Solve: 10+[15-{6/(4-2)}*27] = -112 +(?)

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28 Nov 2013 Maths Calculation Solve: 10+[15-{6/(4-2)}*27] = -112 +(?): OPtion
1) 28
2) 36
3) 38
4) 42
5) 46
6) 51
7) 54
8) 56
9) 57
10)None of these; Correct Option: 8 Best Solution (57)

R.RAVIKUMAR 11 years AGO

According to BODMAS rule:
10+(15-{6/2}*27)=-112+x
10+(15-81)=-112+x
10-66=-112+x
-56=-112+x
x=112-56
x=56

Like? Yes (8) | No (3)

Ratna chandini chilakapati 11 years AGO

By using BODMAS rule.
L.H.S=10+[15-{6/2}*27]
=10+[15-3*27]
=10+[15-81]
=10+[-66]
=-56.
R.H.S=-112+56
=-56
So answer is option 8

Like? Yes (5) | No

FAISAL RIZWAN 11 years AGO

10+[15-{6/(4-2)}*27]=-112+(?)
Apply BODMAS RULE =-112+(?)
10+[15-{6/2}*27]=-112+(?)
10+[15-3*27]=-112+(?)
10+[15-81]=-112+(?)
10-66=-112+(?)
-56+112=56
So option 8 is correct

Like? Yes (4) | No

Udhaya kumar 11 years AGO

Let unknown number as x
10+[15-(3*27)]= -112+ x
10+[15-81]= -112+x
10-66= -112+x
x= -56+112
x=56.............

Like? Yes (4) | No (1)

Sakshi 11 years AGO

10+[15-{6/(2)}*27] = -112 +(?)
10+[15-{3}*27] = -112 +(?)
10+[15-81] = -112 +(?)
10+15-81=-112+(?)
-56+112=(?)
56

Like? Yes (3) | No

Grishma Shah 11 years AGO

10+[15-{6/(4-2)}*27]
= 10 + [15 - {6/2}*27 ]
= 10 + [15 - 3*27 ]
= 10 + [15 - 81]
= 10 + -66]
= -56
= -112 + 56

So answer is 56

Like? Yes (3) | No

Keshav Kishlay 11 years AGO

10+[15-{6/(4-2)}*27]=-112+x
or,10+[15-3*27]=-112+x
or,10+[15-81]=-112+x
or,10-66=-112+x
or,-56=-112+x
so,x=112-56=56

Like? Yes (2) | No

kumar sundram 11 years AGO

a/c to BODMAS-
10+[15-{6/(4-2)}*27]
=10+[15-{6/2}*27]
=10+[15-3*27]
=10+[15-81]
=10+(-66)
=10-66
=-56
=-56-56+56
=-112+56
thus, ? is replaced by 56.

Like? Yes (2) | No

Harshit Daga 11 years AGO

The result of left side is -56.
Therefore,
-56=-112+X
which means
X=56

Like? Yes (2) | No

susmit 11 years AGO

4-2=2
6/2=3
27*3=81
15-61=-66
10-66=-56
now -56=-112+x
so x=-56+112=56
option no.(8)

Like? Yes (1) | No

b.s.venkatesh 11 years AGO

-56+112
56

Like? Yes (1) | No

Rashmi bharti 11 years AGO

10+[15-{6/(4-2)}*27] = -112 +(?)
10+[15-{6/2}*27]+112=X
=>10+[15-81]+112
=>10-66+112
=>56

Like? Yes (1) | No

Ankit Goyal 11 years AGO

Apply BODMAS rule

Like? Yes (1) | No

Sushil Singh 11 years AGO

by solving 10+[15-{6/94-20}*27] we get=-56
also -112+56=-56
so 56(ans)

Like? Yes (1) | No

Anantharaman 11 years AGO

10+[15-{6/(4-2)}*27] = -112 +(?)

