A sum of Rs.1200 become Rs.1323 in 2 years at compound interest compounded annually. Find the rate o

Md Intshamuddin   11 years AGO

(1323/1200)=(1+r/100)^2
=> 441/400=(1+r/100)^2
=> 21/20=1+r/100
=> r=5%

Like? Yes (18) | No (6)  

Avinash Kumar   11 years AGO

here,
Amt=1323
p=1200
n= 2 years
Now,
(amt/p)=( 1+ r/100)^n
1323/1200 = ( 1+ r/100)^2
solving this eqn we get
r=5

Like? Yes (9) | No (1)  

Abhijeet Kumar   11 years AGO

Formula of a compound interest:
A=P(1+R)^T
1323=1200(1+r%)^2
1323=1200(1+r/100)^2
1323=1200{(100+r)/100}^2
1323=12{(100+r)^2}/100
132300/12=(100+r)^2
11025=(100+r)^2 -- taking sqrt on both side
105=100+r
r=5% Ans

Like? Yes (10) | No (2)  

Alok Kumar   11 years AGO

A = p (1+ r/100)^2
r/100 = 1.05 - 1
r = 5%

Like? Yes (6) | No (2)  

ABHISHEK KUMAR MISHRA   11 years AGO

according to question
1323=1200(1+r/100)^2
1323/1200 = (1+r/100)^2
1.05 = (1+r/100)
105-100 = r
so r = 5%

Like? Yes (5) | No (2)  

Md.Sultan Khichi   11 years AGO

Compound intrst formula is a=p(1+r/100)^n
so 1323=1200(1+r/100)^2
After solving we get r=5
Ans:5%.obtn 4.

Like? Yes (4) | No (1)  

Sourav Maity   11 years AGO

1200*5%=60 for one year.so in two years that is 120. so the ans is option 4

Like? Yes (3) | No   

k.d.n padma rao   11 years AGO

amount=principle(1+rate/100)^time period
principle=1200
amount=1323
time period=2yrs
so, rate=((1323/1200)^(1/2)-1)100=5%

Like? Yes (4) | No (1)  

nishant kumar   11 years AGO

principal=1200;amount=1323;time=2 years
let the rate be R% per annum
then,[1200(1+R/100)^2]=1323
or, (1+R/100)^2=1323/1200
=>(1+R/100)=21/20
=>R/100=1/20
=>R=5%
hence rate is 5%pa

Like? Yes (3) | No   

KUNAL GAURAV   11 years AGO

Let the rate of interest be R.
We have,
P(1+R/100)^n=A

Here in the question we have P=1200
A=1323
n=2
So R can be calculated from the above formula.

1200(1+R/100)^2=1323

On solving we get

R=5%

Like? Yes (9) | No (7)  

manasa epuru   11 years AGO

1323=1200(1+r/100)(1+r/100)
on solving we get 5..

Like? Yes (3) | No (1)  

MOVVA ROHITH   11 years AGO

ans:5%
a=p(1+r/(100*n))^(n*t)
here n=1;t=2;a=1323;p=1200
by solving r=5%

Like? Yes (2) | No   

Harleen Chadha   11 years AGO

A=P(1+(r/100))^n
1323/1200=(1+r/100)^2
r=5%

Like? Yes (3) | No (1)  

Kushal Saraf   11 years AGO

formula for compound interest is

M=P(1+i)^n
here i-rate of interest
solving we get- 5% Ans

Like? Yes (3) | No (1)  

Chandni Maurya   11 years AGO

ans=(4) 5%
P=1200Rs,A=1323Rs,n=2years,r=?
where P=principal ,A=amount/sum, n= year,r=rate
A=P(1+r/100)^n
=>1323=1200(1+r/100)^2
=>sq.rt(1.1025)= 1+r/100
=>1.05 = 1+r/100
=>r= (1.05-1)*100
=>r=5%

Like? Yes (3) | No (1)  

JITENDRA KR.BAROLIYA   11 years AGO

1323=1200(1+r/100)^2
441/400=((100+r)^2)/10000
21/20=(100+r)/100
r=5 ans

Like? Yes (2) | No   

SHIVANI PRAKASH   11 years AGO

1200(1+r/100)^2=1323/1200
r=5%

Like? Yes (3) | No (1)  

FRANKLIN VIJAY   11 years AGO

P = Rs. 1,200, A = Rs. 1,323, N = 2
1,323 = 1,200 (1+ r)2
R = 100 × 0.051 = 5.1%.

Like? Yes (2) | No   

Chandra sekhar reddy   11 years AGO

formula: compound interest sum=p(1+r/100)n
here p is intial amount
r is rate
n is no of years

substitute you will get 1200(1+r/100)^2=1320
now solve for r...
Answer is 5%
Choice is 4...

