if x + y = 1/x^2 + 1/x^3 then y(1/2) - y(1) will be here y(n) is the value of y at x = n

M4maths Previous Puzzles

27 Jan 2012 value of y

if x + y = 1/x^2 + 1/x^3
then y(1/2) - y(1) will be
here y(n) is the value of y at x = n

OPtion

1) 2
2) 2.5
3) 3
4) 3.5
5) 4
6) 7.5
7) 9.5
8) 11.5
9) 13
10) none of these

Solution

y(1/2) = 23/2 = 11.5
y(1) = 1
so difference = 10.5

Correct Option: 10 Best Solution (21)

Dr.Dipin Singh   12 years AGO

x + y = 1/x^2 + 1/x^3

y = 1/x^2 + 1/x^3 -x
y(1) = 1+1-1=1
y(1/2) = 4+8-1/2 = 23/2
y(1/2) - y(1) = 23/2 -1 = 21/2 = 10.5 .. none of these ..option 10

Like? Yes (13) | No (1)  

pavan kumar   12 years AGO

here at x=n y=y(n) then at x=1/2 y=y(1/2)
then 1/2+y(1/2)=4+8 then y(1/2)=11.5
and similarly y(1)=1 then y(1/2)-y(1)=11.5-1=10.5

Like? Yes (3) | No (1)  

Shubham   12 years AGO

y(n)=1/x^2 + 1/x^3 - x
y(1/2)=4 + 8 - .5 =11.5
y(1)=1 + 1 - 1 =1

y(1/2) - y(1) = 11.5-1=10.5 i.e. non of these options

Like? Yes (2) | No   

B.Senthil Kumar   12 years AGO

y(1/2)=23/2
y(1)=1
23/2-1=21/2
There is no option so option 10 is correct

Like? Yes (2) | No   

Jason   12 years AGO

if x + y = 1/x^2 + 1/x^3
then y(1/2) - y(1) will be 11.5-1= 10.5
none of these

Like? Yes (2) | No   

Debashis Dey   12 years AGO

y(1/2)=4+8-0.5=11.5
y(1)=1+1-1=1
y(1/2)-y(1)=11.5-1=10.5
hence none of these

Like? Yes (2) | No (1)  

~Sandeep~   12 years AGO

y(n) = 1/x^2 + 1/x^3 - x
y(1/2) = 1/(1/2)^2 + 1/(1/2)^3 - 1/2 = 4+8-1/2
Hence y(1/2)= 11.5
y(1) = 1+1-1 =1
y(1/2) - y(1) = 10.5 (10) none of these)

Like? Yes (2) | No (1)  

Shiv Kumar   12 years AGO

y(1/2) then
(1/2)+ y = 1/(1/2)^2 + 1/(1/2)^3------1
Simplyfying this equation The value of Y becomes 11.5

y(1) becomes 1+ y = 1/(1)^2 + 1/(1)^3------2
Simplyfying this equation Y becomes 1

Y(1/2) - Y (1) becomes 11.5 - 1 = 10.5

Like? Yes (1) | No   

VikrantMundhekar   12 years AGO

let n=(1/2)
; in above equation,
1/2+(1/2)y=1/(1/2)^2 + 1/(1/2)^3
;1/2y=11.5

let n=1
1+y=1+1-1
y=1

;1/2y-y=?
11.5-1=10.5

Like? Yes (1) | No   

GANESH PANDIAN.S   12 years AGO

y(1/2)=23/2
y(1)=1
y(1/2)-y(1)=23/2-1
=21/2=10.5

Like? Yes (1) | No   

ramesh singh   12 years AGO

for value n=1/2 y(1/2)=11.5
nd for n=1 y(1)=1
y(1/2)-y(1)= 11.5-1=10.5

Like? Yes (1) | No   

jai    12 years AGO

y(1/2)=23/2
y(1)=1
y(1/2)-y(1)=23/2-1
=21/2
There is no option here so option 10 is correct

Like? Yes (1) | No   

yazar   12 years AGO

y(1/2)=23/2
y(1)=1
y(1/2)-y(1)=23/2-1
=21/2
there is no option here so option 10 is correct

Like? Yes (1) | No   

rko   12 years AGO

y(1/2)=23/2
y(1)=1
y(1/2)-y(1)=23/2-1
=21/2
so option is 10

Like? Yes (1) | No   

Selva Narayanan A J   12 years AGO

from the above given eq:

Y = 1/X^2 +1/X^3 - X

SO, Y(1/2) = 1/(1/2)^2 + 1/(1/2)^3 - 1/2 = 11.5
Y(1) = 1 + 1 - 1 = 1

So, Y(1/2) - Y(1)= 10.5

Like? Yes (1) | No   

Anish Philip   12 years AGO

y(1/2) = 4+8-0.5=11.5
y(1) = 1
ans = 10.5

Like? Yes (1) | No   

Rakesh Kumar Kohli   12 years AGO

x + y = 1/x^2 + 1/x^3
=> y = 1/x^2 + 1/x^3 - x
So y(1) = 1 + 1 - 1 = 1 and
y(1/2) = 1/(1/2)^2 + 1/(1/2)^3 - 1/2
= 4 + 8 - .5 = 11.5
Thus y(1/2) - y(1)= 11.5 - 1 = 10.5
which is not in any of the 1) to 9) options, so option is 10).

Like? Yes (1) | No   

Akanksha Narula   12 years AGO

y(1/2)=4+8-1/2=23/2
y(1)=1+1-1=1
y(1/2)-y(1)=23/2-1=10.5

Like? Yes (1) | No   

sumanshu   12 years AGO

y(1)=1 , at x=1
y(1/2)=23/2 i.e 11.5 at x=1/2
so y(1/2)-y(1)=11.5-1=10.5
so none of these

Like? Yes (1) | No   

sridhar reddy   12 years AGO

y=1/x^2+1/x^3-x
Y(1/2)=4+8-1/2=23/2
y(1)=1
y(1/2)-y(1)=21/2=10.5

Like? Yes (1) | No   

Phaneendra Sandeep   12 years AGO

y=1/x^2+1/x^3-x
y(1/2)=11.5, y(1)=1
y(1/2)-y(1)=10.5

Like? Yes (1) | No