If in coded language ARJUN = 52898 GAURAV = 58182 RAJAN = 2518 Then VEDAN = ?

BHANU KUMAR   10 years AGO

PRODUCT OF THE ALPHABET'S VALUES-(SUM OF ODD VALUES IN IT)=REQUIRED VALUE

ARJUN=1*18*10*21*14=52920
52920-(1+21)=52898

GAURAV=7*1*21*18*1*22=58212
58212-(7+1+21+1)=58182

RAJAN =18*1*10*1*14=2520
2520-(1+1)=2518
HENCE

VEDAN=22*5*4*1*14=6160
6160-(5+1)=6154 [OPTION 8]

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Urvashi Jain   10 years AGO

a=1 b=2 c=3 d=4 e=5 f=6 g=7 h=8 i=9 j=10 k=11 l=12 m=13 n=14 o=15 p=16 q=17 r=18 s=19 t=20 u=21 v=22 w=23 x=24 y=25 z=26
ARJUN=1*18*10*21*14=52920
ADD ODD NUMBERS 1+21=22
SUBTRACT 52920-22=52898
GAURAV=7*1*21*18*1*22=58212
ADD ODD NUMBERS7+1+21+1=30
SUBTARCT 58212-30=58182
RAJAN=18*1*10*1*14=2520
ADD ODD NUMBERS 1+1=2
SUBTRACT 2520-2=2518
VEDAN=22*5*4*1*14=6160
ADD ODD NUMBERS=5+1=6
SUBTRACT 6160-6-6154
OPTION 8

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Udhaya kumar   10 years AGO

(multiply of all alphanumerics) - (sum of odd alphanumerics)
VEDAN = (22*5*4*1*14) - (5+1) = 6154..........

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KRISHNA CHANDRA UPADHYAY   10 years AGO

PRODUCT OF THE ALPHABET'S VALUES-(SUM OF ODD VALUES IN IT)=REQUIRED VALUE

ARJUN=1*18*10*21*14=52920
52920-(1+21)=52898

GAURAV=7*1*21*18*1*22=58212
58212-(7+1+21+1)=58182

RAJAN =18*1*10*1*14=2520
2520-(1+1)=2518
HENCE

VEDAN=22*5*4*1*14=6160
6160-(5+1)=6154 [OPTION 8]

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ANKUR ANAND   10 years AGO

A(1) B(2) C(3) D(4) E(5) F(6) G(7)H(8)I(9)J(10)K(11)L(12)M(13)N(14)O(15)P(16)Q(17)R(18)S(19)T(20)U(21)V(22)W(23)X(24)Y(25)Z(26)

ARJUN= 1*18*10*21*14=52920-22=52898
GAURAV=7*1*21*18*22=58212-30=58182
RAJAN=18*1*10*1*14=2520-2=2518
VEDAN=22*5*4*1*14=6160-4=6154

ANSWER 8)

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ABHINAV THAKUR   10 years AGO

ARJUN : 1 18 10 21 14, If we multiply the digits we will get 52920, and the given code is 52898, hence there is a difference of 22, and if we look at the normal codes there are 2 odd digits, 1 and 21, whose sum will be 22, this is the main logic.

GAURAV: 7 1 21 18 1 22, Product=58212, given code=58182, Difference=30(sum of 7,1,21,1- odd digits)

RAJAN: 18 1 10 1 14, Product=2520, given code=2518.
Difference=2(sum of 1 & 1-odd digits)

Similarly, VEDAN: 22 5 4 1 14, Product=6160. Sum of odd digits=5+1=6. HENCE, code will be 6160-6=6154.

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T.Aravinth kumar   10 years AGO

A(1),B(2),...Z(26).
VEDAN=(22*5*4*1*14)-(5+1)=6154.

