x+y+z>10 y+z>10 x+z>10 possible set for x,y,z will be

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23 Sep 2011 x y z ?

x+y+z>10
y+z>10
x+z>10
possible set for x,y,z will be

OPtion

1) 3,8,4
2) 5,6,4
3) 6,4,6
4) 4,7,5
5) 7,4,5
6) 5,5,6
7) 5,6,5
8) 5,5,5
9) 8,4,4
10) more then one are possible

Solution

5,5,6 satisfies all the three conditions

Correct Option: 6 Best Solution (10)

jai Narayan Mishra   12 years AGO

by option checking it is clear that 5,5,6 is right option

Like? Yes (13) | No (5)  

Prerna   12 years AGO

Only
6) 5,5,6
satisfies given conditions.
x+y+z = 16>10
y+z=11 >10
x+z=11>10

Like? Yes (6) | No   

Prince varshney   12 years AGO

This can be doen by putting values of xyz in equations and the values which are satisfying the equation are of option 6.
As let x=5, y=5,z=6
first equation ==>5+5+6>10
second eqn==>5+6>10
Third eqn==>5+6>10
hence ans is 6 option

Like? Yes (4) | No (2)  

Soumya Parhi   12 years AGO

The possible set is x=5,y=5,z=6
Here x+y+z=5+5+6=16>10
y+z=5+6=11>10
and x+z=5+6=11>10

Like? Yes (2) | No (1)  

Nishant    12 years AGO

(5,5,6) is satisfying the above condition
since,
x=5,y=5,z=6
x+y+z=16>10
y+z=11>10
x+z=11>10

Like? Yes (1) | No   

Joy   12 years AGO

The rest do not fulfill..!!

Like? Yes (1) | No   

Ankit   12 years AGO

follow all condition

Like? Yes (2) | No (1)  

soumya goyal   12 years AGO

simply put the options and check the ans..to save tym u can first check values for x+z then y+z.
ans is 5,5,6

Like? Yes (1) | No (1)  

somnath ghosh hazra   12 years AGO

SIMPLY BY MANIPULATING RESULTS OF THE OPTIONS GIVEN .BY HIT AND TRAIL METHOD

Like? Yes (1) | No (1)  

dharmil   12 years AGO

5,5,6.
only this option satisfies the condition..
Y+Z>10.
X+Z>10.

Like? Yes (1) | No (1)