There are 8 boys and 10 girls. How many methods are possible to place all of them in such a way so t

M4maths Previous Puzzles

24 Aug 2011 arrangement

There are 8 boys and 10 girls. How many methods are possible to place all of them in such a way so that no two girls could sit together.

OPtion

1) 10
2) 8
3) 90
4) 45
5) 56
6) 80
7) 28
8) 40
9) 100
10) none of these

Solution

if we place 8 boys then we will get 9 places among these boys, but girls are 10, so it is impossible to place them according to the condition given. so answer is 0

Correct Option: 10 Best Solution (7)