k+x = 10, x+y+z >= 8 if y >= 3.5 and 0 <= z <= 4.2 all the 4 are positive real numbers then maxi

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09 Feb 2012 minimum

k+x = 10,
x+y+z >= 8
if y >= 3.5 and 0 <= z <= 4.2
all the 4 are positive real numbers
then maximum value of k will be

OPtion

1) 4.8
2) 5.3
3) 5.5
4) 6.7
5) 7.7
6) 9.7
7) 8.8
8) 3.5
9) 4.2
10) none of these

Solution

according to the given conditions y + z + 2 >= k
so maximum = 3.5 + 0 + 2 = 5.5

Correct Option: 3 Best Solution (0)