What is the next number of the following sequence 122,486,1092,1940,..........

M4maths Previous Puzzles

23 Dec 2013 Sequence What is the next number of the following sequence 122,486,1092,1940,..........: OPtion
1) 3025
2) 2936
3) 3096
4) 3030
5) 4050
6) 3265
7) 4356
8) 4362
9) 1189
10)None of these; Correct Option: 4 Best Solution (80)

Akanksha Mishra 11 years AGO

look upon the series carefully
122,486,1092,1940.....

First Method :
(11*11*1^2) + 1 = 122
(11*11*2^2) + 2 = 364
(11*11*3^2) + 3 = 1092
(11*11*4^2) + 4 = 1940
So next no. will be;
(11*11*5^2) + 5 = 3030

Another Method:
486 - 122 = 364
1092- 486 = 606
1940-1092 = 848

606-364 = 242, 848 - 606 = 242
therefore
848 + 242 = 1090
1090+ 1940= 3030
so answer will be option (4)

I hope my answer will easy to understand

Like? Yes (24) | No (9)

Udhaya kumar 11 years AGO

11 * 11 + 1 = 122
22 * 22 + 2 = 486
33 * 33 + 3 = 1092
44 * 44 + 4 = 1940
similarly
55 * 55 + 5 = 3030........

Like? Yes (7) | No (4)

mayank 11 years AGO

122= (11)2+1
486=(22)2+2
1092=(33)2+3
1940=(44)2+4
next is
3030=(55)2+5

Like? Yes (4) | No (1)

T.Aravinth kumar 11 years AGO

given
122, 486, 1092, 1940.....
take difference between adjacent numbers
346, 606, 848....----(1)
take difference once more
242, 242, .....---(2)
SO add 242 with 848---> 242+848=1090.
THEN 1090 + 1940=3030.
ans(4).

Like? Yes (3) | No (1)

Rahul gulati 11 years AGO

122,486,1092,1940,...(3030)
difference:
364,606,848,...(1090)
Difference:
242,242,...,(242)

Like? Yes (2) | No

Amit kumar 11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1092
44^2+4=1940
55^2+5=3030

Like? Yes (4) | No (2)

Sajib Ghosh 11 years AGO

486=122*4-2=(122)*(2^2)-(2*1)
1092=122*9-6=(122)*(3^2)-(3*2)
1940=122*16-12=(122)*(4^2)-(4*3)

now the next term will be
(122)*(5^2)-(5*4)=122*25-20=3050-20=3030
so, option 4 is correct

Like? Yes (2) | No (1)

TAREK HAYDER SK 11 years AGO

difference between two numbers are increasing by 242. e. g. (486-122)=364;(1092-486)=606;[606-364]=242;(1940-1092)=848;[848-606]=242;
so,848+242=1090 then next term is 1940+1090=3030

Like? Yes (3) | No (2)

M.ANAND 11 years AGO

11^2+1 = 122
22^2+2 = 486
33^2+3 = 1092
44^2+4 = 1940
next
55^2+5 = 3030

Like? Yes (1) | No

krishna 11 years AGO

given that 122,486,1092,1940,..
==>122*1^2 = 122 - 1*0 = 122
==>122*2^2 = 488 - 2*1 = 486
==>122*3^2 = 1098 - 3*2 = 1092
==>122*4^2 = 1952 - 4*3 = 1940
==>122*5^2 = 3050 - 5*4 = 3030
==>122*6^3 = 4392 - 6*5 = 4362
so series is 122,486,1092,1940,3030,4362 .....

