What will be the difference of the amounts in the two types of saving given below 1) 20 rupee per d

Rahul Gupta   11 years AGO

20*100=2000
sum of AP = n/2(2a+(n-1)d)
here, a=25, n=100, d=25
sum=126250
this is in paisa now we have convert in rupee. i.e. sum/100.
126250/100=1262.50
Difference = 2000 - 1262.50 = 737.50
3)737.5 Right Answer

Like? Yes (10) | No (1)  

Md.Sultan Khichi   11 years AGO

20 rupee per day upto 100 days
so amount=20*100=rs.2000.
In second case the money are in AP
so 25+50+75.....
100/2(2*25+(100-1)25)
=126250
RS=126250/100=1262.50
different=2000-63125
=737.5
Ans:3

Like? Yes (3) | No   

hitesh kumar gupta   11 years AGO

first saving upto hundred days will be = 2000 rupees
now next statement contains series
25+50+75+...................upto 100 terms

now 100th terms will be
2500
so sum of this is =1262.5 rupee
the difference is = 737.5
which is 3rd option in given options.

Like? Yes (2) | No   

Lavankumar Reddy   11 years AGO

20 rupee per day 100 days total saving = 2000
25 paisa then 50 paisa then 75 paisa then so on upto 100 days total saving = n(a1 + n(a1))/2= 100(0.25+100(0.25))/2= 2525/2= 1262.5
Then Difference = 2000-1262.5 = 737.5

Like? Yes (2) | No   

dev kumar   11 years AGO

20*100-25*(1+2+.....+100)/100

Like? Yes (2) | No   

a.k.gayathridevi   11 years AGO

1)20*100=2000.00
2).25+.50+.75+1.00+1.25+.... =0.25(1+2+3+4+....+100)
=.25(5050)=1262.50
diff=2000.00-1262.50=737.50

Like? Yes (2) | No   

Saket chhitij   11 years AGO

for First case total=20*100=2000

for 2nd case , terms are in arithmetic progression , therefore sum of n terms in a.p. =n/2*(2a+(n-1)*d)..
which gives the value 1262.5 ... the difference of this 2 value = 737.50

Like? Yes (2) | No   

Rats   11 years AGO

(1)Rs20 for 100days = Rs2000
(2)0.25+0.50+0.75+......upto 100days
Sum=(100/2)(0.50+99*0.25)
=1262.50
Difference=2000-1262.50=737.50.....Ans

Like? Yes (1) | No   

Manish Kumar   11 years AGO

1st saving, 20*100= Rs2000
2nd saving, 100/2[2*25+(100-1)*25]= 126250 paisa =Rs1262.50
so, the difference of the amounts in the two types of saving are Rs(2000-1262.5)= Rs737.50

so option 3 is correct

Like? Yes (1) | No   

SHAIK SADDAM HUSSAIN   11 years AGO

(20*100)-(25+50+75+........+2500)/100=737.50

Like? Yes (1) | No   

Harjit kaur   11 years AGO

1) 20*100=2000
2)series is 25+50+75+...............
N=100
Sn=n/2(2a+(n-1)d)
Here a=25,d=25,n=100
By solving
We get saving =1262.50
So diff is2000-1262.50=737.50

Like? Yes (1) | No   

ArunKumar   11 years AGO

1) 20 *100 = 2000
2) 25 + 50 + 75 + . . . (100 days)
25 ( 1+2+3+ .... ) 100 days
25 * 100 * (100+1)/2
1262.50
diff = 2000-1262.50 = 737.50

Like? Yes (1) | No   

Rajeswar guin   11 years AGO

20*100=2000=a
100/2[2*25+99*.25]=1262.5=b
a-b=737.5

Like? Yes (1) | No   

KD   11 years AGO

Case 1:
20+20+....100th=20*100=2000 rs.

Case 2:
25+50+75+....+100 th term
a=25
d=25
n=100
so nth term is=25+99*25=2500
sum=100/2(25+2500)=2525*50 paise
i.e 1262.5 rs
so difference is 737.50

Like? Yes (1) | No   

kakali sarkar   11 years AGO

in 1st case the no total savings of 100 days will be (100*20)=2000.
in 2nd case total savings will be using A.P
=((100/2)*(2*25+(100-1)*25))=1262.5
so the diff will be=2000-1262.5=737.5

Like? Yes (1) | No   

achyuth   11 years AGO

1) 20 rupee per day upto 100 days the amount will be=20*100=2000
2) 25,50,75,...it is in arithmetic progression so
sum=n/2(2a+(n-1)d)
s=126250 paisa
convert into rupee
s=126250/100
s=1262.5
difference=2000-1262.5
diff=737.50

Like? Yes (1) | No   

ChinnaChowdaiah   11 years AGO

20 per day upto 100 days so total amount will be 2000.

