Latest TCS Aptitude Question SOLUTION: A can do a work in 15, B in 45 and C in 75 days. A do work in day 1, B in day 2, C in day3, A in day 4, B in day 5, C in day 6 and so on. Finally they were paid 9000. Find B share

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A can do a work in 15, B in 45 and C in 75 days. A do work in day 1, B in day 2, C in day3, A in day 4, B in day 5, C in day 6 and so on. Finally they were paid 9000. Find B share?

Asked In TCS rinky das (11 years ago)

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rocks  (11 years ago)

A 15 A 15
B 45 take lcm 225 so B 5
c 75 c 3
1cycle 23 work
9000/225=40
23*9=207+15+3=225.... so B 9*5+3=48...48*40=1920(ANS),....................

Is this solution Helpfull? Yes (17) | No (10)  

Sanjay Singh  (11 years ago)

A's one day work=1/15=6.66%
B's one day work=1/45=2.22%
C's one day work=1/75=1.33%
(A+B+C)'s one day work=1/15+1/45+1/75=23/225=6.66+2.22+1.33=almost 10%
(A+B+C)'s work for 9 days(27 days)=(23/225)*9=23/25
on 28th day A's work 1/15 so total work=23/25+1/15=74/75
if we add B's work on 29th day then total work=74/75+1/45=227/225(exceeds 1)
so we will take only 28 day work.In 28 days A works 10 days.B and C work 9 days each.
So B's share=(9000/28)*9=2892.86

Is this solution Helpfull? Yes (5) | No (5)  

pihu  (11 years ago)

3103.45 is correct ans

Is this solution Helpfull? Yes (3) | No (6)  

sagar  (11 years ago)

ans is 1800

Is this solution Helpfull? Yes (3) | No (4)  

ganesh shankar  (11 years ago)

1920 is the ans

Is this solution Helpfull? Yes (2) | No   

sunil singh rathore  (11 years ago)

3103.44
b's shear

Is this solution Helpfull? Yes (1) | No (7)  

Sonal   (11 years ago)

B share 2812.5

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rahul  (11 years ago)

plz explain properly

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sagar  (11 years ago)

sanjay u r wrong
here in this q the efficiency of each worker is different
no doubt a will work for 10 days b for 9 and c for 9.
but b's effeciency is more as compare to c and less ac compare a.
hence b do about 20% of total work hence b should pay about 20% of total amount= 9000*20/100=1800 aprox near by option will be correct

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