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(#M40001417) HCL QUESTION Keep an EYE

. Pipe A takes 16 min to fill a tank. Pipes B and C, whose cross-sectional circumferences are in the ratio 2:3, fill another tank twice as big as the first. If A has a cross-sectional circumference that is one-third of C, how long will it take for B and C to fill the second tank? (Assume the rate at which water flows through a unit cross-sectional area is same for all the three pipes.)

Solution

Let the cross sectional circumference of A is x so its area will be proportional to x^2, now it is given that A has a cross-sectional circumference that is one-third of C, so cross sectional circumference of C will be 3x, and its area will be proportional to 9x^2, according to the given condition, cross sectional circumference of B will be (2/3)*3x = 2x, so its area will be proportional to 4x^2
since pipe A for which cross sectional area is proportional to x^2, fills the tank in 16 min.
so pipe B and C for which sum of cross sectional area is proportional to 13x^2, will fill the same tank in 16/13 min.
but second tank is twice big in size so time required = 2*16/13 = 32/13 min.

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