25,50,75.......up to 100th day
will be arithmetic progression
so it will be
100/2(2*25 + (100-1) *25)
126250 paise
now convert this into rupees.
1262.50/-
so difference is 2000-1262.50 will be 737.50.

Like? Yes (1) | No   

GAYATHRI   11 years AGO

20+20+.....= 2000(for 100 days)
.25+.5+.75+.....= 1262.5
2000-1262.5 = 737.5

Like? Yes (1) | No   

sravani   11 years AGO

20*100=2000rs
25ps(1+2+...+100)=100*101/2 * 25ps=(100*101)/8rs=1262.5.
diff=737.50rs..

Like? Yes (1) | No   

Rajan   11 years AGO

Ans 3. in first case the saving will be 20*100=2000 and as the second case is in arithmetic progression the saving will be n(a1+an)/2 i.e 100(.25+25)/2=1262.5. so the difference is 737.50

Like? Yes (1) | No   

Rituraj Singh   11 years AGO

amount of first case= 20*100=2000
and in second case, its a A.P.
So last term will be= F.T.+ D(n-1)=> 25 + 25(100-1)=2500
Sum of A.P. is =n/2(F.T.+L.T.)=100/2(25+2500)=126250 i.e. 1262.50 rupees
So difference is =2000-1262.50=737.50

Like? Yes (1) | No   

sanjay   11 years AGO

if we save 20 Rs per day, we save 2000 rs for 100 days and if we save .25 ps per day for 100 days it would be 1262.5.

Like? Yes (1) | No   

PINKY   11 years AGO

first saving ->20*100= rs 2000
second saving -> 25p,50p,75p...upto 100 terms
sum upto 100 terms= 100/2(2*25+(100-1)25)=126250p
RS 126250/100

dif is 737.50

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

Amount after 100 days @20/day=20*100=2000
Amount with increase of 25 paise or 0.25 Rs/day upto 100 days=100/2[2*0.25+ 99*0.25]=1262.5
So difference=2000-1262.5=737.50 Rs.

Like? Yes (1) | No   

b.s.venkatesh   11 years AGO

1)100*20=2000
2)sn=n/2(a+l)
100/2(2525)
=2000-1262.50
=737.50

Like? Yes (1) | No   

Deepak Bharadwaj   11 years AGO

1st case saving = 20x100= rs 2000
second case total saving can be calculated by
25p+50p+75p+....upto 100 terms, which is an A.P
sum= n/2(2a+(n-1)d)=100/2(2x50+(100-1)x25)
=126250p = Rs.1262.50
difference= 2000-1262.50= Rs. 737.50 (3rd option)

Like? Yes (1) | No   

Ann Mary Jolly   11 years AGO

ANS: 3)737.50
An= 20
total amt saved in 1st case = 20*100 = 2000 ....(1)
Bn = 25n (in paisa)
total amt saved in 2nd case = B1+B2+....B100 (in paisa)
= (25*1)+(25*2)+...(25*100)
= 25*(1+2+3+.....100)
= 25*(100*101/2)
= 25*5050
= 126250
= 126250/100 Rs
= 1262.5 ....(2)
(2) - (1) gives, 2000-1262.50 = 737.50 Rs

Like? Yes (1) | No   

VISHAKHA BHATTACHARJEE   11 years AGO

20*100=2000 saving upto 100 days
next will be an AP series with d=25 and 1st term 25 and we go on increasing to 100 terms. sum of an ap series=(2a+(n-1)d)n/2=1262.50
hence diff=737.50

Like? Yes (1) | No   

prem singh   11 years AGO

20 rupees per day upto 100 day
=20*100=2000
25,50,75,..n
sum of AP =n/2[2a+(n-1)d)
so here n=100, a=25,d=25
sum of 100 terms=100/2[2*25+99*25)
=12625
now in rupees=12625/100=1262.50
difference=2000-1262.50
=737.50

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

total savings by 1=20*100=2000
total savings by 2
=100/2[2*0.25+0.25*99]=1262.5........(by A.P)
difference=737.50

Like? Yes (1) | No   

sreetej   11 years AGO

in case1 the savings are 20*100=2000
in case2 the savings are 0.25+0.5+0.75+1+......
it is in a.p with difference 0.25 .
therefore the sum of 100 terms = 1262.5
so answer is 2000-1262.50=737.50

