Latest C Aptitude Question SOLUTION: Q. main() {i nt i=0; for(;i++;printf("%d",i)) ; printf("%d",i); } A. 1 Explanation: before entering into the for loop the checking condition is "evaluated". Here it evaluates to

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(#M40029267) C question C Keep an EYE

Q.
main()
{i
nt i=0;
for(;i++;printf("%d",i)) ;
printf("%d",i);
}

A. 1

Explanation: before entering into the for loop the checking condition is "evaluated". Here it
evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).

Asked In C MAN (11 years ago)

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