A and B complete a work in 10 days, B and C complete the same in 15 days, C and A in 20 days. How many days are required to do the same work if A, B, C work together.
one day work of all the 3 pairs are 1/10, 1/15, 1/20 respectively
so one day work of A, B, C will be 1/2[(1/10)+(1/15)+(1/20)] = 13/120
so days required = 120/13