width and thickness of two iron rails between two stations 5 km. apart are 20 cm. and 15 cm. If density of iron is 7200 kg/m^3, then total iron used to make the 2 rails will be
OPtion
1) 1560000 kg
2) 1080000 kg
3) 1240000 kg
4) 1540000 kg
5) 2160000 kg
6) 2540000 kg
7) 2820000 kg
8) 1860000 kg
9) 3040000 kg
10) none of these
Solution
total mass = number of rails * volume * density
= 2 * 5000 * 0.2 * 0.15 * 7200
= 10000 * 0.03 * 7200
= 300 * 7200 = 2160000 kg
"Obvious" is the most dangerous word in mathematics.
Eric Temple Bell
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