3x + 4y = 19 4x + 5y = 21 then 100x + 100y = ?

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31 Jan 2012 equation 3x + 4y = 19 4x + 5y = 21 then 100x + 100y = ?: OPtion
1) 100
2) 200
3) 377
4) 400
5) 512
6) 600
7) 700
8) 800
9) 991
10) none of these; Correct Option: 2 Best Solution (43)

A.P.Singh 12 years AGO

3x + 4y = 19
4x + 5y = 21

x+y=2
multiplying by 100
100x+100y=200

Like? Yes (5) | No (2)

shyoram Gurjar 12 years AGO

4x +5y =21
- (3x +4y =19)

= x + y =2

so 100x +100y=200

option 2

Like? Yes (3) | No (2)

pk 12 years AGO

here by solving the above two equations 3x+4y=19 and 4x+5y=21 we wil get thevaluesof x and y as x=-11 and y=13 then 100x+100y=100(-11)+100(13)=-1100+1300=200

Like? Yes (1) | No

KIRAN B. MALI 12 years AGO

By solving the two equations,
i.e., 3x+4y=19 and 4x+5y=21, we get the values of x=-11 and y=13,
substitute values of x and y in the equation 100x+100y we get 200... option 2...

Like? Yes (4) | No (3)

Dr.Dipin Singh 12 years AGO

3x + 4y = 19...........(1)
4x + 5y = 21..........(2)

subtracting (1) from (2)
x+y =2
100x +100y =200

Like? Yes (8) | No (7)

jerald 12 years AGO

x=-11 & y=13 and answer is 200

Like? Yes (1) | No

parul mishra 12 years AGO

on solving(by subtracting) both equations..
3x+4y=19.....*4
4x+5y=21.....*3
we get y=13 and x=-11
on putting the values of x&y in the given eq..
100x+100y=200
so option is (b)=200

Like? Yes (1) | No

kalyanikumarappan 12 years AGO

by solving the equations we get,
x=-11,y=13 so
1oox+100y=200

Like? Yes (1) | No

laika goyal 12 years AGO

3x+4y=19...(1)
4x+5y=21...(2)
multiply by 5 in eq. 1 and by 4 in eq. 2
then after solving it... we get
x=-11 and y=13
and then put it into the eq.
100x+100y and get result of it is 200.

Like? Yes (1) | No

santhosh 12 years AGO

consider it as 3x + 4y = 19->(1)
4x + 5y = 21->(2)
subtract (1) from (2) then you get x+y=2
multiplying both side by 100
100x+100y=200

Like? Yes (1) | No

Shiv Kumar 12 years AGO

By Solving 3x + 4y = 19 and 4x + 5y = 21, you will get X=-11 and Y= 13
100x + 100y = 100(x+y)= 100(-11+13) = 200

Like? Yes (1) | No (1)

balaji 12 years AGO

3x + 4y = 19 and 4x + 5y = 21
Find the x and y value from these equations.
then we got x=-11 and y=13
subtitute x and y value to 100x + 100y = ? ,
we got
-1100 + 1300 = 200

So, Answer is 200.

Like? Yes (2) | No (2)

Debashis Dey 12 years AGO

solving the equations we get y=13 and x=-11
therefore 100x+100y=200
option 2 is correct

Like? Yes (2) | No (2)

dhilip 12 years AGO

Solving these Equations we get x=-11;
So y=13, The answer is -1100+1300=200; So the option is 2.....