Taking LHS
10+[15-{6/2}*27]

10+[15-3*27]

10+[15-81]

10+[-66]

-56 = -112+56

56 (Option 8)

Like? Yes (1) | No

KRISHNAN 11 years AGO

By applying BODMAS rule on Left side of the equation
WE get
10+[15-{6/(4-2)}*27]
10+[15-{6/2}*27]
10+[15-3*27]
10+[15-81] or 10-66 or -56
Therefore -56 = -112+56
SO option 8 is correct answer +56

Like? Yes (1) | No

MADHU KUMARI 11 years AGO

10+[15-{6/(4-2)}*27] = -112 +(?)
10+[15-{6/(2)}*27] = -112 +(?)
10+[15-3*27] = -112 +(?)
10+[15-81] = -112 +(?)
10-66 = -112 +(?)
-56=-112+(?)
112-56=(?)
(?)=56

Like? Yes (1) | No

krishn kumar gupta 11 years AGO

10+[15-{6/2}*27]=-112+?
10+[15-3*27]+112=?
10+[15-81]+112=?
10-66+112=?
?=56 Ans.

Like? Yes (1) | No

hemant kumar 11 years AGO

Lets this is x
10+[15-{6/2}*27] = -112 + x
10+[15-3*27] = -112 + x
10+[15-81] = -112 + x
10 - 66 = -112 +x
-56 = -112 +x
-56 + 112 = x
56 = x
hence option 5 is correct

Like? Yes (1) | No

arun prakash singh 11 years AGO

10+[15-{3}*27]=-112+(?)
10+[15-81]=-112+(?)
10+[-66]=-112+(?)
(?)=112-56=56

Like? Yes (1) | No

Gundavarapu Parameswari 11 years AGO

bodmas princple

Like? Yes (1) | No

Nitin rahtor 11 years AGO

firstly solve (6/(4-2)) =3
then 3*27=81 then 15-81=-66 then -66+10 =-56
then -112+56=-56

Like? Yes (1) | No

thangaselvi 11 years AGO

calculate based on bodmas condition

Like? Yes (1) | No

Devendra Marghade 11 years AGO

10+[15-{6/(4-2)}*27]
=10+[15-{3*27}]
=10+(15-81)
=-66=-112+x, x=56

Like? Yes (1) | No

krishnapriya 11 years AGO

given 10+[15-{6/(4-2)}*27]=-112+x
(ie) 10+[15-81]=-112+x
-56=-112+x
x=112-56=56

Like? Yes (1) | No

Lavankumar Reddy 11 years AGO

10+[15-{6/(4-2)}*27]= -112+a
10+[15-{6/2}*27] = -112+a
10+[15-{3}*27] = -112+a
10+[15-81] = -112+a
-56 = -112+a
a=112-56
a=56

Like? Yes (1) | No

Dhanisha veligatla 11 years AGO

given can be solved through BODMAS rule
B=brackets
O=of
D=division
M=multiplication
A=addition
S=subtraction
hence, 10+[15-{6/2)}*27]
=>10+[15-3*27]
=> 10+[15-81]
=> 10-66
=-56
==-112+x=-56
therefore (?)=56

Like? Yes (1) | No

vishal barun 11 years AGO

follwing the 'BODMAS' RULE , we get

10+[15-{6/(4-2)}*27]= 10 + [15-{6/2}*27]
=10 + [15-3*27] = 10 + [-66]
= -56 = -56 -56 +56 (can be written)
=-112 + 56
ans= 56 (option 8)

Like? Yes (1) | No

saurabh tripathi 11 years AGO

ans is -56
-112 +56 = -56

Like? Yes (1) | No

Abirudh reddy 11 years AGO

10+[15-{6/(4-2)}*27]=-112+?
10+[15-{6/2}*27=-112+?
10+[15-(3*27) =-112+?
10+[15-81]=-112+?
10+[-66]=-112+?
-56=-112+?
-56=-112+56 [?=56]
-56=-56

Like? Yes (1) | No

sharath 11 years AGO

according to BODMAS(brackets of division multiplication addition and substation) Rules..

