Two train, Each 80 m long, passes each other on parallel lines. If they are going in same direction, the faster train takes one minute to pass the other completely. If they are going in the opposite directions, they over take each other in three second. Find the rate of each train in meter per second.

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30 Apr 2014 Time, Distance and Speed Two train, Each 80 m long, passes each other on parallel lines. If they are going in same direction, the faster train takes one minute to pass the other completely. If they are going in the opposite directions, they over take each other in three second. Find the rate of each train in meter per second.: OPtion
1) 28 m/sec, 76/3 m/sec
2) 25 m/sec, 76/3 m/sec
3) 27 m/sec, 25 m/sec
4) 26 m/sec, 77/3 m/sec
5) 29 m/sec, 28 m/sec
6) 28 m/sec, 25 m/sec
7) 28 m/sec, 101/4 m/sec
8) 35 m/sec, 30 m/sec
9) 38 m/sec, 28 m/sec
10)None of these; Correct Option: 1 Best Solution (15)

Ann Theressa 10 years AGO

Let the speed of trains be x and y
distance d = 80+80 = 160

speed = distance/time
x-y = 160/60 ---(1)
x+y = 160/3 ---(2)

(1) + (2)
2x = 56
x = 28m/sec

y = 76/3 m/sec

Like? Yes (23) | No (8)

nirmal kumar saini 10 years AGO

let first train speed=v1;
and second train speed=v2;
so when these are going in one direction the resultant speed is=v1+v2;
and when going in opposite direction the resultant speed=v1-v2;
so in first condition equation is:-
d/v1+v2=60; .............(1)
and in second condition equation is:-
d/v1-v2=3; .............(2)
solving both of equation we get
v1=28 m/sec; and
v2=76/3 m/sec;ans

Like? Yes (14) | No (7)

Purosotam Gupta 10 years AGO

let
the speed of one train=x
speed of second train=y
then
the question
x-y=160/60........equ 1
x+y=160/3.......equ 2
then from 1 and 2
x=28 m/s
y=76/3 m/s

Like? Yes (6) | No (2)

indrajeet yadav 10 years AGO

let both trains speed=u and v m/sec
according to question
160/u-v=60........(1)
160/u+v=3.........(2)
solve both equation
u=28 m/sec
v=76/3 m/sec

Like? Yes (5) | No (2)

PAWAN KUMAR 10 years AGO

Let speed of trains be x,y m/sec
now, (x-y)=160/60=8/3 m/sec
and (x+y)=160/3 m/sec
hence, x=28 & y=76/3 m/sec.

Like? Yes (4) | No (3)

MD SOHAIL AKHTER 10 years AGO

let the speed of two trains be x and y (m/sec)

A/Q
160/(y-x)=60........... (1)
and
160/(y+x)=3...............(2)

on solving (1) & (2), we get
x=76/3m/sec
y=28 m/sec
ans- option 1

Like? Yes (4) | No (5)

Udhaya kumar 10 years AGO

160/(x-y)=60
160/(x+y)=3
by solving this we get x=28 , y=76/3.....

Like? Yes (4) | No (5)

KALIA MUDULI 10 years AGO

Let speed of first and second train are S1 and S2.
Given that:lenght of train are 80 m each
1 min=60 sec

according to the first condition:
60=(80+80)/(S1-S2)
S1-S2=8/3 ...........(1)

and according to second condtion:
3=(80+80)/(S1+S2)
S1+S2=160/3 ............(2)

by solving both eque (1)&(2)
we get....

S1=28 m/sec, S2=76/3 m/sec.

Like? Yes (3) | No (5)

Aakash Jain 10 years AGO