After dividing an amount into two parts, Mr. Suresh invests these parts in two different business.
In first, he gains 50% profit whereas in second he has a loss of 25 %.Total profit of
Mr. Suresh in first business is 1888 rupee. What is the total investment of Mr. Suresh if he gains
23 % profit over all.
(One variable solution)
Consider that 100 Rs is invested, then two parts are x & (100 - x)
Taking 50 % profit x becomes (3/2) x
& taking 25% loss (100 – x) becomes (3/4)(100 – x)
As total profit is 23 % hence
[(3/2)x +(3/4)(100 – x)] – 100 = 23
On solving x = 64
Profit = 64 * 50/100 = 32 in every 100 rupee
Overall profit in first business = 1888
Total investment = 100 * 1888 / 32 = 5900
Alternate method
Let total investment = P & part investments are x & (P – x)
According to given condition
x/2 = 1888 implies x = 3776
Similarly according to other condition
3x/2 +(3/4)(P – x) = P 123/100
=>3/2 * 3776 +(3/4)(P – 3776) = P 123/ 100
=>3 * 1888 + (3 /4) P – 3 * 944 = 123 P/100
=>5664 – 2832 = 123 P /100 – (3/4) P
=>2832 = (123 P – 75 P)/100
=>2832 = 48 P/100
=>P = 2832 * 100/ 48 = 5900.