If x/y = 3/2 Then, (x^2+y^2+2xy)/(x^2+y^2-2xy) = ?

FAISAL RIZWAN   11 years AGO

(x^2+y^2+2xy)/(x^2+y^2-2xy)
Can be written as
(x+y)^2/(x-y)^2.....(1)
Given x/y=3/2
then x=3y/2
put the value of x in equation 1
((3y/2)+y))^2/((3y/2)-y)^2
After solving we get 25
so option 8 is correct

Like? Yes (8) | No (1)  

Ashfaque Hussain   11 years AGO

x/y = 3/2
=>x=3y/2
Given expression to evaluate:
(x^2+y^2+2xy)/(x^2+y^2-2xy) = ((x+y)^2)/((x-y)^2)
=(3y/2+y)^2/(3y/2-y)^2 = ((5y/2)^2)/((y/2)^2)
=25

Like? Yes (6) | No (3)  

amit bhagat   11 years AGO

Since, it is been given that x/y = 3/2
therfore we have x=3y/2.
now putting this value of x in -
(x^2+y^2+2xy)/(x^2+y^2-2xy) = (x+y)^2/(x-y)^2)
= (3y/2+y)^2/(3y/2_y)^2
= (5y/2)^2/(y/2)^2
= (25y^2/4)/(y^2/4)
= 25

Like? Yes (3) | No   

Harsh Poddar   11 years AGO

x/y=3/2
x=(3/2)y
(x^2+y^2+2xy)/(x^2+y^2-2xy)
=(x+y)^2/(x-y)^2
=((3/2)y+y)^2/((3/2)y-y)^2
=(5y/2)^2/(y/2)^2
=(25y^2/4)/(y^2/4)
=25
option 8

Like? Yes (2) | No   

ChinnaChowdaiah   11 years AGO

x/y= 3/2
so,
x=3
y=2
put this values in the given expression so we get
(9+4+12)/(9+4-12) =25

Like? Yes (2) | No   

Akash Agrawal   11 years AGO

we rewrite the given equation as(x+y)^2/(x-y)^2
again((x/y+1)/(x/y-1))^2 put the x/y value ans=25.

Like? Yes (2) | No   

RAKESH   11 years AGO

(x^2+y^2+2xy)/(x^2+y^2-2xy) =(x+y)^2/(x-y)^2
=(x/y +1)^2/(x/y -1)^2
=(3/2 +1)^2/(3/2-1)^2
=25/4 *4 =25

Like? Yes (1) | No   

Mahesh   11 years AGO

Let x = 3k and y = 2k

The given expression can be written as (x + y)^ 2/(x-y)^2 = (5k)^2/(k)^2= 25 k^2/k^2= 25

Like? Yes (1) | No   

Raisul Alam   11 years AGO

Here (x/y)=(3/2)
so 2x=3y
and x=(3*y/2)
Now (x^2+y^2+2xy)/(x^2+y^2-2xy)
=(x+y)^2/(x-y)^2
puttting the value of 'x' in terms of 'y' we get
((3*y/2)+y)^2/((3*y/2)-y)^2
=(5*y/2)^2/(y/2)^2
=(25*y^2/4)/(y^2/4)
=25 . Hence option 8 is the right answer.

Like? Yes (2) | No (1)  

achyuth   11 years AGO

if x/y=3/2 so x=3 ,y=2
(x^2+y^2+2xy)/(x^2+y^2-2xy)
(3^2+2^2+2*3*2)/(3^2+2^2-2*3*2)
25/1
ans=25

Like? Yes (2) | No (1)  

Udhaya kumar   11 years AGO

from given x=3y/2
(x+y)^2/(x-y)^2=25/4*4=25..............

Like? Yes (2) | No (1)  

Dipika Singh   11 years AGO

we can write the eq. in simplifed form as =((x+y)^2)/((x-y)^2)
=(((x/y)+1)^2)/(((x/y)-1)^2)
=((3/2+1)^2)/((3/2-1)^2)
=25
answer is => option 8.