Like? Yes (2) | No (2)

shashi kumar 12 years AGO

substracting 2nd eqn from 1st,
x+y=2
100x+100y=200

Like? Yes (2) | No (2)

Tijo Jose 12 years AGO

3x + 4y = 19 -- (eqn 1)
4x + 5y = 21 -- (eqn 2)

(eqn 2) - (eqn 1):
x + y = 2
Therefore, 100x + 100y = 200
Option (2)

Like? Yes (2) | No (3)

YadeeshKumar 12 years AGO

3x + 4y = 19--(1)
4x + 5y = 21--(2)
------------
x + y = 2 -- (2)-(1)
100(x+y)=100*2=200

Like? Yes (3) | No (4)

K BASHA 12 years AGO

by solving 3x+4y=19
4x+5y=21

x=-11,y=13
then 100x+100y=200

Like? Yes (1) | No (2)

pavan kumar 12 years AGO

here by solving the above two equations 3x+4y=19 and 4x+5y=21 we wil get thevaluesof x and y as x=-11 and y=13 then 100x+100y=100(-11)+100(13)=-1100+1300=200

Like? Yes (1) | No (2)

Suresh Varma P 12 years AGO

By Solving the give equations:
x = -11
y = 13
100x + 100y = 200
Ans: option 2

Like? Yes (1) | No (2)

VikrantMundhekar 12 years AGO

after calculating above equation , we get
;x=-11
;y=13
so ans is 200

Like? Yes (1) | No (2)

B.Senthil Kumar 12 years AGO

by solving we get x=-11
and y=13
100x+100y=200

Like? Yes (1) | No (2)

jai 12 years AGO

by solving we get x=-11
and y=13
100x+100y=200

Like? Yes (1) | No (2)

Gunaseelan 12 years AGO

By Solving the given equation we get x=-11 and y=13
then 100x+100y=200

Like? Yes (2) | No (3)

yazar 12 years AGO

x=-11 and y=13
so option 2 is correct

Like? Yes (1) | No (2)

Ankur mangal 12 years AGO

bcos here x=-11
y=13
100x+100y=200

Like? Yes (1) | No (2)

Abhishek Divakar 12 years AGO

eq2-eq1 => x+y=2
100x+100y = 200

Like? Yes (1) | No (2)

saranya kumar 12 years AGO

given that
3x+4y=19
4x+5y=21
by solving the above eqn.
x=-11 & y=13 substituting the above values
100x+100Y=200

Like? Yes (1) | No (2)

rko 12 years AGO

x=-11,y=13
100x+100y=200
so option is 2 is correct

Like? Yes (1) | No (2)

Pratik Goyal 12 years AGO

on solving both the equations simultaneously we the value of x is -11 and coresssponding value of y is 13 so 100x+100y= 200

Like? Yes (1) | No (2)

sivakumar 12 years AGO

3x+4y=19....(1); 4x+5y=21....(2) equ(2) - equ(1); x+y=2; 100x+100y = 200;

Like? Yes (1) | No (2)

Rupayan Mondal 12 years AGO

by cross multiplication x = -11, y = 13
=> 100*x + 100*y = 100*(-11) + 100*13
=> 200

Like? Yes (1) | No (2)

suresh 12 years AGO

multiply 4 x 1st equation and 3 X 2nd equation and slove y=13, x=-11

Like? Yes (1) | No (2)

GANESH PANDIAN.S 12 years AGO

3X+4Y=19---->1
4X+5Y=21---->2
SOLVE 1 & 2 EQUATION WE GET
X=-11
Y=13
-1100+1300=200
SO ANSWER IS 200

Like? Yes (1) | No (2)

senthil 12 years AGO

x=-11 and y=13 then 100x+100y=200

Like? Yes (2) | No (3)

Nikhil Juyal 12 years AGO

3x + 4y = 19....(1)
4x + 5y = 21....(2)
Subtract (1) from (2)
we get x+y=2
then 100x + 100y = 200

Like? Yes (1) | No (2)

arunraj 12 years AGO

from the two equation x=-11 y=13

for 100x+100y= 200

Like? Yes (1) | No (2)

Sreenivasa Chowdary Nellore 12 years AGO

Sutract First equation from Second Equation

3x + 4y = 19 - - (1)
4x + 5y = 21 - - (2)

(2)-(1)
then (x+y) = 2

hence 100x+100y = 100(x+y)= 200.

Regards,
Sreenivasa Chowdary Nellore.

Like? Yes (1) | No (2)

GANESH MARAGANI 12 years AGO