Like? Yes (2) | No (1)

eeranna 11 years AGO

(11^2)+1=122
(22^2)+2=386
(33^2)+3=1092
(44^2)+4=1940
(55^2)+5=3030

Like? Yes (2) | No (1)

Amit pandit 11 years AGO

squre root of every number is in the sequense of 11.045,22.045,33.045,44.045 and the option 4 has 55.045

Like? Yes (2) | No (1)

Roushan Singh 11 years AGO

11*11 = 121+1 = 122
22*22 = 484+2 = 486
33*33 = 1089+3 = 1092
44*44 = 1936+4 = 1940
similarly,
55*55 = 3025+5 = 3030

Hence ans is 4)3030

Like? Yes (3) | No (2)

Pradyumna K S 11 years AGO

121n^2 + n.
121(1)^2+1=121
121(2)^2+2=486
121(3)^2+3=1092
121(4)^2+4=1940
121(5)^2+5=3030

Like? Yes (2) | No (1)

muthu 11 years AGO

(122*5^2)-5*4=3030

Like? Yes (1) | No

swastik 11 years AGO

it is a series of 121*n^2+n
so 121*1^2+1=122
121*2^2+2=486
121*3^2+3=1092
121*4^2+4=1940
121*5^2+5=3030

Like? Yes (1) | No

Ashfaque Hussain 11 years AGO

11*11+1=122 , 22*22+2=486 , 33*33+3=1092 , 44*44+4=1940 , 55*55+5=3030

Like? Yes (1) | No

chandana 11 years AGO

The numbers in the series are of the form (121*n^2)+n.
(121*1^2)+1=122(first number)
(121*2^2)+2=486(second number)
(121*3^2)+3=1092(third number)
(121*4^2)+4=1940(fourth number)
(121*5^2)+5=3030(fifth number).
so my answer is 3030(option 4)

Like? Yes (1) | No

ABHISHEK KUMAR 11 years AGO

122=11*11+1
486=11*44+2 44-11=33
1092=11*99+3 99-44=55
1940=11*176+4 176-99=77
now 176+99=275
therefore
next number=11*275+5=3030

Like? Yes (1) | No

pratibha Tiwari 11 years AGO

divide all the numbers of series by 2 to simplify the series
on dividing,We will get 61,243,546 and 970
Now 243-61=182
546-243=303
970-546=424 nw if we see the difference between obtained no.s it is equal like 303-182=121&424-303=121
Nw if we add 121 next to 424 we get 424+121=545 nw add 970+545=1515 we got the no. Of series. We mouble the number 1515*2=3030..we got actual no.of series,.

Like? Yes (1) | No

srivatsan v 11 years AGO

the difference for each number is increased by 242 when you subtract 1940 from 3030 you will get 1090 which is increased by 242 from the previous difference

Like? Yes (1) | No

pratik jitendra malviya 11 years AGO

11*11+1=122
22*22+2=486
33*33+3=1092
44*44+4=1940
55*55+5=3030

Like? Yes (1) | No

g.soujanya 11 years AGO

122 486 1092 1940 3030
364 606 848 1090
242 242 242

Like? Yes (1) | No

sai sirish 11 years AGO

486-122=364
1092-486=606=364+242
1940-1092=848=606+242
next=1940+848+242=3030

Like? Yes (1) | No

Gunaseelan 11 years AGO

Given 121 = (11*11)+1
486 = (22*22)+2
1092 = (33*33)+3
1940 = (44*44)+4
Thus Answer is 3030 = (55*55)+5

Like? Yes (2) | No (1)

Priya Dharshini 11 years AGO

first get the difference between 486 and 122,then get difference between 1092 and 486,then similarly for 1940 and 1092.the differences are 364,606,848 again the difference between 364 and 606 is 242.and similarly the difference between 848 and 606 is 242.so obviosly the next number in the sequence we can get by adding 848 and 242 so that we get 1090.finally 1940+1090=3030.

