If in a coded language 32+57+48=11/23 27+62+51=26/3 And 19+72+53=33/8 Then 45+99+34=

M4maths Previous Puzzles

18 Sep 2009 Break the code

If in a coded language
32+57+48=11/23
27+62+51=26/3
And 19+72+53=33/8
Then 45+99+34=

OPtion

1) 25/13
2) 34/5
3) 18/19
4) 16/9
5) 23/7
6) 34/15
7) 48/23
8) 21/31
9) 21/13
10) 28/13

Solution

Here (32+57+48) is solved in the following manner
First divide 57 by 32, we get 1 and 25 as reminder then divide 48 by reminder we obtain 1 and 23 as
reminder hence the result code is 11/23. Similarly in second case (27+62+51), first divide 62 by 27
we get 2 and 8 as reminder then divide 51 by reminder we obtain 6 and 3 as reminder hence the result code is 26/3, similarly for others.

Correct Option: 5 Best Solution (0)