The difference of a 3 digit positive number and the formed by reversing the digits of the number is 99. Sum of the digits at units and thousands place is 11 and tens place is 1 less then the units place. Product of the 2 numbers will be
let the number is 100x+10y+z
so according to the given condition
(100x+10y+z)-(100z+10y+x) = 99
so x-z = 1
other conditions given are x+z = 11
and y = z-1
on solve this we find x = 6, y = 4 and z = 5
so number is 645