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BITU KUMAR NIRALA   10 years AGO

REQUIRED VALUE=PRODUCT OF THE ALPHABET'S VALUES-(SUM OF ODD VALUES IN IT)

ARJUN=1*18*10*21*14=52920
52920-(1+21)=52898

GAURAV=7*1*21*18*1*22=58212
58212-(7+1+21+1)=58182

RAJAN =18*1*10*1*14=2520
2520-(1+1)=2518
HENCE

VEDAN=22*5*4*1*14=6160
6160-(5+1)=6154
Answer:-6154 (OPTION 8)

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amit vijayvargiya   10 years AGO

vedan=22*5*4*1*14=6160-6=6154

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Devendra Marghade   10 years AGO

Number all the letters of word according A=1,B=2,C=3,D=4,.........,Z=26
Multiply all the numbers of word and subtract the sum of vowels.
So,
VEDAN =(22)(5)(4)(1)(14)=22*5*4*1*14-(5+1)=6160-6=6154

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swarupa nuggu   10 years AGO

6160-6

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kanchan   10 years AGO

arjun...multiply as1*18*10*21*14=52920
52920-22=52898
similarly
gaurav
7*1*21*18*1*22=58212
58212-30=58182
sim
for
rajan
18*1*10*1*14=2520;2520-2=2518
for vedan 22*5*4*1*14=6160
aprox ans is 6154

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Sandip Dutta   10 years AGO

ARJUN = 1*18*10*21*14 -(1+21)=52898 (here A & U are Vowel)
RAJAN =18*1*10*1*14 - (1+1) = 2520 (for 2 A )
so
VEDAN = 22*5*4*1*14 - (5+1) =6154 (here E & A are Vowel)

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Narendra Jadon   10 years AGO

Multiplication of all the digits is nearly equal to the give code...
Hence for VEDAN
22x5x4x1x14 = 6160
Hence answer is 6154
Option 8.

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sompon temtheerakij   10 years AGO

A=1,B=2,C=3,.........X=24,Y=25,Z=26
ARJUN = (1*18*10*21*14)-(1+18+10+21+14)+42 = 52898
GAURAV = (7*1*21*18*1*22)-(7+1+21+18+1+22)+40=58182
RAJAN = (18*1*10*1*14)-(18+1+10+1+14)+42=2518
VEDAN=(22*5*4*1*14)-(22+5+4+1+14)+40=6154

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SURAJIT KUNDU   10 years AGO

V=22
E=5
D=4
A=1
N=14
NOW 22*5*4*1*14=6160
SINCE, NUMBER WILL BE = 6160-6=6154

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KUNDU   10 years AGO

V=22
E=5
D=4
A=1
N=14
NOW, 22*5*4*1*14=6160
SINCE, NUMBER WILL BE= 6160-6=6154
SO, 8> 6154 is ans

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vadthyavath   10 years AGO

ARJUN=1*18*10*21*14=52920
now subtract sum of odd numbers from total
52920-(1+21)=52898
similarly,
VEDAN=22*5*4*1*14=6160-(5+1)=6154

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santosh kumar   10 years AGO

according to Gaurav...

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T.VIGNESWARA REDDY   10 years AGO

1*18*10*21*14=52920 (-22)
7*1*21*18*22=58212 (-30)
22*5*4*1*14=65160 (-6)

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Aravinth kumar   10 years AGO

ARJUN (Multiplication of all letters by this number) =52920 -22 =52898
so,
VEDAN = 6154

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pooja chavan   10 years AGO

arjun=product of numeric equivalent of alphabet=52920-(vowels)
=52920-22=52898
so for vedan=6160-6=6154

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Vignesh   10 years AGO

option 8

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Lakshmi Narmada   10 years AGO

6154

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raj ranjan verma   10 years AGO

A(1), B(2), C(3), D(4), E(5), F(6), G(7), H(8), I(9), J(10), K(11), L(12), M(13), N(14), O(15), P(16), Q(17), R(18), S(19), T(20), U(21), V(22), W(23), X(24), Y(25) ,Z(26)
Code is obtained as follow
multiply the corresponding no. of the alphabets and then subtract the vowels from it
like
ARJUN=[1(A)*18(R)*10(J)*21(U)*14(N)]-[1(A)+21(U)]=52898
SIMILARLY
VEDAN=(22*5*4*1*14)-(5+1)=6154

