MADHU KUMARI   11 years AGO

formula
if a is r% more than b then b is less than a by
( (r/(100+r))*100)%
((10/(100+10))*100)=9.09%

Like? Yes (9) | No (2)  

sharath   11 years AGO

1st 100
2nd 110
%less=(100/110)*100=9.09

Like? Yes (2) | No   

mirtunjay verma   11 years AGO

(10/110)*100=9.09

Like? Yes (3) | No (1)  

R.RAVIKUMAR   11 years AGO

let manvinder marks be x and sukhvinder marks be y
so, x=(1+0.1)y
so, y=(1/1.1)x
that is y=0.909x
so, y=(1-0.0909)x
so, y is (0.0909*100)=9.09% marks less than x.

Like? Yes (5) | No (4)  

Devendra Marghade   11 years AGO

If marks of Sukhvinder=x,Manvinder=x+(x*10/100)=1.1x
If 1.1x marks are considered as 100%
then x= x*100/1.1x= 90.90%
So % less=100-90.90=9.09

Like? Yes (2) | No (1)  

Ann Mary Jolly   11 years AGO

Ans: 7) 9.09
Let marks of Sukhvinder be x.Then marks of Manvinder is 1.1x
Marks by which Sukhvinder has less than Manvinder = (1.1x-x)/1.1x*100 = .1/1.1*100 = 9.09%

Like? Yes (2) | No (1)  

Leelanand Kumar Yalla   11 years AGO

If sukhvinder got 100 marks.. then
Manvinder got 110 marks..
therefore.. (10/110)*100= 9.09

Like? Yes (2) | No (1)  

siddhanta kumar Behera   11 years AGO

x*(10/100)=x/10
x+x/10=11x/10
(11x/10)*(y/100)=x/10
y=100/11=9.09
............ANSwer

Like? Yes (2) | No (1)  

Himani   11 years AGO

let sukhvinder obtained 20 marks
10% of 20 is 2 hence maninder\'s marks=22
sukhvinder\'s maks is 2 less than manininder
therefore (2/22)*100 = 9.09%

Like? Yes (1) | No   

AMIT JAISWAL   11 years AGO

given that marks of manvinder is 10% more than sukhvinder,then
according to the formula-
marks of sukhvinder is lesser than manvinder
=(10/100+10)*100%
=(10/110)*100%
=100/11=9.09
so correct answer=9.09

Like? Yes (1) | No   

Lavankumar Reddy   11 years AGO

Suppose Let Sukhvinder obtain 100
then Manvinder 10% more than Sukhvinder = 110
then less than by Sukhvinder then Manvinder = 10/110*100 = 9.09

Like? Yes (1) | No   

Abirudh reddy   11 years AGO

1st 100
2nd 110
%less=(100/110)*100=9.09

Like? Yes (1) | No   

Harsha ludhani   11 years AGO

if sukhvinder = 100
than manvinder = 110

so sukhvinder obtained 10 less marks
that is (10/110)*100
it is 9.09 (option 7)

Like? Yes (1) | No   

Abhijeet Kumar   11 years AGO

let
sukhvider got x marks out of 100 then
manvider marks would be [x+(x*10/100)]=(x+0.1x)
difference is (x+0.1x-x) = 0.1x marks
and (x+0.1x)= 1.1x
if (1.1x) is 100 perecntage
then 0.1x is (100/1.1x)*0.1x=(100/11)*1
= 9.09 percentage

Like? Yes (1) | No   

FAISAL RIZWAN   11 years AGO

For this question we have formulae
[(x/(100+x)*100]%
then put the value of x=10
[10/(100+10)*100]%
(10/110)*100
after solving we get 9.09
So option 7 is correct

Like? Yes (2) | No (1)  

mukesh   11 years AGO

1000/110

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syed raashid hussain   11 years AGO

110 - 110*x% = 100
110- 110*x/100 =100
x=100/11
x=9.09
as how many percentage of 110 is less from 110 so that it get 1oo. so above is the procedure to solve that.

Like? Yes (2) | No (1)  

arun prakash singh   11 years AGO

% less marks=(10\110)*100=9.09

Like? Yes (1) | No   

mahi   11 years AGO

(m-1.1m/m)*100=9.09%

Like? Yes (1) | No   

vishal shanker polowalia   11 years AGO

let sukhvinder marks be 100
so, manvinder marks is 110
{(110-100)/110}*100= 9.09

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Udhaya kumar   11 years AGO

let Sukhvinder mark as x and r is the % of required value
then
10 x = [x+(10x/100)] * r
10 x = 110 x /100 * r
r = 100*10/110
r = 1000/110 = 9.09090909............

