An integer is such that twice of its square is 7 less than the 9 multiple of that integer. Integer

M4maths Previous Puzzles

25 Nov 2010 Find the number?

An integer is such that twice of its square is 7 less than the 9 multiple of that integer. Integer is

OPtion

1) 6
2) 4
3) 8
4) 2
5) 5
6) 1
7) 7
8) 3
9) 9
10) 10

Solution

According to the given condition
2x2 = 9x – 7
Only 1 satisfies this condition

Correct Option: 6 Best Solution (18)

Dr.Dipin Singh   13 years AGO

An integer is such that twice of its square is 7 less than the 9 multiple of that integer.
If Integer is x, then
2*x*x=9*x-7 or 2x^2-9x+7=0 ,
solving it , we get x=1 and 7/2 out of which 1 is only integer value as required.

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VIJI   13 years AGO

Let number be X
Given that :2(X)^2=9X-7
2X^2-9X+7=0
x=7/2 or x=1
Hence x=1

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Bankim   13 years AGO

2*x^2=9x-7

when x=1,

2*x^2=9x-7 means 2=9-7=2

Like? Yes (1) | No   

SUDESHNA SEN   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

Mamon Sengupta   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

Trishita Dasgupta   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

ASHOK ROY   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

Sudeshna Sengupta   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

Parbati Sen   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

Abhishek Mukherjee   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

ANIRBAN CHATTERJEE   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

DEBALINA CHAKRABORTY (DUTTA)   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

JEEVAN DAS   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

JAYEETA DESHMUKH   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

PINKU SUD   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

SARBANI DAS GHOSH   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

TAPAN SINGHA   13 years AGO

2x^2= 9x-7,
or, 2x^2-9x+7=0,
or, 2x^2-2x-7x+7=0,
or, 2x(x-1)-7(x-1)=0,
or, (x-1)(2x-7)=0,
therefore, x=1, (7/2)
So, the integer is= 1...... Option 6)

Like? Yes (1) | No   

madhuri   13 years AGO

2(x^2)=9x-7
solving this, x=1

Like? Yes (1) | No