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Gokul Krishnan to kriti kankariya 4 years ago

Good Morning My sister...Can you please tell me what is sap? and for what it is used?

Reply Like? Yes (2) | No

Gokul Krishnan to JANARTHANAN RAM 4 years ago

23.1 square + 48.6 square - 39.8square =x+1147.69
by unit digit method,
in this problem 1+6-4-9 = x which is equal to x = -6 then how can it equal to x =4

Reply Like? Yes (3) | No

Gokul Krishnan to JANARTHANAN RAM 4 years ago

A can do a piece of work 4 hour, B and C can do it In 3 hour while A and C can together do it in 2 hour how long will B alone take to do it ?

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neha gupta 4 years ago

B alone will take 12 hours to do it.

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Gokul Krishnan to JANARTHANAN RAM 4 years ago

23.1 square + 48.6 square - 39.8square =x+1147.69
by unit digit method,
in this problem 1+6-4-9 = x which is equal to x = -6 then how can it equal to x =4

Reply Like? Yes (1) | No

Gokul Krishnan to JANARTHANAN RAM 4 years ago

How the unit digit of (137^13)^47 is 3 ?
Brother,I am so puzzled,Please help me without fail...
I am getting the answer of 1....Please help me.I am waiting for your reply...

Reply Like? Yes (1) | No

Saurabh Chaudhary 4 years ago

137^13 can be written as 7^13,cyclicity of 7 is 4,divide 13 by 4 you get remainder 1 therefore 7^1.Now solve for 7^47 again divide by 4 you get remainder 3,now 7^3=343,hence unit digit is 3.

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SunNy Yadav 4 years ago

Unit digit 3 hi hoga ...
As we know
{(137)^13}^47 = (137)^611

Now according to rule.. Kyunki Base ka unit 7 hai datsy ...
1) 611 - 1 =610
2) 610Ã·4 = remainder ayega 2
3) 2+1 = 3
Now Base ke unit ki power 3 ko bana do aur jo unit aye result me wahi hoga ..
As 7^3 = 7×7×7 = 343
Unit = 3

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SunNy Yadav 4 years ago

Rule =

Agar Base me unit 0, 1, 5, 6 ho to use solve karne par unit bhi 0, 1, 5 ya 6 hi hoga ...

But agar base ke unit me 2, 3,4,7,8,9 ho to..
Power me pehle 1 minus karo
Fir use 4 se divide karo
Jo remainder aye usme 1 plus karo
Then base ki unit me woh power rakh do..
Jo result me unit ayega wahi hoga ..

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Gokul Krishnan to JANARTHANAN RAM 4 years ago

The difference between the compound interest and the simple interest accrued on an amount of Rs. 18,000 in 2 years was Rs. 405. What was the rate of interest p.c.p.a?

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Gokul Krishnan 4 years ago

The difference between the compound interest and the simple interest accrued on an amount of Rs. 18,000 in 2 years was Rs. 405. What was the rate of interest p.c.p.a?

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JANARTHANAN RAM 4 years ago

Ans: 15%

The difference b/w the compound interest and the simple interest over 2 years=P*(r/100)^2
P*(r/100)^2=405;
18000(r/100)^2=405;
r^2=405*10000/18000=225
r=15 %

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Gokul Krishnan to JANARTHANAN RAM 4 years ago

Brother when the series is squared,then we use the formulae
(n(n+1)(2n+1))/6, how you changed the formulae...help me, still I am very much confused....

Reply Like? Yes (1) | No

JANARTHANAN RAM 4 years ago

Hi bro,
1^2 + 3^2 +5^2 +.....,n term =(n/3)*(2n+1)*(2n-1)------(1)
2^2 + 4^2 +6^2 +.....,n term =(2n/3)*(n+1)*(2n+1)------(2)
For even,
(1^2 - 2^2 +3^2 -4^2+......n term)= (1^2 + 3^2 +5^2 +...n/2 term) - (2^2 + 4^2 +6^2 +.....,n/2 term)
Using (1) & (2)
(1^2 - 2^2 +3^2 -4^2+......n term)= -n*(n+1)/2
For Odd,
(1^2 - 2^2 +3^2 -4^2+......n term)= (1^2 + 3^2 +5^2 +...(n+1)/2 term) - (2^2 + 4^2 +6^2 +.....,(n-1)/2 term)
Using (1) & (2)
(1^2 - 2^2 +3^2 -4^2+......n term)= n*(n+1)/2

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Gokul Krishnan 4 years ago

The difference between the compound interest and the simple interest accrued on an amount of Rs. 18,000 in 2 years was Rs. 405. What was the rate of interest p.c.p.a?
can you help me to solve in the easiest way?

Like? Yes (1) | No

Gokul Krishnan to Pargat Pal Singh 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (2) | No

Gokul Krishnan to Rats 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (2) | No

Gokul Krishnan to Karthik Pandiyan 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (1) | No

Gokul Krishnan to C.T.Narayanan 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (1) | No

Gokul Krishnan to MOJUMDER 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (1) | No (1)

MOJUMDER 4 years ago

(40*41*81)/6 - 2*2^2[(20*21*41)/6] = -820. Think.

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Gokul Krishnan to RAKESH 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (1) | No

RAKESH 4 years ago

(1^2-2^2)+(3^2-4^2)+(5^2-6^2)... +(39^2-40^2)
a^2-b^2=(a+b)(a-b)
= - [1+2+3+4+5+6+---------+ 39+40]
= -20*41
= -820

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Gokul Krishnan to susmit 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (1) | No (1)

Gokul Krishnan to ~Sandeep~ 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (3) | No (1)

Gokul Krishnan to Dr.Dipin Singh 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (3) | No

Gokul Krishnan to JANARTHANAN RAM 4 years ago

Brother could you please find the answer of this question find the sum of first 40 terms of series 1^2-2^2+3^2-4^2+...

Reply Like? Yes (1) | No

JANARTHANAN RAM 4 years ago

Hi Bro,
Sum of 1^2-2^2+3^2-4^2+...+n^2= - (n/2)*(n+1) (If n is even)
So Sum= - (40/2)(40+1)= -820

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Gokul Krishnan 4 years ago

Thanks My Brother...What about when the N is odd condition (ie) what is the formulae?

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JANARTHANAN RAM 4 years ago

Sum of 1^2-2^2+3^2-4^2+...+n^2= - (n/2)*(n+1) (If n is even)
Sum of 1^2-2^2+3^2-4^2+...+n^2= (n/2)*(n+1) (If n is Odd)

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veeraiah 6 years ago

hai..............

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ER. Gokul
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Gokul krishnan (M)

Total Points 1445
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M4 Score

Score from best 50 Questions

Attempted 50
Date Points

14 Jun 16 16
29 Jun 16 17
07 Jul 16 16
08 Jul 16 15
11 Jul 16 15
12 Jul 16 16
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02 Aug 17 15
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Total 780
M4 Score780 / 10 = 78

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