Like? Yes (1) | No   

Pooja P   11 years AGO

given that x/y=3/2
so,(x/y)+1=(x+y)/y=(3/2)+1=5/2..............(1)
again,(x/y)-1=(x-y)/y=(3/2)-1=1/2.............(2)
dividing eq(1)by eq(2)we get
(x+y)/(x-y)=(5/2)*2=5
so{(x+y)/(x-y)}^2=5^2=25
ans.(8)

Like? Yes (1) | No   

Rajasekhar Reddy   11 years AGO

(x+y)^2/(x-y)^2 = (x/y+1)^2/(x/y-1)^2
= (25/4)/(1/4) = 25

Like? Yes (2) | No (1)  

Prakash kumar   11 years AGO

(x+y)^2/(x-y)^2 = [(x/y) + 1]^2 / [(x/y) - 1]^2
= (5/2)^2/(1/2)^2
= 25 ans

Like? Yes (1) | No   

Devendra Marghade   11 years AGO

(x^2+y^2+2xy)/(x^2+y^2-2xy)=(x+y)^2/(x-y)^2
=(x+y)(x+y)/(x-y)(x-y)
=y[(x/y)+1]x[(1+(y/x)]/y[(x/y)-1]x[1-(y/x)]
Substituting values x/y=3/2 & y/x=2/3
[(3/2)+1][(1+(2/3)]/[(3/2)-1][(1-(2/3)]
=[(5/2)(5/3)]/[(1/2)(1/3)]
=25

Like? Yes (1) | No   

Suman   11 years AGO

Here given x/y=3/2
Let us assume x=3k and y=2k where k>0
According to the question (x^2+y^2+2xy)/(x^2+y^2-2xy)
=(x+y)^2/(x-y)^2 [formula]
=(3k+2k)^2/(3k-2k)^2
=(5k/k)^2
=25 (answer)
=

Like? Yes (1) | No   

b.s.venkatesh   11 years AGO

(x+y)^2/(x-y)^2
y=2x/3
sub we get 25

Like? Yes (1) | No   

Harjit kaur   11 years AGO

x/y = 3/2
Applying componendo nd dividendo
X+y/x-y=5/1
Then, (x^2+y^2+2xy)/(x^2+y^2-2xy) = ?
(X+y)^2/(x-y)^2=(5k)^2/(1k)^2
=25

Like? Yes (1) | No   

batsal   11 years AGO

(x+y)^2/(x-y)^2=((5/2)/(1/2))^2=25

Like? Yes (1) | No   

Rashmi bharti   11 years AGO

(x+y)^2/(x-y)^2
=>25.

Like? Yes (1) | No   

theodar   11 years AGO

above given numerator has formula of (a+b)^2 and denominator is (a-b)^2 and hence applying, the answer is (3+2)^2/(3-2)^2=25
ANS:8)25

Like? Yes (1) | No   

krishnapriya   11 years AGO

multiply the given equation with 1/y^2 in numerator and denominator
then put x/y=3/2
the result will be 25

Like? Yes (1) | No   

Lavankumar Reddy   11 years AGO

First x/y = 3/2 then x = 3y/2
Second
(x^2+y^2+2xy)/(x^2+y^2-2xy) = (x+y)^2/(x-y)^2
= (x+y/x-y)^2
Then Substitute x value
=(3y/2+y/3y/2-y)^2
=(3y+2y/3y-2y)^2
=(5y/y)^2
=(5)^2
=25

Like? Yes (1) | No   

harjeet   11 years AGO

x/y=3/4
x=3y/2
put in
simplified equation
(x+y)^2/(x-y)^2=(3y/2+2)/(3y-2)
ans is 25

Like? Yes (1) | No   

SONU GUPTA   11 years AGO

If x/y=3/2
then, (x^2+y^2+2xy)/(x^2+y^2-2xy)=(x+y)^2/(x-y)^2=(x/y+1)^2/(x/y-1)^2=(3/2+1)^2/(3/2-1)^2=(5/2)^2/(1/2)^2=(25/4)/(1/4)=25

Like? Yes (1) | No   

Chandni Maurya   11 years AGO

ans=25
dividing by y^2 in Denominator n N. v get,
[(x/y)^2+1+2(x/y)]/[(x/y)^2+1-2(x/y)]
=>put x/y=3/2
=>25/1=25

Like? Yes (1) | No   

suseela   11 years AGO

it is of the form [(x+y)^2]/[(x-y)^2].when y is taken as common in numerator and denominator we get {([x/y]+1)/[x/y]-1}^2.solving it by sunbstituing x/y =3/2,we get 25

Like? Yes (1) | No   

bejavada suresh   11 years AGO

use this formuale(x+y)^2/(x-y)^2

Like? Yes (1) | No   

MANISH KUMAR   11 years AGO

use componendo-dividendo method
(x^2+y^2+2xy)/(x^2+y^2-2xy)=(x+y)^2/(x-y)^2
={(x+y)/(x-y)}^2
now,
x/y=3/2
=x+y/x-y=3+2/3-2
=x+y/x-y=5
squaring both sides;
{(x+y)/(x-y)}^2=25.......answer

