Unit place digit in 3^(3^3) –(3^3)^3 is

M4maths Previous Puzzles

20 Jan 2011 Unit place?

Unit place digit in 3^(3^3) –(3^3)^3 is

OPtion

1) 4
2) 3
3) 2
4) 1
5) 0
6) 9
7) 8
8) 7
9) 6
10) 5

Solution

unit place digit of first part = 7 and that of second part = 3 so difference = 4

Correct Option: 1 Best Solution (17)

Bimal   13 years AGO

3^(3^3) –(3^3)^3 = 3^27-3^9

last digit of 3^27= 7......
last digit of 3^9= 3....
unit digit of 3^(3^3) –(3^3)^3 = 3^27-3^9 will be 7-3=4

Like? Yes (4) | No (1)  

Brij   13 years AGO

3^27-27^3; unit digit will be 7-3=4

Like? Yes (4) | No (1)  

Dolly   13 years AGO

last digit of 3^27 is 7 and last digit of 27^3 is 3.

7-3=4

Like? Yes (4) | No (2)  

A.P.Singh   13 years AGO

Unit place digit in 3^(3^3) –(3^3)^3 is 7-3=4

Like? Yes (4) | No (2)  

dhiresh   13 years AGO

3^(3^3) –(3^3)^3=3^27-27^3
unit digit of 3^27= unit digit of 3^3=7
and unit digit of 27^3=3
so diffrence of 7-3=4
option 1 is correct.

Like? Yes (3) | No (1)  

S. Singh   13 years AGO

7-3=4

Like? Yes (4) | No (2)  

ravi jha   13 years AGO

3^27(3 9 7 1 3 repeat at 5th position)
so last digit=7
27^3(7 9 3)
last digit 3
so answer =7-3=4
so obtion 1

Like? Yes (2) | No (1)  

ATRI SANYAL   13 years AGO

3^(3^3)-(3^3)^3= 3^27-27^3= 3^27-3^9
Now, 3^27 has a unit value of 7 [since mod(27/4)=3 and 3^3= 27] and 3^9 has a unit value of 3 [since mod(9/4)=1 and 3^1=3], so the difference is 7-3=4..... Option 1)

Like? Yes (3) | No (3)  

goutam Choudhury   13 years AGO

3^(3^3)-(3^3)^3= 3^27-27^3= 3^27-3^9
Now, 3^27 has a unit value of 7 [since mod(27/4)=3 and 3^3= 27] and 3^9 has a unit value of 3 [since mod(9/4)=1 and 3^1=3], so the difference is 7-3=4..... Option 1)

Like? Yes (2) | No (2)  

Rama Chandra Prakash Kapa   13 years AGO

unit place digit of 3^(3^3) = 7
unit place digit of (3^3)^3 = 3

so unit place digit of 3^(3^3)-(3^3)^3=7-3=4

Like? Yes (1) | No (2)  

Ranjeet Verma   13 years AGO

3^9-9^3=18954
so unit place digit =4

Like? Yes (1) | No (2)  

shashank saxena   13 years AGO

3^27-3^9
7-3
4

Like? Yes (1) | No (2)  

Mamon Sengupta   13 years AGO

3^(3^3)-(3^3)^3= 3^27-27^3= 3^27-3^9
Now, 3^27 has a unit value of 7 [since mod(27/4)=3 and 3^3= 27] and 3^9 has a unit value of 3 [since mod(9/4)=1 and 3^1=3], so the difference is 7-3=4..... Option 1)

Like? Yes (2) | No (3)  

ASHOK ROY   13 years AGO

3^(3^3)-(3^3)^3= 3^27-27^3= 3^27-3^9
Now, 3^27 has a unit value of 7 [since mod(27/4)=3 and 3^3= 27] and 3^9 has a unit value of 3 [since mod(9/4)=1 and 3^1=3], so the difference is 7-3=4..... Option 1)

Like? Yes (3) | No (4)  

Suresh Varma P   13 years AGO

3^27 - 27^3 = 7625597484987 - 19683 = 7625597465304

so the unit place is 4 Ans: option 1

Like? Yes (2) | No (4)  

Sneha Latha M   13 years AGO

We have to calculate 3 power 27 - 27 power 3:
7625597484987-19683=7625597465304
then units place is 4.

Like? Yes (1) | No (3)  

kapil    13 years AGO

1st term unit place 7 and of other is 3

Like? Yes (1) | No (3)