A positive integer is such that the difference of its square and square root is 252. What will be the sum of that positive integer, square of that integer and fourth root of that integer?
let the positive integer is x, then according to the given condition
x^2 - sqrt(x) = 252
since difference is 252, which is an integer, and sqrt(x) is also involved, so definitely x will be a perfect square integer. Check 1,4,9 in x, but no satisfactory result will obtain. now if we take 16 in x, we will get 256-4 = 252, hence x will be 16. apply the value of x in desired expression.