Like? Yes (1) | No   

Jyothi   11 years AGO

20*100=2000
s=n/2(2a+(n-1)d)
a=0.25
d=0.25
n=100
s=1262.5
difference=2000-1262.5=737.5

Like? Yes (1) | No   

Saurabh Keshri   11 years AGO

case 1- saving= rs 20*100

case 2- saving =25+50+75+100....100 terms
=25(1+2+3+....+100)
=25*100*101/2
=126250 p = rs 1262.5
difference= 2000-1262.5= 737.5

Like? Yes (1) | No   

Aakash Kumar   11 years AGO

20*100-1262.50

Like? Yes (1) | No   

ALISHA AHAMAD   11 years AGO

20*100=2000
.25+(.25+.25)+(.25+2*.25)+.....+(.25+99*.25).
sum = 100/2(2*.25+99(.25))=1262.50
2000-1262.50= 737.50

Like? Yes (1) | No   

mirtunjay verma   11 years AGO

20Rs per day then for 100 day it will
20*100=2000
and 25,50,75,...till 100 term we use sum of n number formula,so for that we take 25 common out this series so it will convert in new series
25(1+2+3.....+100)
so sum will
25*50*101=126250 paise..we convert it into Rs.then it will 1262.50Rs
so therefore diff is 2000.00-1262.50=737.50 Rs.
:)

Like? Yes (1) | No   

batsal   11 years AGO

1. 20*100=2000
2. it is based on AP
S= n/2(2a+(n-1)d)
here n=100 d=0.25 a=0.25
so, S= 1262.5
difference is 2000-1262.5=737.5

Like? Yes (1) | No   

NIDHI   11 years AGO

1. 20*100=2000
2. it is based on AP
S= n/2(2a=(n-1)d)
here n=100 d=0.25 a=0.25
so, S= 1262.5
difference is 2000-1262.5=737.5
S= n/2(2a+(n-1)d)

Like? Yes (1) | No   

HARI om kashyap   11 years AGO

20*100=2000
next saving is in arithmetic progression where first term is 25
common difference 25
number of terms is 100
then Sn= 100/2[2*25+(100-1)*25]
=1262.5
so differenc is 2000-1262.5=737.5

Like? Yes (1) | No   

moumita majee   11 years AGO

20*100=2000
next saving is in arithmetic progression where first term is 25
common difference 25
number of terms is 100
then Sn= 100/2[2*25+(100-1)*25]
=1262.5
so differenc is 2000-1262.5=737.5

Like? Yes (1) | No   

neeru   11 years AGO

first is a direct multiplication while second is an ap..

Like? Yes (1) | No   

SHIVANI PRAKASH   11 years AGO

20*100- [100/2(2*0.25+99*0.25)]
=737.50

Like? Yes (1) | No   

Preetika Karnal   11 years AGO

1) Rs 20*100 =Rs 2000
2) Rs 100/2*(25 + 25+(100-1)*25)/100 =Rs 1262.50

1) - 2) =737.50

Like? Yes (1) | No   

Grishma Shah   11 years AGO

In case-1:
20 rupee for 100 days = 2000 rs at 100th day.
In case-2:
25 paisa increment every day forms a.p.
Here, a=0.25; d=0.25; n=100
Sn= n/2(2a + (n-1)d)
at 100th day sum= 50*25.25=1262.5

Hence, diffence of case 1 and case 2 is 737.5/- rupee

Like? Yes (1) | No   

pranayee karmakar   11 years AGO

as 20*10=2000-[1/100{100/2(2*50+99*25)}]=737.5

Like? Yes (1) | No   

Praveen   11 years AGO

let x denotes 25 paisa
then,
case i: 20 rupee= 0.25 x 4 x 20= 80x
in case ii:

x+2x+3x...100x ==>Arithmetic Progression==>5050x
==>5050 x 0.25
==>1262.5
diffenece = 2000-1262.5
==>737.5

Like? Yes (1) | No   

vikash kumar   11 years AGO

tn=25+25(100-1)=2500paisa

100*(25+2500)
---------------=2525*50=1262.50Rs
2

Rs 2000-1262.50

Like? Yes (1) | No   

Abhideep Saha   11 years AGO

20*100=2000. 25*!00(100+1)/2=126250 paise. 1262.50 rs. 2000.00-1262.50=737.50 rs.

Like? Yes (1) | No   

ankita   11 years AGO

1. 20*100=2000
2. a=25,n=100,d=50-25
(n/2)(2a+(n-1)d)=1262.5
ans=737.5

Like? Yes (1) | No