The side of a square exceeds the side of another square by 4 cm and the sum of the area of the two s

YUVAN SATHAIAH   10 years AGO

side of the smaller square is x cm
side of the larger square=(x+4)cm
Area of the smaller square+Area of the larger square=400 cm^2
x^2+(x+4)^2=400
x^2+x^2+8x+16=400
2x^2+8x-384=0
x^2+4x-192=0
x^2+16x-12x-192=0
x(x+16)-12(x+16)=0
(x+16)(x-12)=0
x+16=0 or x-12=0
x=-16 or x=12
x=12
side of the smaller square is 12cm
side of the larger square=(4+12)=16cm

option is 5)12cm,16cm

Like? Yes (8) | No (4)  

S.SHAFI   10 years AGO

Let the side of the smaller square be x cm.

Side of the larger square = Side of the smaller square + 4 cm

∴ Side of the larger square = (x + 4) cm

Given, Area of the smaller square + Area of the larger square = 400 cm2

x^2 + (x+4)^2 = 400

by solving we get x=12

Side of the smaller square = 12 cm

Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm

Like? Yes (5) | No (2)  

madanpal vishwakarma    10 years AGO

let assume that the side of first square is x then second square side is (x+4)

so according to question

x^2+(x+4)^2=400

x^2+(x^2+8x+16)=400

so
2x^2+8x=384

x^2+4x-192=0

after solving we get
x=12,x=16

so option 5 is correct.
12^2+(12+4)^2=400

Like? Yes (4) | No (1)  

rajesh   10 years AGO

square=x say
another sqaure=x+4
x^2+(x+4)^2=400
then x=12,16

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

let side of 1st sq. = x
side of 2nd sq. = x+4

x^2 + (x+4)^2 = 400
x= 12, -16

so, sides = 12, 16

Like? Yes (1) | No   

shaiffali Aggarwal   10 years AGO

let the side of first square is x
n another is x+4
x^2 + (x+4)^2= 400
by solving we get x=12

Like? Yes (1) | No   

Sunku Mounika   10 years AGO

Side of the another square is X.Then side of the first square is X+4.
Then sum of the areas of the squares=400
i.e. 2x^2+4x-192=0
By solving the equation we get x=12.
The another square side is 16.
So, ans is 12 and 16.

Like? Yes (1) | No   

Krsihna Prasad   10 years AGO

Area of square =l^2
12*12+16*16=400

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kiruthika   10 years AGO

Let the side of the smaller square be x cm.

Side of the larger square = Side of the smaller square + 4 cm

∴ Side of the larger square = (x + 4) cm

Given, Area of the smaller square + Area of the larger square = 400 cm2

x^2+(x+4)^2=400
x^2+x^2+8x+16-400=0
2x^2+8x+384=0 div by 2
x^2+4x-196=0
==> x= -16 , 12
x=12 and x+4= 16
so the ans is x= 12 ,16 option 5

Like? Yes (1) | No   

Manikumar R   10 years AGO

14^2+16^2=400

Like? Yes (1) | No   

MD SOHAIL AKHTER   10 years AGO

let the side of one square be 'x'
the side of other square= x+4

A/Q
x^2+(x+4)^2=400

on solving for x, we get;
x=12
x+4= 16

so the correct option is (5)

Like? Yes (1) | No   

TRIMURTULU   10 years AGO

first square area=a
next square area=4+a
sum of areas=a^2+16+a^2+8a=400
solve
a=12
b=a+4=16

Like? Yes (1) | No   

akansha   10 years AGO

let the sides of d 2 squares be x and (x+4)
now x^2 + (x+4)^2 = 400 (given)
solving this,we get
x=12 and x+4 as 16

Like? Yes (1) | No   

virendra dubey   10 years AGO

let side1=x hence side2=x+4;
hence x^2+(x+4)^2=400;
so x=12 x+4=12+4=16
so ans=12cm,16cm

Like? Yes (2) | No (1)  

Soumya   10 years AGO

let smaller square be Xcm
larger square is (X+4)cm
given sum of both squares is 400 sq.cm
i.e.,X^2+(X+4)^2=400
X^2+X^2+16+8X=400
=> 2X^2+8X-384=0
=> X^2+4X-192=0
=> X^2+16X-12x-192=0
=> X(X+16)-12(X+16)=0
=> (X+16)(X-12)=0
so X=-16(but we can't take negative value for area) X=16,12.