Like? Yes (1) | No

Aditya Verma 11 years AGO

series 122,486,1092,1940
differences series 364,606,848...
diff of diff series 242,242,....
848+242=1090
next term = 1940+1090= 3030
answer is option 4

Like? Yes (1) | No

RagunathKC 11 years AGO

(121)(x^2)+x
if x=1 then 121+1=122
if x=2 -> 121*4+2=486
if x=3 -> 121*9+3=1092
if x=4 -> 121*16+4=3030

Like? Yes (1) | No

sivaraman 11 years AGO

122-486=364, 486-1092=606, 1092-1940=848
so
364,606,848 the common difference of this number is 242
so
add 242+848=1090
1090+1940=3030

Like? Yes (1) | No

Anilkumar 11 years AGO

121*1+1=122
121*4+2=486
121*9+3=1092
121*16+4=1940
121*25+5=3030

Like? Yes (1) | No

Prakash kumar 11 years AGO

11^2+1
22^2+2
------
55^2+5 = 3030

Like? Yes (1) | No

navneet shankhwar 11 years AGO

by the sequence 242 is the difference of the difference of the given number
therefor, 242+848=1090
1090+1940=3030

Like? Yes (1) | No

kishan kumar 11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1096
44^2+4=1940
55^2+5=3030

Like? Yes (1) | No

VIKASH RAY 11 years AGO

the general formula of this series is- 121n^2 + n.
we have to find the fifth term in this series, so n=5.
by putting n=5 in the general formula we get 3030.
hence,option 4 is correct.

Like? Yes (1) | No

SHRISH SHUKLA 11 years AGO

11*11+1 , 22*22+2 , 33*33+3.....so on..
answer
3030

Like? Yes (1) | No

thol 11 years AGO

the difference btween each difference is 242.,by adding it to the next number we get 3030...

Like? Yes (1) | No

asam srinivasa kumar 11 years AGO

(121*n^2) + n where n=1,2,3,....
n=5--->(121*5^2)+5=3030

Like? Yes (2) | No (2)

Narendra 11 years AGO

121n^2 + n.

Like? Yes (1) | No (1)

vishal shanker polowalia 11 years AGO

The reason is 121(n^2)+n
when n = 1
122

when n = 2
486

when n = 3
1092
when n = 4
1940
when n = 5
3030

Like? Yes (1) | No (1)

Jigyasa Kumar 11 years AGO

its following the sequence 121 n^2 +n
so the next no. will be 3030

Like? Yes (1) | No (1)

Leelanand Kumar Yalla 11 years AGO

Here 122= 121*1+1=122;
486=121*4+2=486;
1092=121*9+3=1092;
1940=121*16+4=1940;
similarly.....
Next 121*25+5=3030.....
This is the Answer.....

Like? Yes (2) | No (2)

Shubham Saxena 11 years AGO

The Given series is 122,486,1092,1940,..........
486-122=364
1092-486=606
1940-1092=848
The difference of 606 & 364 and 848 & 606= 242
So by considering the difference of 242
Next no. will be 3030
as, 3030-1940=1090
which again 1090-848=242
Hence Answer is 3030

Like? Yes (2) | No (2)

D.Mamatha 11 years AGO

The given sequence is 122,486,1092,1904,....

(121*1^2) + 1 = 122

(121*2^2) + 2 = 486

(121*3^2) + 3 = 1092

(121*4^2) + 4 = 1940

Similarly......

(121*5^2) + 5 = 3030

So the option 4 is correct.

Like? Yes (2) | No (2)

susmit 11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1092
44^2+4=1940
so answer is 55^2+5=3030
option no.4

Like? Yes (1) | No (1)

Rajasekhar Reddy 11 years AGO

the sequence is follows as
121*(n^2) + n
where n = 1,2,3,4,5,.......
for n = 5
121*25 + 5 = 3030

Like? Yes (1) | No (1)

Ankit Goyal 11 years AGO

11^2 + 1 = 122
22^2 + 2 = 486
33^2 + 3 = 1092
44^2 + 4 = 1940
55^2 + 5 = 3030 (Answer)

Like? Yes (1) | No (1)

Aarush Singh 11 years AGO

121n^2 + n

Like? Yes (1) | No (1)