Like? Yes (1) | No   

laxman   11 years AGO

take y^2 commn on both numerator and denominatr.then y^2 cancelld,then substitute the value given in the sum.........
we get 25 as answr........gud luck

Like? Yes (1) | No   

sivaramakrishna   11 years AGO

x=3k,y=2k
x+y=5k
x-y=k
25k^2/k^2==>25

Like? Yes (1) | No   

KD   11 years AGO

(x^2+y^2+2xy)/(x^2+y^2-2xy) =((x+y)/(x-y))^2 ...eqn1
x/y = 3/2 => x=3y/2
Now putting the value of x in the eqn 1.

we get ((5/2)/(1/2))^2=25 is the answer.

Like? Yes (1) | No   

shaswata tripathy   11 years AGO

x/y=3/2
let x/3=y/2=k(constant) x=3k y =2k
(x^2+y^2+2xy)/(x^2+y^2-2xy)
=(x+y)^2 / (x-y)^2
=(3k+2k)^2 / (3k-2k)^2
=25k^2 / k^2=25

Like? Yes (1) | No   

Dr.Dipin Singh   11 years AGO

If x/y = 3/2
Then, x= 3/2 y
(x^2+y^2+2xy)/(x^2+y^2-2xy) = (x+y)^2/(x-y)^2 = ((3/2y+y)/(3/2y-y))^2 = 5^2=25

Like? Yes (1) | No   

Neelu khandelwal   11 years AGO

this equals to (x+y)^2/(x-y)^2
=((x/y+1)/(x/y-1))^2
=25

Like? Yes (1) | No   

prakash kumar   11 years AGO

x/y=3/2
using componendo and dividendo rule
x+y/x-y =x/y
therefore (x+y)/(x-y)=(3+2)/(3-2)=5
(x+y)^2/(x-y)^2 = 5^2 =25,

Like? Yes (1) | No   

SURAJ ARYA   11 years AGO

x/y=3/2
using componendo and dividendo rule
x+y/x-y =x/y
therefore (x+y)/(x-y)=(3+2)/(3-2)=5
(x+y)^2/(x-y)^2 = 5^2 =25,

Like? Yes (1) | No   

Logeshwaran Thangaraj   11 years AGO

value of x=3 & y=2. substitute it in the equation. you will get the answer as 25. also, the given expression is nothing but (x+y)^2/(x-y)^2. substitute the value of x & y to get the answer

Like? Yes (1) | No   

Himodyuti Bardhan   11 years AGO

x and y has the common divisor which can be eliminated and so we can safely assume that x=3 and y=2.
Rest is basic maths.

Like? Yes (1) | No   

haritha Boyapati   11 years AGO

=>((x+y)/(x-y))2
=>given x/y=3/2
=>x=3y
=> submit in the above equation we get answer as 25

Like? Yes (1) | No   

asha   11 years AGO

x^2+y^2+2xy = (x+y)^2
x^2+y^2-2xy = (x-y)^2

(x+y)^2/(x-y)^2=(3+2)^2/(3-2)^2
--> 5^2/1^2 --> 25/1 =25
ans is option 8) 25.

Like? Yes (1) | No   

Bharat Bhushan Jha   11 years AGO

x=3/2*y
(x+y/x-y)^2=25

Like? Yes (1) | No   

ashish agarwal   11 years AGO

divide whole with xy

Like? Yes (1) | No   

Britto prabhu   11 years AGO

x/y=3/2;
so,x=3y/2;
(x+y)^2/(x-y)^2=(3y/2+y)^2/(3y/2-y)^2
(25y^2/4)/(y^2/4)
Ans:25

Like? Yes (1) | No   

rajith lakshmanan   11 years AGO

(x/y+1)^2 / (x/y-1)^2

Like? Yes (1) | No   

sowmya   11 years AGO

x/y=3/2
i.e x=3/2y
so sub given eq then ans is 25

Like? Yes (1) | No   

kant kumar   11 years AGO

x=3y/2
put this value in (x+y)^2/(x-y)^2

Like? Yes (1) | No   

Jasmine Khan   11 years AGO

x/y=3/2
by componendo & devidendo
x+y/x-y=5/1
squaring both the sides
(x+y)^2/(x-y)^2=25/1

Like? Yes (2) | No (1)  

Aditya Chittekar   11 years AGO

Taking x^2 common we get,
[1+(y/x)^2+ 2*y/x]/ [1+(y/x)^2-2*y/x]
Substituting y/x=2/3,
[1+ 4/9+ 4/3]/ [1+ 4/9- 4/3],
=25