Like? Yes (1) | No   

Mahalakshmi   10 years AGO

let area of first square be x^2
area of second square be (x+4)^2
from question we form equation x^2 + (x+4)^2 =400
solving it we get x=12 so another square exceed by 4 so its values is 16
so option 5)12,16

Like? Yes (1) | No   

Pallekonda Rajesh   10 years AGO

area of one square=a^2
area of another square=(a+4)^2
so a^2+(a+4)^2=400 if we solve this equation
we will get a=12,and another 12+4=16
12cm,16cm

Like? Yes (1) | No   

abhilasha   10 years AGO

a-b =4
a^2 + b^2 = 400
a = 12, b = 16

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

If side of one square=x, then
Side of another square=x+4
Given x^2+(x+4)^2=400
x^2+4x-192=0
(x+16)(x-12)=0
x=12
Side of another square=x+4=12+4=16

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Jigyasa Kumar   10 years AGO

a-b =4
a^2 + b^2 = 400
a = 12, b = 16

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Aarush Singh   10 years AGO

a-b =4
a^2 + b^2 = 400
a = 12, b = 16

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Rahul Das   10 years AGO

in this option only 5 option has total area 400
12^2+16^2=400

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sadhikbhasha   10 years AGO

Let the side of the smaller square be x cm.

Side of the larger square = Side of the smaller square + 4 cm

∴ Side of the larger square = (x + 4) cm

Given, Area of the smaller square + Area of the larger square = 400 cm2



Side of the smaller square = 12 cm

Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm

Like? Yes (1) | No   

azharshahid01@gmail.com   10 years AGO

Suppose side of first square is x then side of another square is x+4.
According to question (x)^2+(x+4)^2=400.
On solving above equation x=12.
Sides of squares are x and x+4,
So side of squares are 12 and 16 cm.

Like? Yes (1) | No   

jairaj   10 years AGO

area of a square =a^2,
if the side of the square is exceeds by 4cm then side of the square is =a+4 cm
then area of square is =(a+4)^2
sum of the area of the two squares =
(a^2)+(a+4)^2=400
by solve the above eq,we can get 12,16cm

Like? Yes (1) | No   

ravi   10 years AGO

side=x & x+4

sum of areas=x^2+x^2+2x+16=400

solving we get x=12
sides=12 & 16

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Dinesh thatti   10 years AGO

Let the side of the smaller square be x cm.

Side of the larger square = Side of the smaller square + 4 cm

Side of the larger square = (x + 4) cm

Given, Area of the smaller square + Area of the larger square = 400 cm2

Side of the smaller square = 12 cm

Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm

so answer is 12cm,16cm

Like? Yes (1) | No   

Varunraj Reddy   10 years AGO

By the given conditions the equation becomes
a^2+(a+4)^2=400 sq.cm.
by solving we get a=12cm,16cm
option 5.

Like? Yes (1) | No   

anubhav verma   10 years AGO

X^2+(X+4)^2=400
X
X+4
AREA
X^2
(X+4)^2
2*X^2+8X-384=0
X^2+4X-192=0
(X-12)*(X+16)=0
X=12
ANS...1)12
2)12+4=16

Like? Yes (1) | No   

J.DHANDAPANI   10 years AGO

Let the side of a square be x.Then the side of another square is (X+4).
SO,by data,x^2+(X+4)^2=400,
Solving the quadratic equation we get,x=4.
so,the dimensions are 12cm &16cm

Like? Yes (1) | No   

SHEREENA NISHAD   10 years AGO

take x and x+4 as sides of squares
sum of area = x^2 + (x+4)^2 = 400
2x^2 + 8x + 16 = 400
x= -16 & 12
So Ans x=12
sides of squares 12cm and 16cm

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DHIRENDRA    10 years AGO

12^2+16^2=144+256=400

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Rajasekhar Reddy   10 years AGO

let the side of square be x cm
then the side of another square be x+4 cm
the sum of the areas of the two squares is 400 cm^2
x^2 + (X+4)^2 = 400

by solving we get x = 12
by adding 4 we get x = 16

Like? Yes (1) | No   

Saidinesh   10 years AGO

x^2+(x+4)^2=400;
solving x =12,16

Like? Yes (1) | No   

ashish kumar   10 years AGO

let x,x+4 is the side of 2 square.
x^2+(x+4)^2=400
by solving or by checking with the options
12^2+16^2=400

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rakesh   10 years AGO

there is only one option which gives sum of the squres as 400

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naveen reddy   10 years AGO

option 5=>12^2+16^2=400

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Prabhat Yadav   10 years AGO

Ans is 5

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VIMALRAJ V   10 years AGO

side of 1st square=X
Side of 2nd square=X+4
Sum of square of area=400
i.e. (X^2)+((X+4)^2)=400
X^2+X^2+16+8X=400
2X^2+8X+16=400
on simplify
X=-16 & X=12 since X can't be negative
Therefore X=12
side of 2nd square=X+4=12+4=16
Therefore dimensions are 12cm and 16cm.