Like? Yes (2) | No   

LOGAN WOLVERINE   11 years AGO

p(1+r/100)2=1323;
(1+r/100)2=1323/1200;
1.1025;
(100+r)2=1.1025*10000;
(100+r)2=11025;
(100+r)2=105^2;
100+r=105;
r=105-100;
interest=5%
1=

Like? Yes (2) | No   

HARIHARAN S   11 years AGO

By using compound interest formulae

Like? Yes (2) | No   

ch.jyothsna   11 years AGO

P=1200 amount=1323 n=2 for calculating R we have formula amount=P(1+(R/100))^n 1323=1200(1+(R/100))^2
(1+(R/100))^2=1.1025
1+(R/100)=1.05
100+R=105
R=5
so R=5%

Like? Yes (4) | No (2)  

KARTHIGA DEVI.J   11 years AGO

c.i=p((1+r/100)^n -1)
p=1200;n=2
sub,
r=5%.

Like? Yes (2) | No   

KALIDASS   11 years AGO

Amount=P(1+(R/100))^n
1323=1200(1+(R/100))^2
R=5%

Like? Yes (2) | No   

Gokul Krishnan   11 years AGO

P=A/(1+(R/100))^n
R=5%

Like? Yes (3) | No (1)  

Madhu pericherla   11 years AGO

A=P(1+(r/100))^n

1,323=1=200(1+r/100)^2

1+(r/100)^2=(1,323/1,200)

(1+(r/100))^2=441/400

(1+(r/100))^2=(21/20)^2

(1+r/100)=21/20

(r/100)=1/20

r=5
the required rate of compound interest per annum is 5%

Like? Yes (3) | No (2)  

ritesh kumar pandey   11 years AGO

let the rate be x;
so 1323 = 1200(1+x/100)^2
so x = 5;

Like? Yes (2) | No (1)  

vigneshwari   11 years AGO

the formula to find the amount compounded annually, final amount = P[1+ R/100]^n
here, amount = Rs.1323, p = Rs.1200, n= 2 years.
Then, 1323 = 1200x[1+ R/100]^2
= 1200[100+R]^2 / 10000
(100+R)^2 = 11025
R^2 + 200R - 1025 = 0
R = 5.
required rate of interest = 5%.

Like? Yes (4) | No (3)  

Alok kumar   11 years AGO

P=1200
A=1323
N=2
LET RATE OF INTEREST IS R
WE KNOW A=P(1+R/100)^N
USING ABOVE
WE GET R=5%

Like? Yes (4) | No (3)  

rahul jha   11 years AGO

A=P(1+(r/100))^n
n=2 yr,A=1323,P=1200
1323=1200(1+(r/100))^2
1+(r/100)=.05
r=5 %

Like? Yes (5) | No (4)  

nirmal   11 years AGO

1323=1200(1+R/100)2
=>then calculate R from this formula

Like? Yes (2) | No (1)  

Mayuresh Srivastava   11 years AGO

A=P(1+(r/100))^n
Here A=1323,P=1200,n=2
thus r=5

Like? Yes (2) | No (1)  

Abhik Kumar Dey   11 years AGO

A=P(1+r/100)^n
n=2
P=1200
A=1323

on calculating we get r=5%

Like? Yes (2) | No (1)  

ashiwani kumar singh   11 years AGO

ans=4
1323=1200*(1+r/100)^2;
(1323/1200)^1/2=(1+r/100);
(21*100/20)=100+r;
105-100=r;
r=5%

Like? Yes (2) | No (1)  

Aniruddha Bhattacharjee   11 years AGO

x=1200
y=1323
x*5/100+x=1260
1260*5/100=63
NOw 1260+63=1323

Like? Yes (4) | No (3)  

Ankit Shukla   11 years AGO

1323=1200(1+(r/100))*(1+(r/100))
1323/1200=(1+(r/100))*(1+(r/100))
421/400=(1+(r/100))*(1+(r/100))
21=20=(1+(r/100))
r/100=1/20
s0 r=5%

Like? Yes (2) | No (1)  

Bingumalla Abinay   11 years AGO

A=P(1+r/n)2t

1323/1200=[1+r]^2

r=5%

Like? Yes (2) | No (1)  

Jasmine Khan   11 years AGO

A=P(1+r/100n)^nt
1323=1200(1+r/100)^2
1323/1200=(100+r/100)^2
36.37/34.64=100+r/100
r=3637/34.64-100
r=4.99%

Like? Yes (2) | No (1)  

vky   11 years AGO

1323=1200*(1+r/100)square
r=5%

Like? Yes (2) | No (1)  

ravi singh   11 years AGO

answer is 5%

A=P * (1 + R/100)^T

where A=amount
P=principle
R=rate
T=time
from question
1323=1200* (1 + R/100)^2
by solving this we get R=5

hence answer is option 4

Like? Yes (3) | No (2)  

Mariappan   11 years AGO

P=1200, A=1323, n=2yrs

A=P(1+r/100)^n

therfore, r =5%

Like? Yes (2) | No (1)  

kishor kumar   11 years AGO

amt = sum (1+r/100)^t
1323 = 1200(1+r/100)^2
or r= 5%

Like? Yes (2) | No (1)  

Naveen Jayan   11 years AGO

A=P(1+r)^t formula. Substituting the values give us 0.05 which is 5%

Like? Yes (2) | No (1)  

