+12=60 7
For MOHAN sum of positions of alphabets = 13+15+8+1+14=51 4
For AKBER sum of positions of alphabets = 1+11+2+5+18=37 1
For SUNIL sum of positions of alphabets = 19+21+14+9+12=75 9
For LALIT sum of positions of alphabets = 12+1+12+9+20=54 5
For AASHU sum of positions of alphabets = 1+1+19+8+21 = 50 3
For GOKUL sum of positions of alphabets = 7+15+11+21+12= 66 8
For IMRAN sum of positions of alphabets = 9+13+18+1+14= 55 6
For KANIK sum of positions of alphabets = 11+1+14+9+11= 46 2
For SUMIT sum of positions of alphabets = 19+21+13+9+20 = 82 10

On arranging them in increasing order, MOHAN should be coded as 4.

Correct Option: 10 Best Solution (1)

Mehul MKDP   15 years AGO

CODE IS MADE UP AS SUM OF ASCII CODE
OF EACH CHAR. IN THEIR NAME.
AND ARRANGED IN ASCENDING ORDER ON THAT CODE
RANK (CODE) IS GIVEN.

RAHUL is coded as 7 ( 380 )
GOKUL is coded as 8 and ( 386 )
IMRAN is coded as 6 (375 )
MOHAN = 371

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