Like? Yes (1) | No   

sirisha aryasomayajulu   10 years AGO

let the side of first square be 's'.hence the side of second square becomes 's+4'.
given that s^2+(s+4)^2=400
solving the equation,we get the final equation as follows:
s^2+4s-192=0
using the formula for solving equations we get
s=12,s+4=16

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Gayathri   10 years AGO

x^2+(x+4)^2=400
By solving the above equation,we get
2x^2+8x-384=0
Further solving,
x=12,-16not considered
s0 take 12as answer

Like? Yes (1) | No   

AMIT KUMAR   10 years AGO

let side of square=xcm
other square=x-4cm
a/c question,
x^2+(x-4)^2=400
2x^2-8x=386
x^2-4x=193
x=16.03
other square=12.03
dimension=root2*side=root2*12.03=17(approx)
root2*side=root2*16.03=22(approx)

Like? Yes (1) | No   

meghana   10 years AGO

let sq1 and sq2 as square1,square2.
assume sq1 side =a
then sq2 side=4+a.
given that area of sq1 and sq2 is 400.
area of square = side^2
so,a^2+(4+a)^2=400
solve above equation : a=12
that means side of sq1 = 12 cm
side of sq2=4+a=4+12 =16 cm

Like? Yes (1) | No   

DHAKAD NEETENDRA SINGH   10 years AGO

let I square has side x cm
and II has x+4 cm
according to question,
x^2+(x+4)^2=400
x= 12,16 ans...

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Vikram Saini   10 years AGO

a^2+(a+4)^2=400
solving it we get
a=12
and b=a+4=16
so answr is 12,16

Like? Yes (1) | No   

modem mounika   10 years AGO

area of 1st square=x*x
area of 2nd square=(x+4)*(x+4)
so
x^2+(x+4)^2=400
then X is 12
so
12 and 16 are correct

Like? Yes (1) | No   

RAJ KAMAL   10 years AGO

a^2+(a+4)^2=400
where a is the side of one of the squares..............
and(a+4)is the side of another............
solving this eqn would yield a=12 and (a+4)=16................the required answer

Like? Yes (1) | No   

Gnanaprakash S   10 years AGO

The side of the is increased by 4cm.
x^2+(x+4)^2=400.
After solving this equation we get x+2=14
then x=12,x+4=16
SO,option 5)12cm,16cm

Like? Yes (1) | No   

deepak kumar   10 years AGO

normal quadratic equation.

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ashish kumar singh   10 years AGO

it can be easily solved by the given options, as sum of area of squares is 400,
then to satisfy x*x+y*y=400
and only one can satisfy this equation by put x=12 an y=16,
12*12=144 and 16*16=276
276+144=400.
thus answer is 12 and 16cm

Like? Yes (1) | No   

NIDHI MEHLA   10 years AGO

x^2 +(x+4)^2 = 400
solving for value of x we get x = 12 and -16
thus x = 12 neglecting -16.
hence x=12 and x+4=16

Like? Yes (1) | No   

irfan alam   10 years AGO

let 1st square side is x , and second\'s side is x-4
by given values

x*x + (x-4)(x-4)=400
on solving we get solution for x & x-4

Like? Yes (1) | No   

Kowshik Sarker   10 years AGO

let the side of the first square is (x+4) and second one is x.So the equation becomes...
(x+4)^2+x^2=400
solving this we get x^2+4x-192=0
from this we get x=12 and x=-16
so sides will be 12cm and 16cm.

Like? Yes (1) | No   

Hemalatha   10 years AGO

on solving.
a^2+4a-199=0

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ARJYA HALDER   10 years AGO

let, the side of smaller square is x.
So, the side of the bigger square is (x+4).
From question, x^2+(x+4)^2=400
Solving we get, x=12,-16.
Magnitude of side cannot be in negative.
So, x=12.
So, the dimensions of two squares are 12cm & 16cm.

Like? Yes (1) | No   

VIKASH RAY   10 years AGO

Let, the side of one square be- x cm
then the side of another square is (x-4) cm
then according to the given question ,
x^2+(x-4)^2=400
by solving this we get that option 5 is correct.

Like? Yes (1) | No   

P.Selva Dhasni   10 years AGO

area(x)+area(x+4)=400
x^2+(x+4)^2=400
(x-12)(x+16)=0
x=12,-16
so, dimensions are 12,16.

