In a four digit number all the four digits are different and sum of all digits is 27. In the number 3 & 4 are not present. Ten's and unit's digits are least and greatest digits of the given number respectively; Sum of all possible results will be
All the four digits are different and sum of all digits is 27 so 0, 1, 2 can not be taken as digits. 3 & 4 are not present as given so available digit are
5, 6, 7, 8, 9
Only 5+6+7+9 = 27
So 8 will be rejected
now according to given condition last two digits are least & greatest of the number so last two digits are 5 & 9 possible no are
6759 + 7659 = 14418