How many combinations are possible if 3 one rupee coin, 4 fifty paise coin and 2 twenty five paise c

M4maths Previous Puzzles

23 Apr 2014 Solve

How many combinations are possible if 3 one rupee coin, 4 fifty paise coin and 2 twenty five paise coin are available. It is compulsory to select any one of the coin

OPtion

1) 23
2) 24
3) 59
4) 55
5) 60
6) 26
7) 12
8) 9
9) 6
10)None of these

Solution

Out of 3 one rupee coin, total possible combinations are
0 one rupee coin, 1 one rupee coin,
2 one rupee coin, 3 one rupee coin,
Out of 4 fifty paise coin, total possible combinations are
0 fifty paise coin, 1 fifty paise coin, 2 fifty paise coin, 3 fifty paise coin, 4 fifty paise coin,
Similarly out of 2 twenty five paise coin, total possible combinations are
0 twenty five paise coin, 1 twenty five paise coin, 2 twenty five paise coin,
Therefore total number of methods = 4*5*3 – 1= 60-1 = 59
(1 case is deducted because in a case no coin is selected)

Correct Option: 3 Best Solution (11)

Ann Theressa   10 years AGO

Number of ways in which atleast one object may be selected out of 'p' alike objects of one type and 'q' alike objects of second type and 'r' alike objects of 3rd type is,

(p+1)*(q+1)*(r+1)-1 = (2+1)*(3+1)*(4+1) - 1
=3*4*5 - 1
=60-1
=59

Like? Yes (6) | No (3)  

Pargat Pal Singh   10 years AGO

4*5*3-1=60-1=59 combinations

Like? Yes (4) | No (2)  

llamar   10 years AGO

4*3*2+4*3+4*2+3*2+4+3+2=24+12+8+6+9=59

Like? Yes (1) | No   

Aman   10 years AGO

Total possible combinations from
000 to 342 will be 4*5*3=60.
But 000 is not permitted as It is compulsory to select any one of the coin .
so possible combinations = 60-1=59

Like? Yes (3) | No (2)  

RAKESH   10 years AGO

(3+1)*(4+1)*(2+1)-1
=59

Like? Yes (2) | No (1)  

harshal agrawal   10 years AGO

(1,0,0),(1,0,1),(1,0,2)
(2,0,0),(2,0,1),(2,0,2)
(3,0,0),(3,0,1),(3,0,2) 9 cases
similarly with 1,2,3,4 coins from 50 pse, and 0,1,2 from 25 pse , (4*9) = 36 more cases
total becomes 45
now if 0 coin drawn from one ruppee,
i.e. 15 more caese. but (0,0,0) not allowed.
hence 45+14 = 59 cases.

Like? Yes (2) | No (2)  

Keshav Kishlay   10 years AGO

Total possible combinations = (3+1)*(4+1)*(2+1)=60
But It is compulsory to select any one of the coin.
so 0 one rupee coin, 0 fifty paise coin and 0 twenty five paise coin selection is not allowed.
so desired combinations = 60-1=59

Like? Yes (1) | No (1)  

shree   10 years AGO

Total possible combinations = (3+1)*(4+1)*(2+1)=60
But It is compulsory to select any one of the coin.
so 0 one rupee coin, 0 fifty paise coin and 0 twenty five paise coin selection is not allowed.
so desired combinations = 60-1=59

Like? Yes (1) | No (1)  

Pallab Das   10 years AGO

total possible combination = (3+1)*(4+1)*(2+1)=60
But It is compulsory to select any one of the coin

so 60-1=59

Like? Yes (1) | No (1)  

steffy edmond   10 years AGO

Number of ways in which atleast one object may be selected out of 'p' alike objects of one type and 'q' alike objects of second type and 'r' alike objects of 3rd type is,
(p+1)*(q+1)*(r+1)-1 = (2+1)*(3+1)*(4+1) - 1
= 3*4*5 - 1
= 60-1
= 59

Like? Yes (1) | No (2)  

RANA MONDAL   10 years AGO

total combination is...
=(4+3+2)+{(4*3)+(3*2)+(4*2)}+(4*3*2)
=9+26+24
=59

Like? Yes (1) | No (3)