Pratiksha Gupta 11 years AGO

Like? Yes (2) | No (2)

R.RAVIKUMAR 11 years AGO

(122*4)-2=486
(122*9)-6=1092
(122*16)-12=1940
(122*25)-20=3030

Like? Yes (2) | No (2)

kumar sundram 11 years AGO

here,
(11*1)^2+1=121
(11*2)^2+2=486
(11*3)^2+3=1092
(11*4)^2+4=1940
so, next no. is
(11*5)^2+5=3030

Like? Yes (1) | No (1)

Shubham Saxena 11 years AGO

Like? Yes (1) | No (1)

Siba Kumar Sahu 11 years AGO

ans: 3030
because the terms are in the series as
122
122*2^2-2*1 =486
122*3^2-3*2 =1092
122*4^2-4*3 =1940
so the next term will be
122*5^2-5*4=3030

Like? Yes (1) | No (1)

satyen nabar 11 years AGO

The difference between numbers is 364, 606, 848. the difference is increasing by 242. Hence 848+242=1090. 1940+1090=3030.

Like? Yes (1) | No (1)

rupireddy bharath kumar 11 years AGO

(11)^2+1=122
(22)^2+2=486
(33)^2+3=1092
(44)^2+4=1940
(55)^2+5=3030

Like? Yes (1) | No (1)

KRISHNAN 11 years AGO

The series is formed by 121*n^2+1
so 121+1^2+1 =122
121+2^2+2 =486
121+3^2+3 = 1092
121+4^2+4 = 1940
121+5^2+5 = 3030

Like? Yes (1) | No (1)

Arati Sethi 11 years AGO

we have the nos 122,486,1092,1940 so looking at the nos we can write the nos as
122
122*4-2*1 =486
122*9-3*2 =1092
122*16-4*3 =1940
so according to the series the next no must be
122*25-5*4=3030

Like? Yes (1) | No (1)

P Niranjan 11 years AGO

series in the form of
121*n^2+n

n starts with 1
so, 121*5^2+5 = 3030

Like? Yes (1) | No (1)

Sukanya 11 years AGO

122 486 1092 1940 3030

364 606 848 1090

242 242 242
Hence there is a common difference of 242 for each increase.

Like? Yes (1) | No (1)

Dinesh thatti 11 years AGO

11^2=121+1=122,
22^2=484+2=486,
33^2=1089+3=1092,
44^2=1936+4=1940,
55^2=3025+5=3030

Like? Yes (1) | No (1)

YUVAN SATHAIAH 11 years AGO

11*11+1=122
22*22+2=486
33*33+3=1092
44*44+4=1940
then
55*55+5=3030
option is 4)3030

Like? Yes (1) | No (1)

SONU GUPTA 11 years AGO

122,486,1092,1940,?
so
11*11=121+1=122
22*22=484+2=486
33*33=1089+3=1092
44*44=1936+4=1940
55*55=3025+5=3030
so answer will be 3030

Like? Yes (1) | No (1)

Harshit Daga 11 years AGO

The difference is
364, 606, 848, y(difference between the next number of the series and 1940)

Assume that next number should be x
means x = 1940+y

now if you see that the difference series gives the difference as 242, 242, 242
which means y = 848+242
y=1090

and therefore,
x=1940+y
x=3030

Like? Yes (1) | No (1)

JAYANTHI K 11 years AGO

(11^2)+1=122
(22^2)+2=486
(33^2)+3=1092
(44^2)+4=1940
similarly
(55^2)+5=3030

Like? Yes (1) | No (1)

SanthoshKumar 11 years AGO

(11*11)+1 =122
(22*22)+2 =486
(33*33)+3 =1092
(44*44)+4 =1940
(55*55)+5 =3030(answer)

Like? Yes (1) | No (1)

jaya prakash reddy 11 years AGO

sequence of n numbers : 121n^2+n

Like? Yes (1) | No (1)

