Minimum sum of 5 positive integers on the basis of following conditions 1. 1 is not allowed

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03 Feb 2011 Sum of 5 positive integers?

Minimum sum of 5 positive integers on the basis of following conditions

1. 1 is not allowed
2. Two successive integers are not allowed
3. First two prime numbers are not allowed

OPtion

1. 45
2. 41
3. 20
4. 37
5. 39
6. 22
7. 38
8. 43
9. 44
10. 40

Solution

Integers are 4, 6, 8, 10, 12

Correct Option: 10 Best Solution (10)

Dr.Dipin Singh   13 years AGO

1. 1 is not allowed
2. Two successive integers are not allowed
3. First two prime numbers (2,3) are not allowed .
Minimum possible number is 4.
Next number can be 6 only as two successive integers are not allowed.

Under given conditions, Minimum sum of 5 positive integers will be 40 as 4+6+8+10+12=40.

Like? Yes (4) | No (1)  

Dimple   13 years AGO

First integer will be 4 and then next 4 even numbers.
sum =40

Like? Yes (3) | No (1)  

Arneet   13 years AGO

1,2,3 are not allowed.

4+6+8+10+12=40

Like? Yes (3) | No (1)  

Bimal   13 years AGO

4+6+8+10+12=40

Like? Yes (1) | No   

dharmaveer   13 years AGO

based on the given condition, possible first 5 positive integers are 4,6,8,10,12.
and the sum is 40.

Like? Yes (2) | No (2)  

Suresh Varma P   13 years AGO

4 + 6 + 8 + 10 + 12 = 40

Like? Yes (1) | No (1)  

SUJIT PATTANAYAK   13 years AGO

4+6+8+10+12 = 40

Like? Yes (1) | No (1)  

Sneha Latha M   13 years AGO

possibility for getting minimum sum 5 positive integers is 4,6,8,10,12
so the sum is 40.

Like? Yes (1) | No (1)  

Prabir Sen   13 years AGO

4+6+8+10+12= 40..... Option 10)

Like? Yes (1) | No (1)  

susmit   13 years AGO

4+6+8+10+12=40.
according to given conditions.
1. 1 is not allowed.
2. Two successive integers are not allowed.
so 2 and 3 are not allowed.
3. First two prime numbers are not allowed .

Like? Yes (1) | No (2)