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(#M40002811) TCS QUESTION tcs Keep an EYE

A jogger jogs (1/6)th of his usual speed. How much % she has to increase to reach normal pace of walking

Solution

Initial speed = 1/6th
required speed = 1
so increment = 5/6th
% increment = (5/6)*100/(1/6) = 500 %

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Asked In TCS purvi (14 years ago)

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(#M40002810) TCS QUESTION tcs Keep an EYE

Age of 2 in the ratio 4:5. Total of 2 ages is 55. After 2 yrs ages are in ratio 5:7

Solution

Incomplete question
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Asked In TCS purvi (14 years ago)

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(#M40002809) TCS QUESTION tcs Keep an EYE

. 1/6th of a no is 4 times more than 2/3 of a no.find no

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(#M40002808) TCS QUESTION tcs Keep an EYE

Peter is 2times paul’s age was when peter’s age is same as paul’s present age.find pauls
age.

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(#M40002798) TCS QUESTION tcs Keep an EYE

Smita was making 1 larger cube of size 5*5*5 using smaller cubes of 1*1*1. She created solid larger cube, then she decided to make hollow
cube. Then how many 1*1*1 cubes required to make hollow larger cube

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(#M40002796) TCS QUESTION tcs Keep an EYE

Lion and rat are staying in jungle happily
Lion lies on : MON, TUE, WED
RAT lies on : WED, THURS, SAT
if Lion says : I didn't lie yesterday
Rat says : I didn't lie yesterday
so what day is today?

Asked In TCS purvi (14 years ago)

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(#M40002795) TCS QUESTION tcs Keep an EYE

((4x+3y)+(5x+9y))/(5x+5y) = ? as (x/2y) = 2
Ans: as x=2y put the value and get the answer.

Solution

((4x+3y)+(5x+9y))/(5x+5y) = (9x+12y)/(5x+5y)
given that x = 4y
so (9x+12y)/(5x+5y)= 48y/25y =48/25

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Asked In TCS purvi (14 years ago)

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(#M40002793) TCS QUESTION tcs Keep an EYE

Difference between two numbers is 4, and their product is 17. Then find the sum of their squares?

Asked In TCS purvi (14 years ago)

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(#M40002792) TCS QUESTION tcs Keep an EYE

There is a long story & within it a mathematical series present like
8 6 17 14 35 30 71 _ 143.

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(#M40002790) TCS QUESTION tcs Keep an EYE

On Tuesday college parking place have only 4 Wheeler & bicycles, total no. of wheels was 182, what is the possible no of bicycles?
a)20 b 19 c 18 d 17

Solution

for 17 bicycles remaining wheels = 182-(17*2)= 148 = 37 4wheeler
similarly for 19 bicycles remaining wheels = 182-(19*2)= 144 = 36 4wheeler
so 19 and 17 are possible answers


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