Latest Infosys Aptitude Question SOLUTION: could any one give clear explaination on the problems of crypto arithmetic,,,,plz solve this problem with detailed explaination.....banana+guava=orange.what is the value of o+r+a+n

BANANA
+GUAVA
-------
ORANGE
-------

means A+A=E, N+V=G, A+A=N, N+U=A, A+G=R, B+_=O

So just start from last
A+A=E
"A" can have d values ranging {0,1,2,3,4,5,6,7,8,9}
first lets take A=0... A+A= 0+0=0... Again d result is 0... means E=0... So not possible for 2 alphabets to have same number...

Lets take A=1... A+A= 1+1=2... A=1, E=2,... v have to find d value for "N"...
Look A+A=N (3rd term)... A+A is already "E" (ie E=2A)... So definitely N should not be 2A... Therefore N=2A+1... There should be remainder from the 2nd term...
so N=2A+1... N=2(1)+1= 3... Assign a value for to get a remainder... Take V=7
3+7=0 carry 1... 1+A+A=3...
next N+U=A...result should be 1... 3+8=1 carry 1...
next A+G=R... 1+1+7=9... There is no carry which means B nd O ll have d same value... so not possible... So try for different values...
Note here A+G=R should produce a carry... then only v can yield B+carry=O

By trial nd error method, Again start from last... Try A=2... Its also not possible... Agan A=3... Not possible...
Now A=4... E=2A=8... N=2A+1=9...
For getting a carry If i take V=1, A+G ll not produce carry... So take V=2... N+V=G... 9+2=1 carry 1... 1+A+A=9... N+U should produce 4... 9+5=4 so U=5... next A+G = 4+1=5 not producing carry... Here 4+(>5) only yields a carry...
So v should get G value >5...
So again trail nd error method, N+V=G... Lets take V=7 ..N+V=G... 9+7=6 carry 1...
1+A+A=N... N+U=A... 9+5=4 carry 1... 1+A+G=R... 1+4+6=1 carry 1... 1+B+_=O...
Values remaining is {0,2,3}
1+0+_=1 not possible
1+2+_=3


So
B=2, A=4, N=9, A=4, N=9, A=4
G=6, U=5, A=4, V=7, A=4
O=3, R=1, A=4, N=9, G=6, E=8

O + R + A + N + G + E
3 + 1 + 4 + 9 + 6 + 8 = 31

Ans : 31

@IAMATURE

Its Assign a value for "V" to get a remainder...
bcozzz already A+A=E... So definitely A+A should not be equal to N... So N+V should produce a carry... So A+A+1=N... (ie N=E+1)... Now we have to assign a value for V to get a carry...

I hope u understand this...

Is there any other method to solve it quickly?

B A N A N A+
- G U A V A
-------------
O R A N G E

===>
A+A = E
A+A+1 = E+1 = N
B+1 = O
A+G =R and carry 1
and B,O,A not equal to zero
for A

i am new for crypto......i did not understand this procedre.plz explain me in a clear manner i am basic learner for crypto i hope as early as possible...

31
by adding banana and guava
we get 314968=31

@ Saraswathy:
I did not understand this line :
Assign a value for to get a remainder... Take V=7
3+7=0 carry 1... 1+A+A=3...

thanx alot sarawathy 4r this explaination....

to all kindly tell wats wrong in
B A N A N A
4 8 7 8 7 8
G U A V A
+ 3 0 8 5 8
------------------------
O R A N G E
5 1 8 7 3 6


PLZ DO REPLY IF SEE IT

ne mre ans is also possible by this methd and that ans is:
287878
+40868
-----------
328746


3+2+8+7+4+6=30