Like? Yes (2) | No (1)  

YUVAN SATHAIAH   11 years AGO

formula used:
if A is R% more than B, then B is less than A by [R/(100+R)*100]%

if A is 10% more than B by =[10/(100+10)*100]%

=9.09

Like? Yes (1) | No   

SAISIREESH BABU CHERUKU   11 years AGO

lets suppose sukhvinder got 90 so it makes mavinder 99
if 99 is 100% the find what percent is 9
900/99=9.090909

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chandana   11 years AGO

(1/(10+1))*100=9.09

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rajkumar   11 years AGO

if sukuvindar got 100 marks then mahvindar gets 110 as per problem
so difference is 10 marks sukuvindar less than mahavindar
so => 10/110*100=9.09% less

Like? Yes (1) | No   

SAURABH KHOTANI   11 years AGO

manvinder obtains 10% more
so sukhvinder will have (100*10)/(100+10)%less
i.e. 9.09%

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deepak   11 years AGO

as we divided by 110 we get 9.09 as ans

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RAKESH   11 years AGO

(10/110)*100=100/11=9.09

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KRISHNAN   11 years AGO

Assuming Sukhvinder get 10 marks, then Manvinder gets 10% more marks i.e (10 + 10%of 10) 11 marks
Sukvinder get 1 marks less than Manvinder or
1/11*100 or 9.09% less marks is obtained by Sukvinder than Manvinder
Option 7 is the correct answer

Like? Yes (1) | No (1)  

Rajasekhar Reddy   11 years AGO

let the sukhvinder marks be x
then, Manvinder marks be y = 1.1x
then x = 1/1.1 = 0.909y
% of less marks obtained by sukhvinder than Manvinder is
(y-0.909y)/y * 100 = 9.09%

Like? Yes (1) | No (1)  

Abhijeet Dabre   11 years AGO

M = 110 marks (10% more than) S
if 110 is 100 marks means S got Less marks
by % is...
S = 10/110*100
Therefore S = 9.09.
Option 7.

Like? Yes (1) | No (1)  

Dinesh thatti   11 years AGO

say Sukhvinder=100%
Manvinder obtains 10% marks more then Sukhvinder

Manvinder=110%

10/110*100=9.09

Like? Yes (1) | No (1)  

sai sirish   11 years AGO

let x be sukhvinder marks,then manvinder marks will be x+0.1x=1.1x,
% less mrks obtained by sukhvinder than manvinder=
(1.1x-x)/1.1x=0.1x/1.1x=1/11=9.09

Like? Yes (1) | No (1)  

Prabhat Yadav   11 years AGO

*100=9.09

Like? Yes (2) | No (2)  

harjeet   11 years AGO

let Sukhvinder's marks=80
Soo,
Manvinder marks =110%of(Sukhvinder's marks)
=110/100(80)=88
then

x%of(Manvinder's marks)= Sukhvinder's marks

x%=80/88

x%=9.09 option(7)

Like? Yes (1) | No (1)  

Ankit Goyal   11 years AGO

(1/11) * 100 = 9.09

Like? Yes (1) | No (1)  

Satyendra Singh   11 years AGO

formulae in such situation when rate increases of a commodity by R% than the reduction in cosumption so as not to increase the expenditure is
[(R)*100/(100+R)]%
[10*100/(100+10)]% = 9.09

Like? Yes (1) | No (1)  

vaibhav kumar    11 years AGO

let mavindra has 110 rs
so sukhvindra have 100

percentage =10*100/110=9.09

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Gautham   11 years AGO

(10/110)*100=9.09

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julee verma   11 years AGO

according to the question,
let Sukhvinder marks=x
so manvinder marks=x+x*10%
=11x/10
so, differnce of marks=11x/10-x=x/10
so less marks obtained by sukhvinder than manvinder = (x/10)/(11x/10)*100=100/11=9.09
therefore answer=9.09
or
according to the formula,
marks of sukhvinder is less than marks of manvinder= [10/(100+10)]*100%
=9.09

Like? Yes (1) | No (1)  

vishal barun   11 years AGO

let,marks obtained by sukhwinder = x
marks obtained by manvinder = 1.1*x
% less marks obtained by sukhwinder than manwinder = (1.1*x-x)/1.1*x = 9.09 % (option 7)

Like? Yes (1) | No (1)  

lovely verma   11 years AGO

given that-
marks of manvinder is 10% more than sukhvinder,so
according to the formula-
sukhvinder marks is less than manvinder
= [10/100+10]*100%
=100/11=9.09
answer=9.09

Like? Yes (1) | No (1)