Latest IBM Aptitude Question SOLUTION: two administrative assistants were typing a 135 page report if one admin assistant typed one and 5/10 times as many pages as the other, how many pages did the more rapid admin assi

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two administrative assistants were typing a 135 page report if one admin assistant typed one and 5/10 times as many pages as the other, how many pages did the more rapid admin assistant type?

Asked In IBM soniya (5 years ago)

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Devendra Marghade  (5 years ago)

27 pages

Let slower assistant types 'x' pages, then faster one types x*(1 & 5/10) = x*15/10 = 3x/2 pages.
So ratio of their pages typed = x : 3x/2 = 2 : 3
Therefore in total 135 pages, slower assistant types 135*(2/5)=54 pages and faster 81 pages.
Hence faster assistant typed 81 - 54 = 27 more pages.

Is this solution Helpfull? Yes (13) | No (7)  

Abhishek Kumar  (5 years ago)

1&5/10*x + x = 135
15*x/10 + x = 135
x = 54
radip admin typed = 15*x/10 = 15*54/10 = 81 pages

Is this solution Helpfull? Yes (8) | No (3)  

Rahul Sahare  (5 years ago)

As it is given in question that :-
rapid=1.5*slower;
so, the ratio become rapid/slower=3/2;
therefor in total 135 pages,slower assistant type 135*(2/5)=54pages and rapid type 81 pages.
hence faster assistant typed 81-54=27 more pages.

Is this solution Helpfull? Yes (1) | No (1)  

julia rossi  (4 years ago)

assistant a does x pages and assistant b does x + 5/10x pages.

x+(5/10x) = x + 1/2x = 2 1/2x = 2.5x = 135pages total.


x = 135/2.5 = 54pages

assistant a does x.....54 pages
assistant b does x+5/10x.......54 + 27 = 81 pages

81 - 54 = 27 pages more done by assistant b

Is this solution Helpfull? Yes | No (1)  

Niharika  (4 years ago)

let x+y=135
x=1*5/10y
so 1*5/10+y=135
then y=54
and x=81
difference is the more rapid papges typed=81-54=27;

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