The cost of n dozen banana is x rupee more than 100 rupee and the cost of 6n dozen banana is 14x rupee less than 700 rupee. Which of the following is the cost of 1 dozen banana (Given that n and x are positive integers)
let the cost of 1 dozen banana is y rupee
then n*y = 100+x
and 6n*y = 700-14x
take n*y = 100+x from first equation in the second equation, we will get
6(100+x) = 700-14x
or 600+6x = 700-14x
or 20x = 100
or x = 5
on putting x=5, n*y = 100+5 = 105