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Placement Papers with Solutions

(#M40000569) IBM QUESTION Keep an EYE

In A,B,C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A,B,and C have equal number of marbles.

If the total number of marbles are 72, then the number of marbles with A at the starting
(a) 20
(b) 30
(c) 32
(d) 39

Asked In IBM Aditi Sharma (14 years ago)

Solved YadeeshKumar Read Solution (6)

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(#M40000568) IBM QUESTION Keep an EYE

If A,B,C are having some marbles with each of them. A has given B and C the same number of marbles each of them already have. Then, B gave C and A the same number of marbles they already have. Then C gave A and B the same number of marbles they already have. At the end A, B, and C have equal number of marbles. If x,y,z are the marbles initially with A,B,C respectively. Then the number of marbles B have at the end

(a) 2(x-y-z)
(b) 4(x-y-z)
(c) 2(3y-x-z)
(d) (x+y-z)

Asked In IBM Aditi Sharma (14 years ago)

Solved HARMEET KAUR Read Solution (10)

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(#M40000567) IBM QUESTION Keep an EYE

In 1978, a kg of paper was sold at Rs25/-. If the paper rate increases at 1.5% more than the inflation rate which is 6.5% a year, then what will be the cost of a kg of paper after 2 years?

(a) 29.12
(b) 29.72
(c) 30.12
(d) 32.65
(e) none of these

Asked In IBM Aditi Sharma (14 years ago)

Unsolved Read Solution (5)

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(#M40000566) IBM QUESTION printer problem Keep an EYE

Printer A prints 8192 character per min and printer B prints 13862 character per min four character ar e equal to one word. Printer A starts at 7:15 am while Printer B starts at 7:29 am then at what time both will have same no of words printed .

Asked In IBM Aditi Sharma (14 years ago)

Solved HARMEET KAUR Read Solution (8)

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(#M40000607) TCS QUESTION Keep an EYE

A Roman was born the first day of the 35th year before Christ and died the first day of the 35th year after Christ. How many years did he live?
(a) 70
(b) 69
(c) 71
(d) 72

Solution

A Roman was born the first day of the 35th year before Christ means before the start of year 0, 35 years has been past and died the first day of the 35th year after Christ means 35th year is about to start at his death so only 34 years has been completed so total years = 69


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Asked In TCS anuj (14 years ago)

Solved YadeeshKumar Read Solution (5)

Is this Puzzle helpful?   (14)   (0) Submit Your Solution Arithmetic

(#M40000606) TCS QUESTION Keep an EYE

Leena cut small cubes of 10 cm dimension each. She joined it to make a cuboid of length 100 cm, width 50 cm and depth 50 cm. How many more cubes does she need to make a perfect cube?
a) 500
b) 250
c) 750
d) 650

Solution

volume of given cube = 100*50*50 = 250000
required volume = 100*100*100 = 1000000
so extra volume required = 750000
so cubes required = 750000/10*10*10 = 750

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Asked In TCS Sumandeep Ghosh (14 years ago)

Solved Read Solution (4)

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(#M40000605) TCS QUESTION Keep an EYE

1! + 2! +......... + 50!=?
a)3.1035*10^64
b)2.1021*10^65
c)3.1035*10^63
d)3.1035*10^62

Solution

solve 50! + 49! + 48!
others are lower terms
this can be done by calculator only

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Asked In TCS Sumandeep Ghosh (14 years ago)

Solved SANTOSH AGRASINGH Read Solution (2)

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(#M40000602) TCS QUESTION Keep an EYE

There is a bacteria which has the probability of die 1/3 of its total number or it may tripled. Find out the probability
A. P=1/3+(2/3*p^3)
B. P=2/3+(2/3*p^3)
C. P=2/3+(1/3*p^3)
D P=2/3+(2/3*p^3)

Asked In TCS Sumandeep Ghosh (14 years ago)

Solved khushboo mishra Read Solution (10)

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(#M40000601) TCS QUESTION Keep an EYE

The bacteria has the probability of split into 3 and probability to die is 1/3rd of the total bacteria.Let the probability is P.Some of them survived with probability 1/5.Then which among the following relation is true?
a)P=1/3+1/5*3
b)P=1/5*(1/8-3)

Asked In TCS Sumandeep Ghosh (14 years ago)

Solved marudhupandian .p Read Solution (10)

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(#M40000600) TCS QUESTION Keep an EYE

A man goes north 37km.turns left goes 2km.turns right goes 17km.turns right goes 2km. find distance b/w starting ending point.
a) 54
b) 27
c) 81
d) 67

Solution

Since man moves 2 km east and 2 km west so distance between initial and final points will be (37+17)km = 54km

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Asked In TCS Sumandeep Ghosh (14 years ago)

Solved Pradeepthi Read Solution (8)

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