Like? Yes (1) | No   

SONU GUPTA   10 years AGO

Let the side of the smaller square be x cm.
Side of the larger square = Side of the smaller square + 4 cm
∴ Side of the larger square = (x + 4) cm
Given, Area of the smaller square + Area of the larger square = 400 cm2

Side of the smaller square = 12 cm
Side of the larger square = (x + 4) cm = (12 + 4) cm = 16 cm

Like? Yes (1) | No   

santhosh   10 years AGO

let the sides of the square are x,x+4
given x^2+(x+4)^2=400 => x=12
so other square side is 16cm

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vishnuvardhan   10 years AGO

x^2+(x+4)^2=400 (assume side of one square as x and another x+4)
x^2+x^2+8x+16=400
x^2+4x-192=0
x=12,-16
as side of square is always positive x=12
sides of squares are 12,16

Like? Yes (1) | No   

karthik hariharan   10 years AGO

square area formula is a^2
so here the 5th option is suitable for the answer that is 400sq cm

Like? Yes (1) | No   

Vivek Jain   10 years AGO

let sides be a and a+4;
so a^2 + (a+4)^2=400
a^2+4a-192=0
so a=12,-16
a=12 onlyhence other side will ve a+4=12+4=16
so option 5)12cm,16cm

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Rajat Goyal   10 years AGO

Clear from option.

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Sandeep Negi   10 years AGO

on justifying. .. x=12 other y=16

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Parthi Smith   10 years AGO

(a^2)+[(a+4)^2]=400
therefore,(a^2)+4a-192=0
a=12

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C.Aarthi   10 years AGO

x^2 + (x+4)^2 =400
2X^2 + 8x + 16=400
2X^2 + 8x - 384=0
x^2 + 4x - 192=0
x=12 & -16
x=12
sides=12 and 16 (option 5)

Like? Yes (1) | No   

srujana aitha   10 years AGO

consider side of square as x then
x^2+(x+4)^2=400
solving that x=12
so square sides are 12,12+4

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Komala.G   10 years AGO

Option (5)
assume side of square as b
The sum of the area of the two squares = area of 1st square + area of 2nd square
400 = b^2 + (b+4)^2
400 = b^2 + (b^2+16+8b)
400-16 = 2b^2 + 8b
384 = 2b^2 + 8b ------divide by 2
192 = b^2 + 4b
b^2+4b-192 = 0
b^2+16b-12b-192 = 0
b(b+16)-12(b+16) = 0
(b-12) (b+16) = 0
b = 12, -16

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mohd zakir   10 years AGO

X^2+4X-192=0

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Anucia Mary A   10 years AGO

12 square is 144
16 square is 256
the total of the square is 400
satisfies the condition
the difference between sides of the 2 squares are 4
so answer is option 5)12cm,16cm

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Greeshma Varghese   10 years AGO

let the side be x..then side of next square s (x+4)^2
x^2+x^2+8x+16=400
x^2+4x+8=200
by solving x=12...x+4=16

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Ghanshyam Gulati   10 years AGO

a^+(a+4)^2=400

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Snehasis   10 years AGO

Side of the first square is x then other should be x+4
Therefore, x^2+(x+4)^2 = 400
After solving,
x=12 and x=-16
A side of a square cannot be negative therefore x=12 then the other side is 16.

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vijay   10 years AGO

verify options s^2+4s+8=200.we get 200

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Abhishek   10 years AGO

let the side of first square be x cm
so next sqare having dimension=(x+4)

According to question
x^2+(x+4)^2=400
x^2+x^2+8x+16=400
x^2+4x-192=0
(x+16)(x-12)=0
so,x=-16,12
since,side of square can never be negative
hence,x=12 cm
and x+4=12+4=16 cm

so correct answer is option no.5

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Jaydeep Gupta   10 years AGO

x^2 + (x+4)^2 =400
by solving,we get x=12
and condition is satisfied with 12 and 16

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SaiKiranyaLakshmi   10 years AGO

area of a square=side*side
so
(12*!2)+(16*16)=400

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Udayan N Kothari   10 years AGO

Let x= 12 then x + 4 = 16

Now,

12^2 + 16^2 = 400
144 + 256 = 400
So, option 5 is correct.

Like? Yes (1) | No (1)  

Surya Narayana K   10 years AGO

Answer : 12cm and 16cm

Consider side of first square as x cm
then side of another square is (x+4) cm.

Sum of the area of the two squares is 400.i.e.,
x^2+(x+4)^2=400
=>x^2+x^2+8x+16-400=0
=>2x^2+8x-384=0
=>x^2+4x-192=0
=>(x-12)(x-16)=0
=>x=12,16

So ans is 12cm,16cm (Option 5).

Like? Yes (2) | No (2)  

ASHISH MITTAL   10 years AGO

x^2+(x+4)^2=400
2x^2+8x+16=400
x^2+4x-192=0
after solving we get x=16 and 12

Like? Yes (1) | No (1)  

SID PRASANTH KUMAR   10 years AGO

side of first square x and area x^2
side of second square x+4 and area (x+4)^2

sum of area's x^2 + (x^2+4^2+8x)=400
x will be 12 and x+4 will be 12+4=16

Like? Yes (1) | No (1)