Like? Yes (1) | No   

jyoti kumari   11 years AGO

x=3/2y
put the value of x in terms of y in given question

Like? Yes (1) | No   

aruna   11 years AGO

13+12/13-12=25/1=25

Like? Yes (1) | No   

Rahul Gupta   11 years AGO

(x+y/x-y)2
=((x/y+1)/(x/y-1))2
=(3/2+1/3/2-1)2
=(3+2/3-1)2
=(5)2
=25

Like? Yes (2) | No (1)  

abhi   11 years AGO

(x+y)^2/(x-y)^2
taking y common
y^2(x/y+1)^2/y^2(x/y-1)
y^2 will cut
then
y/x=3/2
so answer is 25

Like? Yes (1) | No   

Ann Mary Jolly   11 years AGO

Ans 8) 25
x/y = 3/2 = 1.5
=> x =1.5y ....(1)
Then,(x^2+y^2+2xy)/(x^2+y^2-2xy)=((x+y)^2)/((x-y)^2)
Substituting (1) in the above expression,we get
ans = (2.5y)^2/(.5y)^2 = (2.5/.5)^2
= 25

Like? Yes (1) | No   

arijit sarkar   11 years AGO

(x^2+y^2+2xy)/(x^2+y^2-2xy)

=(x+y)^2/(x-y)^2
={(3y/2)+y)}^2/{(3y/2)-y)}^2 [x/y=3/2, so x=3y/2]
=(5y/2)^2/(y/2)^2
=25y^2/4 * 4/y^2
=25

Like? Yes (1) | No   

Kinjal Shah   11 years AGO

The equation is equivalent to (x+y)^2/(x-y)^2
Let x=3 and y=2
SUbstituting the values. Answer is 25

Like? Yes (1) | No   

NavyaNuchu   11 years AGO

(x+y)^2/(x-y)^2=divide num dino by y=>(x/y+1)^2/(x/y-1)^2=(5/2)^2/(1/2)^2=25

Like? Yes (1) | No   

vishnu   11 years AGO

ans is 25
let divide numerator and denominator by y^2 and substutite the x/y values

Like? Yes (1) | No   

Neha Sharma   11 years AGO

x^2+y^2+2xy)/(x^2+y^2-2xy)=(x+y)^2/(x-y)^2
=>y^2(x/y+1)/y^2(x/y-1)
here x/y=3/2
=>(3/2+1)^2/(3/2-1)^2
=>5^2=25

Like? Yes (1) | No   

sandy   11 years AGO

it can be written as (x+y)^2/(x-y)^2
substitute x=3/2*y
we will get ans as 25

Like? Yes (1) | No   

mehul   11 years AGO

put x=3y/2
y^2 will get cancel & hence we obtain 25

Like? Yes (1) | No   

Yatin Batra   11 years AGO

numerator is (x+y) square and denominator is (x-y
0 square....then make it whole square and apply componendo devidendo...we will get 25 as the ans.

Like? Yes (1) | No   

niranjanpulikonda   11 years AGO

apply componendo and dividendo
x/y=3/2
x+y/x-y=5
squaring on both sides

Like? Yes (1) | No   

susmit   11 years AGO

x/y = 3/2.
So by compodendo and dividendo.
(x+y)/(x-y) = (3+2)/(3-2) = 5
So, (x^2+y^2+2xy)/(x^2+y^2-2xy) = (5^2)/(1^2) = 25/1 = 25.
Hence, option no. (8)

Like? Yes (2) | No (2)  

R.RAVIKUMAR   11 years AGO

(x+y)^2/(x-y)^2
=> (x/y+1)^2/(x/y-1)^2
=> (3/2+1)^2/(3/2-1)^2 as x/y=3/2
=> 25

Like? Yes (2) | No (2)  

Suman Saurabh   11 years AGO

Given x/y=3/2
(x^2+y^2+2xy)/(x^2+y^2-2xy)=(x+y)^2 /(x-y)^2 =25

Like? Yes (1) | No (1)  

Sriparna Boote   11 years AGO

We know that
(x^2+y^2+2xy)=(x+y)^2
(x^2+y^2-2xy)= (x-y)^2
so the given equation is in the fform of
(x+y)^2/(x-y)^2
now dividing numerator and denominator by 1/y^2 we get

(x/y+1)^2/(x/y-1)^2
now putting x/y= 3/2 we get
the required answer as 25


hence 25 is the answer

Like? Yes (2) | No (2)  

PINKY   11 years AGO

x=3
y=2
(3+2)^2/(3-2)^2
25

Like? Yes (2) | No (2)