Balakrishnan M   11 years AGO

A=P[1+(r/100)]^n
1323=1200[1+(r/100)]^2
(1323/1200)=[1+(r/100)]^2
(441/400)=[1+(r/100)]^2
(21/20)^2=[1+(r/100)]^2
(21/20)=[1+(r/100)]
(21/20)-1=(r/100)
(1/20)=(r/100)
r=5%

Like? Yes (3) | No (2)  

Shubhankur Manuja   11 years AGO

Amount = P*(1+R/100)^2

1323 = 1200*(1+R/100)^2

1.05 = 1+R/100

R=5%

Like? Yes (2) | No (1)  

Harsh Poddar   11 years AGO

By formula
1200*(1+(r/100))^2=1323
(1+(r/100))^2=441/400
1+(r/100)=21/20
r/100=1/20
r=5
rate =5%
option 4

Like? Yes (2) | No (1)  

aman kumar tiwari   11 years AGO

1323=1200(1+(r/100))(1+(r/100))=r=5% ans

Like? Yes (1) | No   

brijesh   11 years AGO

Amount=P(1+(R/100))^N
1323=1200(1+(R/100))^2

calculating it we get R=5%

Like? Yes (1) | No   

Bhargaviinduri   11 years AGO

we know compound interest=p(1+r/100)^t

here p=sum,t=time,r=rate of interest

1323=1200(1+r/100)^2 by solving this we get
r=5%

Like? Yes (1) | No   

sanjay singh   11 years AGO

principal=1200(P)
amount=1323(A)
A=P(1+r/100)^2
1323=1200(1+r/100)^2
solving it ,r=5

Like? Yes (1) | No   

Jagadeesh Rampati   11 years AGO

Here, P = Rs. 1,200, A = Rs. 1,323, N = 2, i = ? 1,323 = 1,200 (1+ i)^2
(1+i)^2=1323/1200
(1+i)^2=1.1025
take logs on both sides
2 log(1+i)=1og 1.1025
2 log(1+i)=0.0426
log (1 + i) = 0.0213
(1 + i) = Antilog 0.0213 = 1.051
i = 0.051 and R = 100 × 0.051 = 5.1%.

Like? Yes (1) | No   

praneeth   11 years AGO

A=P(1+r/n)^nt
A=1323 rs. t=2years;n=1(compounded annually);P=1200;
1323=1200(1+r)^2
r=0.05
r(%)=0.05*100=5%

Like? Yes (1) | No   

jeevan reddy mandali   11 years AGO

323 rs increment per 2 years which means 61.5 rs per a year. so its , 1200*rate = 61.5 => 1/rate = 1200/61.5 => rate=0.05 => 5%

Like? Yes (1) | No   

MAYANK AGARWAL   11 years AGO

a=p(1+r/100)^n
given
a=1323,p=1200,n=2
we get r=5%

Like? Yes (1) | No   

richa ahuja   11 years AGO

p=1200
a=1323
n=2
a=p(1+r/100)^n
1323=1200(1+r/100)^2
r=5%

Like? Yes (1) | No   

Jayaraman Baskar   11 years AGO

amount=principal*(1+R/100)^n
R-rate of interest;n=no. of years
1323=1200*(1+R/100)^2
R=5%

Like? Yes (1) | No   

ravi chandra singh   11 years AGO

A=p(1+R/100)^n
put all values then
1323=1200(1+R/100)^2

1323/1200=(1+R/100)
1.05=1+R/100

0.05=R/100

so,R=5%

Like? Yes (1) | No   

sumanth   11 years AGO

5%+5%+((5*5)/100)=123
and 1323-1200=123

Like? Yes (1) | No   

mohini gupta   11 years AGO

A = P ( 1 + r/n )^ nt,
where,
P = principal amount (initial investment)
r = annual interest rate (as a decimal)
n = number of times the interest is compounded per year
t = number of years
A = amount after time t.
by solving, 1323=1200(1+r)^2,
r=.5*100=5%

Like? Yes (1) | No   

roushan   11 years AGO

total amount=principal value(1+r/100)^t
1323=1200(1+r/100)^2
1323/1200=(1+r/100)^2
1.05=1+r/100
.05=r/100
r=5%

Like? Yes (1) | No (1)  

Ch Kumaraswamy   11 years AGO

principal amnt p=1200,
total amnt =1323
years n=2,
let r be the rate of intrst.,
by using compound intrst annually formula

toal amnt=p*(1+r/100)^n

by solving we get r=5%.

Like? Yes (2) | No (2)  

Chithra   11 years AGO

5% compound interest from 1200 is 60+60+3=123, total 1200+123=1323

Like? Yes (2) | No (2)  

Raju Sharma   11 years AGO

bcoz
ci =p(1+R/100)^n
usig this formula we get rate of 5%

Like? Yes (1) | No (1)  

balaji ponnambalam   11 years AGO

C.I=P(1+(x/100))^n
so, ans 4%

Like? Yes (1) | No (1)