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(#M40001878) INFOSYS QUESTION latest question Keep an EYE

Rahul took part in a cycling game with many others in a circular closed circuit. After pedaling for several minutes, he found that 1/5th of the cyclists ahead of him and 5/6th of the cyclists behind him together formed the total no. of participants. How many were participating in the race?

Asked In Infosys Aditi Sharma (14 years ago)

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(#M40001795) TCS QUESTION latest tcs question Keep an EYE

Which of the following groups of three can sit together on a bench?
(a) Freddy, Jonathan and Marta (b) Freddy, Jonathan and Vicky
(c) Freddy, Sarah and Vicky (d) Hillary, Lupe and Sarah
(e) Lupe, Marta and Roberto

Solution

I think, this is incomplete question and is only a part of question no M40001796

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Asked In TCS Aditi Sharma (14 years ago)

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(#M40001798) TCS QUESTION latest tcs question Keep an EYE

Make six squares of the same size using twelve match-sticks. (Hint : You will need an adhesive to arrange the required figure)

Asked In TCS Aditi Sharma (14 years ago)

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(#M40000552) INFOSYS QUESTION Solve for X Keep an EYE

(X)^1/3-(X)^1/9=60

Asked In Infosys Aditi Sharma (14 years ago)

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(#M40000575) IBM QUESTION IBM maths puzzle Keep an EYE

In a square, all the mid points are joined. The inner square is shaded. If the area of the square is A, what is the area of the shaded area?

Asked In IBM Aditi Sharma (14 years ago)

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(#M40001866) INFOSYS QUESTION latest infosys question Keep an EYE

Both the Allens and the Smiths have two young sons under eleven. The name of the boys whose ages rounded off to the nearest year are all different are Arthur, Bert, Carl and David . Taking the ages of the boys only to the nearest year , the following staements are true

* Arthur is three years younger than his brother
* Bert is the oldest
* Carl is half as old as one of the allen boys
* David is five years older than the younger smith boy
* the total ages of the boys in each family differ by the same amount
today as they did five years ago

How old is each boy and what is each boys family name.

Asked In Infosys Aditi Sharma (14 years ago)

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(#M40001609) TCS QUESTION latest puzzle Keep an EYE

The pace length P is the distance between the rear of two consecutive footprints. For men, the formula, n/P = 144 gives an approximate relationship between n and P where, n = number of steps per minute and P = pace length in meters. Bernard knows his pace length is 164cm. The formula applies to Bernard's walking. Calculate Bernard's walking speed in kmph.
a) 23.22 b) 8.78 c) 11.39 d) 236.16

Solution

n/P = 144
n = 144 * P
P = 1.64
n = 144 * 1.64 = 236.16 approx 236 steps per minute we are taking n in integer for it represents no. of steps
now v = d / t
v = 1.64 * 236 meter/minute
v = 387.04 meter / minute
or v = (387.04/1000)/(1/60)
or v = 387.04*60/1000 = 23.2224

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Asked In TCS Aditi Sharma (14 years ago)

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(#M40001514) TCS QUESTION latest riddle Keep an EYE

There are two box, one containing 10 red balls and the other containing 10 green balls. You are allowed to move the balls between the boxes so that when you choose a box at random and a ball at random from the chosen box, the probability of getting a red ball is maximized. This maximum probability is
a)3/4
b)14/19
c)37/38
d)1/2

Solution

14/19

To maximise probability of red ball,
Move 9 red balls in other box such that one box contains 1 red ball and other box contains 9 red and 10 green balls,

then

probability of getting red ball = 1/2 *1 + 1/2*9/19 = 1/2+9/38= 28/38=14/19
This is the answer given by DIPIN and is the correct answer


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Asked In TCS Aditi Sharma (14 years ago)

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(#M40001555) TCS QUESTION latest question Keep an EYE

Alok is attending a workshop. How to do more with lesser and today's theme is working with fewer digits. The speakers discuss how a lot of miraculous mathematics can be achieved if mankind (as well as womankind) had only worked with fewer digits.
The problem posed at the end of the workshop is
How many four digit numbers can be formed using the digits 1,2,3,4,5
(but with repetition) that are divisible by 4?

Can you help Alok find the answer?
a) 100 b) 125 c) 75 d) 85

Asked In TCS Aditi Sharma (14 years ago)

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(#M40001513) TCS QUESTION latest question Keep an EYE

After the typist writes 12 letters and addresses 12 envelopes, she inserts the letters randomly into the envelopes (1 letter per envelope). What is the probability that exactly 1 letter is inserted in an improper envelope?
a)0
b)12/212
c)11/12
d)1/12

Solution

Ans is Zero. Question is asking whether there is any chances of one letter getting inserted in an improper envelope, but there can-not be onr case as if one gets improper there is another letter who will be inserted in the improper envelope too...
This answer is given by RANVIR GUPTA and is correct answer

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Asked In TCS Aditi Sharma (14 years ago)

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