Dr.Dipin Singh 11 years AGO

nth tgerm is given by
(11n)^2+n
1st term=(11*1)^2+1=122
..
..
5th term = (11*5)^2+5= 55^2+5= 3025+5=3030

Like? Yes (2) | No (2)

Abhijeet Kumar 11 years AGO

general form :(121*n^2)+n
(121*1^2)+1=(121*1)+1=122
(121*2^2)+2=(121*4)+2=486
(121*3^2)+1=(121*9)+3=1092
(121*4^2)+2=(121*16)+4=1940
(121*5^2)+1=(121*25)+5=3030...Ans

Like? Yes (2) | No (2)

VINAYKUMAR MR 11 years AGO

(x2 * n) + n
X= 11 n= 1,2,3,4,5,6..........
(121 * 1) + 1 = (121 * 1) + 1 =122
Similarly (11^2 * 5^2)+5
(121 * 25)+5 =3030

Like? Yes (2) | No (2)

Keshav Kishlay 11 years AGO

486-122=364,
1092-486=606,
1940-1092=848 and
606-364=242,
848-606=242 so,
similarly 848+242=1090 and 1940+1090=3030

Like? Yes (1) | No (1)

pankaj chandra joshi 11 years AGO

11^2+1,22^2+2...............55^2+5

Like? Yes (1) | No (1)

achyuth 11 years AGO

11*11+1=122
22*22+2=486
33*33+3=1092
44*44+4=1940
the next number..
55*55+5=3030
ans;3030

Like? Yes (1) | No (1)

AMIT JAISWAL 11 years AGO

here 486-122=364
1092-486=606 (364+242)
1940-1092=848(606+242)
x-1940=848+242
x=1940+1090
x=3030

Like? Yes (1) | No (1)

amit bhagat 11 years AGO

here 486-122=364
1092-486=606 (364+242)
1940-1092=848(606+242)
x-1940=848+242
x=1940+1090
x=3030

Like? Yes (1) | No (1)

Krishna Chaitanya 11 years AGO

The number's difference is in AP with common difference 242,
486-122=364
1092-486=606
1940-1092=848
now the numbers 364,606,848 are in AP with d=242 therefore we need to add 242 to 848 so that we get 1090 now we should add 1090 to 1940 to get next number which is 3030.

Like? Yes (1) | No (1)

Nivetha 11 years AGO

The series follows the sequence 121n^2+n
121(1^1)+1=122
121(2^2)+2=486
121(3^2)+3=1092
121(4^2)+4=1940
121(5^2)+5=3030

Like? Yes (1) | No (1)

kiran kumar reddy yanamala 11 years AGO

11*11+1,22*22+2,33*33+3,44*44+4,55*55+5,.....

Like? Yes (1) | No (1)

julee verma 11 years AGO

11^2+1=122
22^2+2=486
33^2+3=1092
44^2+4=1940
55^2+5=3030

Like? Yes (1) | No (1)

A.Sivapriya 11 years AGO

Given Sequence is 122,486,1092,1940

122 = (121 X 1^2)+1
486 = (121 X 2^2)+2
1092 = (121 X 3^2)+3
1940 = (121 X 4^2)+4

Like wise the next number is (121 X 5^2)+5 = 3030
So, the option is 4.

Like? Yes (2) | No (3)

J.Arun kumar 11 years AGO

(11*11)+1=122
(22*22)+2=486
(33*33)+3=1092
(44*44)+4=1940
(55*55)+5=3030

Like? Yes (1) | No (2)

Meenakshi 11 years AGO

122*4=488-2=486
122*9=1098-6=1092
122*16=1952-12=1940
122*25=3050-20=3030

Like? Yes (1) | No (2)

Dimple

India

Punjab

Time: 00:01:33

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What is the next number of the following sequence 122,486,1092,1940,..........

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23 Dec 2013 Sequence

What is the next number of the following sequence
122,486,1092,1940,..........

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