How many numbers of two digits are divisible by 5...

M4maths Previous Puzzles

18 Apr 2013 Number

How many numbers of two digits are divisible by 5...

OPtion

1) 12
2) 13
3) 14
4) 15
5) 16
6) 17
7) 18
8) 19
9) 20
10)None of these

Solution

series 10, 15 .... 90, 95
An=a+(n-1)d
n=18
option 7

Correct Option: 7 Best Solution (16)

prashant thakur   11 years AGO

a no is divisible by 5 only when its unit digit is 0
or 5..........clearly there are 19 such digits between 10 to 99....

Like? Yes (5) | No (2)  

sanjay singh   11 years AGO

FROM5*1 TO 5*19 THERE ARE 19 TERMS
THUS FROM 5*2 TO 19*5 THERE ARE 18 TERMS

Like? Yes (3) | No   

anjul meid   11 years AGO

10....95; 95=10+(n-1)*5=>n=18

Like? Yes (3) | No   

Rats   11 years AGO

Number of two digits divisible by 5
10,15,20,.....,95
l=a+(n-1)d
a=10, d=5 & l=95
95=10+(n-1)5
95=5n+5
5n=90
n=18

Like? Yes (2) | No   

kalaiarasan   11 years AGO

Total two digits(10-99) are : 90
Divisible by 5 : 90 / 5 = 18 numbers.

Like? Yes (3) | No (1)  

Dr.Dipin Singh   11 years AGO

Two digit numbers divisible by 5 are
10 (2*5), 15(3*5),... ,90(18*5),95(19*5)

so 18 numbers

Like? Yes (2) | No   

Mukesh Kr Singh   11 years AGO

10+15+......+95
so
95=10+(n-1)*5
n=19
so option 7 is coreect

Like? Yes (3) | No (1)  

Balakrishnan M   11 years AGO

Two digit number are 10 to 99.
Number of two digit numbers are 90.
Numbers of two digits are divisible by 5 = 90/5
= 18

Like? Yes (2) | No   

D.Jagruthi   11 years AGO

between 10 to 90=9
between 15 to 95=9
=> 18

Like? Yes (2) | No (1)  

Anbarasi Rodrigo   11 years AGO

Tn = a+(n-1)d
tn : last term = 95
a= 10
d= 5
95=10+(n-1)5
95= 10 + 5n-5
90 = 5n
n =18

Like? Yes (1) | No   

Gunaseelan   11 years AGO

10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95.

Like? Yes (2) | No (1)  

Darpankumar   11 years AGO

as you can see 5and 100 are not 2 digit so no from 10 to 95 are divisible by 5

Like? Yes (1) | No   

ganesh   11 years AGO

last digit are should be 5 or 0, it is x5 or x0 format.By using permutations and combinations,
x5 ,x0. x possible values 1-9.
possible total values=9, to arrange in single palce , so combination 9c1 for x5 and 9c1 for x0.
so total combinations = 9c1+9c1= 18.

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

Two digit numbers from 10 to 99, divisible by 5 are
10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90, 95 = total 18

Like? Yes (1) | No (1)  

krishnapriya   11 years AGO

two digits divisible by 5 are
10,15,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95

Like? Yes (1) | No (1)  

ravindra   11 years AGO

10,20,25,30,35,40,45,50,55,60,65,70,75,80,85,90,95
are two digits number which is divisible by 5

Like? Yes (1) | No (1)