{6/(4-2)}=3
10+[15-3*27]=-112+?
10-66=-112+?
-56=-112+?
so
?=-56

answer is 8

Like? Yes (1) | No

siddagalla bhaskar 11 years AGO

according to BODMAS rule first I solve in the bracket once and then muitiplication in brackets and then substraction. finally addition which is not in the brackets. that is equal to -112+x=-56 i.e x=56

Like? Yes (1) | No

lokesh goud 11 years AGO

10+[15-{6/(4-2)}*27] = -112 +(?)
10+[15-{6/2}*27]=-112+(?)
10+[15-3*27]=-112+(?)
10+[15-81]=-112+(?)
10+[-66]=-112+(?)
-56=-112+(?)
-56+112=(?)
56=?

Like? Yes (1) | No

Gopal 11 years AGO

10+[15-{6/2}*27]
=10+[15-{3}*27]
=10+[15-81]
=10-66
=-56
=-112+56

Like? Yes (1) | No

IFFAT IRAM 11 years AGO

10+[15-{6/(4-2)}*27]=-112+x
10+[15-{6/2}*27]=-112+x
10+[15-3*27]=-112+x
10+[15-81]=-112+x
10-66=-112+x
-56=-112+x
x=56

Like? Yes (2) | No (1)

sandy 11 years AGO

=10+(15-((6/2)*27))
=10+(15-(3*27))
=10-66
=-56
-112+x=-56
x=56

Like? Yes (1) | No

Ayush Rastogi 11 years AGO

10+[15-{6/(4-2)}*27]=-112+x
10+[15-{6/2}*27]=112+x
10+[15-81]=-112+x
25-81+112=x
x=56 ans...

Like? Yes (1) | No

ARJYA HALDER 11 years AGO

Let, the required ans be x.
So,
10+[15-{6/2}*27]=-112+x
or, 10+[15-81]=-112+x
or, x=25-81+112=56
So, option 8 is right.

Like? Yes (1) | No

achyuth 11 years AGO

rule of bodmas
10+[15-{6/(4-2)}*27]=-112+(?)
10+[15-81]=-112+(?)
-56=-112+(?)
ans=56

Like? Yes (1) | No

ChinnaChowdaiah 11 years AGO

4-2=2
6/2=3
27*3=81
15-81=-66
10+[-66]=-56
-56=-112+?
?=112-56
?=56

Like? Yes (1) | No

Chithra 11 years AGO

10+(15-3*27)=-112+x
10+(15-81)+112=x
10-66+112=x
x=56

Like? Yes (1) | No

mirtunjay verma 11 years AGO

soling equation by bomus rule we get 56

Like? Yes (1) | No

palagatisriharshithareddy 11 years AGO

10+(15-(6/(4-2))*27)=-112+x
-56=-112+x
x=56

Like? Yes (1) | No

a.k.gayathridevi 11 years AGO

10+[15-3*27]+112=x
122+[15-81]=x
x=122-66=56

Like? Yes (1) | No

ROHIT UPADHYAY 11 years AGO

10-66=-112+56

Like? Yes (1) | No

Abinaya sekar 11 years AGO

*(),{},[]
*BODMAS
Bracket Of Division Multiplication Addition Subtraction

Like? Yes (1) | No

vijaydurga rao 11 years AGO

-56=-112+(?)
-56=-112+56
-56+56=0

Like? Yes (1) | No

julee verma 11 years AGO

according to the BODMAS rule firstly solve the brackets, solution will be-
10+[15-{6/(2)}*27]=-112+x
10+[15-{3}*27]=-112+x
10+[15-81]=-112+x
10+[-66]=-112+x
10-66=-112+x
112-56=x
x=56
hence correct answer will be 56

Like? Yes (1) | No

lovely verma 11 years AGO

let unknown value is x so,
10+[15-{6/(4-2)}*27]=-112+x
10+[15-{6/2}*27]=-112+x
10+[15-81]=-112+x
10+[-66]=-112+x
10-66=-112+x
-56+112=x
x=56
so answer=56

Like? Yes (1) | No

AMIT JAISWAL 11 years AGO

let unknown value=x, so solution will be-
10+[15-{6/(2)}*27]=-112+x
10+[15-{3}*27]=-112+x
10+[15-81]=-112+x
10+[-66]=-112+x
10-66=-112+x
x=-66+112=56
hence answer will be 56

Like? Yes (1) | No

Abhishek Singh 11 years AGO