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gouthamdaneti   10 years AGO

by giving values to A to Z
multiply each value of the letter in the names u get value
for vedan the value is 6160 the nearest answer is 6154

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Boby yadav   10 years AGO

ARJUN=(A*R*J*U*N)-((A+R+J+U+N)-42)=(1*18*10*21*14)-((1+18+10+21+14)-42)=52920-(64-42)=52898
GAURAV=(58212)-(70-40)=58182
RAJAN=2520-(44-42)=2518
VEDAN=6160-(46-40)=6154

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Arijit Acharyya   10 years AGO

A(1),B(2),C(3),D(4),E(5),F(6),G(7),H(8),I(9),J(10),K(11),L(12),M(13),N(14),O(15),P(16),Q(17),R(18),S(19),T(20),U(21),V(22),W(23),X(24),Y(25),Z(26)

now , now multiply numbers according to english letters-(addition of odd numbers)
A(1) R(18) J(10) U(21) N(14)=(1*18*10*21*14)-(1+21)=52920-22=58182
G(7) A(1)U(21)R(18)A(1)V(22)=(7*1*21*18*1*22)-(7+1+21+1)=58212-30=58182
R(18) A(1)J(10)A(1)N(14)=(18*1*10*1*14)-(1+1)=2520-2=2518
& V(22)E(5)D(4)A(1)N(14)=(22*5*4*1*14)-(5+1)=6160-6=6154
option 8)

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shree   10 years AGO

6160-6=6154

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NIRUPOM GHOSH   10 years AGO

VEDAN multiply.....and then substract with vowels letters.

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Dark Knight   10 years AGO

Multiplying all the character value and then minus the value which is given doing that we will get the closest answer which is option 8

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sudipta maji   10 years AGO

A(1) R(18) J(10) U(21) N(14)=(1*18*10*21*14)-(1+21)=52920-22=58182
G(7) A(1)U(21)R(18)A(1)V(22)=(7*1*21*18*1*22)-(7+1+21+1)=58212-30=58182
R(18) A(1)J(10)A(1)N(14)=(18*1*10*1*14)-(1+1)=2520-2=2518
& V(22)E(5)D(4)A(1)N(14)=(22*5*4*1*14)-(5+1)=6160-6=6154

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aditya wargis   10 years AGO

multiply the position of each letter then we will get first two digit of the number,i.e ARJUN=1*18*10*21*14=52920-22=52898,similarly we can find the first two digit of the remaining code

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Dinesh thatti   10 years AGO

multiply respective numbers of integers and subtract odd numbers

a r j u n = 52920 after subtraction we get 52898

similarly
V E D A N = 6160 after subtraction we get 6154

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surbala   10 years AGO

eeee

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GOWRABATHUNI RAJESH   10 years AGO

Answer is 6154

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Ravi Bhalani   10 years AGO

Multiplication of digits minus some of vowels
where a-1,b-2,..,z-26

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Varunraj Reddy   10 years AGO

ARJUN = 52898
ARJUN=(1*18*10*21*14)-(1+21)=52920-22=52898
Similarly
VEDAN=(22*5*4*1*14)-(5+1)=6160-6=6154

Option 8)

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MRITUNJAY KUMAR   10 years AGO

V E D A N= 22*5*4*14-(5+1)=6154
22 5 4 1 14
OPTION 8)

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guddu   10 years AGO

multiply all no.and subtract sum of odd nomber which is given in the leter
ARJUN=1*18*10*21*14=52920-(21+1)=52898
GAURAV=7*1*21*18*1*22=58212-(7+1+21+1)=58182
RAJAN=18*1*10*1*14=2520-(1+1)=2518
VEDAN=22*5*4*1*14=6160-(5+1)=6154

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Asha Praveena   10 years AGO

Multiply all the letter numbers and subtract number.
Then we get the answer

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KALAIARASI   10 years AGO

we consider VEDAN as V*E*D*A*N
and, V is 22nd letter in alphabet,E is 5th and so on.

now, we calculate 22*5*4*1*14=6160
and we have to take sum of the numbers which are in odd place
i.e.,5+1=4

now we have to subtract 4 from 6160

now we get absolutely correct ans 6154

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