In a single throw of two dice, what is the probability of getting a total of less than 6.

piyush jain   11 years AGO

for total less than the 6 the choices are:
(1,1);(1,2);(1,3);(1,4);(2,1);(2,2);(2,3);(3,1);(3,2);(4,1)
now there are in total 10 possibilities out of 36
hence probability=10/36=5/18

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anand s idagal   11 years AGO

Total of 36 times ... in that getting probability of total of less than is 10
..so 10/36

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Rajib Chakraborty   11 years AGO

total of less than 6 can be possible by the follwing ways :
1+1,1+2,1+3,1+4,2+1,2+2,2+3,3+1,3+2,4+1........
totally there are 10 combinations,, and Total number of possible outcomes = 6^2 = 36
now answer is : 10/36=5/18...thank you

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Sagar Jinachandran   11 years AGO

the favorable outcomes are
(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)
no: of favorable outcomes=10
total outcomes=36
probability=10/36=5/18
option 4

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Mounika Reddy   11 years AGO

sum below 6,der r 10 possibilities
(1,1) (1,2) (2,1) (1,3) (2,2) (3,1) (1,4) (2,3) (3,2) (4,1)
total psblts 6^2
probability is 10/36=5/18

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Devendra Marghade   11 years AGO

Out of the total 6x6=36 possible outcomes,
the combinations (1,1)(1,2)(1,3)(1,4)(2,1)(2,2)(2,3)(3,1)(3,2)(4,1)=10 favourable outcomes
So probability=10/36=5/18

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C.Manohar   11 years AGO

(1,1),(1,2),(1,3),(1,4)
(2,1),(2,2),(2,3)
(3,1),(3,2)
(4,1)
p=10/6^2

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django   11 years AGO

prob of 1=0
prob of 2= 1/36
prob of 3=(1/36)*2
prob of 4=3*1/36
prob of 5=4*1/36
net prob =sum of all probs 5/36

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Sri Vatsalya   11 years AGO

ans:5/18 the possible outcomes which satisfy the condition are (1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1) the total no of outcomes are 36 therefore the probability is `10/36=5/18

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ponprakash   11 years AGO

A={( 1,1 ),(1,2 ) ,(1,3 ),(1,4),(2,1 ),(2,2 ),(2,3), ( 3,1),(3,2),(4,1)
n(A)=n(n)/n(S)
10/36=5/18

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Anil Kumar Bharti   11 years AGO

Ans: 4) 5/18
Exp:
Total of less than are (1,1), (1,2),(1,3),(1,4), (2,1), (2,2), (2,3), (3,1), (3,2),(4,1) is 10
and no of dice is 2
So, 10/6^2 =10/36 =5/18

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Garima Garg   11 years AGO

Total probability 36
no of cases of total less than 6. 10
req probability= 10/36=5/18

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Suman   11 years AGO

(1,1) (1,2) (1,3) (1,4)
(2,1) (2,2) (2,3)
(3,1) (3,2)
(4,1)
n(S)=36
n(E)=10
P(E)=10/36=5/18

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snehik podder   11 years AGO

a be the event.
n(a)={(1,4);(1,3);(1,2);(1,1);(2,3);(2,2);(2,1);(3,2);(3,1),(4,1)}
=10
n(s)=36
p(a)=10/36=5/18

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Ann Mary Jolly   11 years AGO

ANS : 5/18
For getting a sum of less than 6,the no.s on the dice should be less than 5.(B'coz in case if one of the dice shows 5,then for the least no. shown on the other dice;ie, 1 the sum is 6).

So the cases arising,where one dice shows a no. within 1-4:
For 1,other dice can show the no.s 1,2,3,4.
For 2,other dice can show the no.s 1,2,3.
For 3,other dice can show the no.s 1,2.
For 4,other dice can show only the no. 1.
Counting the cases where sum

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Archita Mitra   11 years AGO

(1,1),(1,2),(1,3),(1,4)(2,1),(2,2)(2,3)(3,1)(3,2)(4,1)
10/36=5/18

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Anil kumar   11 years AGO

1-1,1-2,1-3,1-4,2-1,2-2,2-3,3-1,3-2,4-1,since there are ten ways that the total of two dice is

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saravanan   11 years AGO

possibilities are
{(1,1)(1,2)..(1,4)
(2,1)..(2,3)
(3,1)(3,2)
(4,1)}
therefore there are 10/36 probabilities

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Balakrishnan M   11 years AGO

Getting a total of less than 6 = {(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}
Number of values "Getting a total of less than 6" =10
Total number of values = 36
Probability = 10/36
= 5/18

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Harinder Singh   11 years AGO

1/36+2/36+3/36+4/36

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putsala devi vijaya   11 years AGO

total no of cases less than 6 is 10
i.e,(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)

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Udhaya kumar   11 years AGO

total prob = 6^2 = 36
less than 6 = 4 = 4+3+2+1 =10
10/36 = 5/18

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Sangeeth   11 years AGO

In two throws of a die, n(S) = (6 x 6) = 36.

Let E = event of getting less than 6 ={(1,1)(1,2)(1,3)(1,4)(2,1)(2,2)(2,3)(3,1)(3,2)(4,1)}
so E=10
p(E)=n(e)/n(s)=10/36= 5/18

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Priya Mahajan   11 years AGO

less than 6 means 1-5 i.e. 10 numbers and there are two dices each has 6 numbers on it.Therefore it becomes 6*6=36
10/36=5/18

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Sanchit Khaneja   11 years AGO

there are 12 cases in which sum is less than 6.
Cases are:- (1,1) (1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)

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Rohit   11 years AGO

Total combinations= 36
required combination = 10
(1,1)(1,2)(1,3)(1,4)(2,1)(2,2)(2,3)(3,1)(3,2)(4,1)

probability=10/36
=5/18

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shravya   11 years AGO

total number of ways is 36
number of ways to get number less than 6 is 10
so probability is 10/36=5/18

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Swarrnabanu   11 years AGO

The probability total of less than 6 is 5/18. the possible cases of values than 6 are (1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)and total pairs available is 36.Thus we get the value as 5/18.

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Dhivya   11 years AGO

The Chances are (1,1,(1,2),(1,3)(1,4) (2,1) (2,2) (2,3) (3,1) (3,2) (4,1)......so the probability will be 10/36....simplies it will get 5/18

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Jasmine Khan   11 years AGO

sum(x,y)

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Roopam Jain   11 years AGO

Total 10 possibilities :
1,1
1,2
1,3
1,4
2,1
2,2
2,3
3,1
3,2
4,1

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