A railway half ticket costs half the full fare but the reservation charge is the same on half ticket

Kushagra Tiwari   10 years AGO

Let the reservation charge be x rs
and the first class charge for full ticket be y rs

then x+y = 362

and y + (2x1/2)y + 2x=554
3y/2 + 2x =554
therefore 3y+4x = 1108
and 4y+4x = 1448

therefore y =Rs 340

and x = 362-340
= 22
which is in the 9th option

Like? Yes (54) | No (20)  

Pranoy Bej   10 years AGO

Let cost full ticket = 2x and reservation cost = y
then 2x+y = 632-----------------(i)
3x+2y=554------------------(ii)
solving equations y= 22

Like? Yes (24) | No (10)  

jitendra varshney   10 years AGO

let reservation charges be x,
and first class charge for full ticket be rs. y
so x+y=362,.................(i)
1+1/2y+2x=554,
3y/2+2x=554,
3y+4x=1108,...............(ii)
and from equation 1
4y+4x=1448,
y=340,
x=362-340,
x=22 ans so option 9 is correct

Like? Yes (13) | No (3)  

pawan kumar   10 years AGO

let..full fare =Rs. X and reservation charge = Rs. Y
so X+Y=362 and X+(X/2)+2Y=554
Solving these two equations we get
Y=22
i.e., Reseration charge= Rs.22

Like? Yes (11) | No (5)  

Mahesh   10 years AGO

Let the cost of full ticket be 2x and that of half ticket is x.
The reservation charges be y.
In the first case 2x+y=362
in the second case 2x+y+x+y=554
two times the second equation is 6x+4y=1108
Three times the first equation is 6x+3y=1086
Subtracting the second equation from the first one,
y=1108-1086=22
eservation charges are Rs.22

Like? Yes (9) | No (4)  

Abhishek Vishwakarma   10 years AGO

Let reservation charge be x rs
and the first class charge for full ticket be y rs

then x+y = 362

and y + (2x1/2)y + 2x=554
3y/2 + 2x =554
> 3y+4x = 1108
and 4y+4x = 1448

therefore y =Rs 340

and x = 362-340
= 22

Like? Yes (8) | No (3)  

S.SHAFI   10 years AGO

Full ticket = 362
Ticket Cost = 340
Fare = 22

Half Ticket = Full Ticketcost/2 = 340/2 =170
Fare = 22 is common for full and half tickets...
so total half ticket cost = 170 + 22 =192

Now Full ticket and half ticket = 362 + 192 = 554

Like? Yes (8) | No (3)  

Gourab Dutta   10 years AGO

Reservation charges= y, normal ticket price =x
x+y=362
(x+y)+((x/2)+y)= 554
By solving this two equ we ll get y= 22

Like? Yes (8) | No (4)  

DIPAK TIWARI   10 years AGO

Let X₹ be the reservation charge
So, 362+{(362-X)/2 +(X)}=554
=>362+181-X/2+X=554
=>X/2=11
=>X=₹22
Option 9

Like? Yes (6) | No (2)  

NAVEEN KUMAR   10 years AGO

Let reservation charge=x & first class charge for full ticket=y
then,
x+y=362------------->(1)
& y+(1/2)y+2x=554
or,3y+4x=1108------->(2)
from (1) and (2)
x=22 & y=340 ,hence reservation charge=Rs.22 option(9)

Like? Yes (9) | No (5)  

Prakash   10 years AGO

Let the reservation charge be x and fare be y.
therefore from 1st statement we get -(x+y)=362
from 2nd statement we get -(2x+3/2yy)=554
Solving these 2 questions we get,
x=22

Like? Yes (4) | No   

BITU KUMAR NIRALA   10 years AGO

let y be the fare and x be the reservation charges,
so according to questions,
y+x=362 and----------------------------(1)
(y+x) + (y/2 +x)=554--------------------(2)
operate equation 1 multiplied by 2 and subtract with equation 2 we get,
y=340 and x=22
so,
Answer:-22(option-9)

Like? Yes (6) | No (2)  

Sagar Kumar Subudhi   10 years AGO

Let, x be the reservation charge then

2(192-x)=362-x => 384-2x=362-x => x=22

x=22

Like? Yes (5) | No (1)  

Inline Geek   10 years AGO

suppose full ticket costs x and reservation charge y

then
x+ y = 362
and (x + x/2) + (y + y) = 554

solving both the equation we get y = 22

Like? Yes (5) | No (2)  

swarupa nuggu   10 years AGO

22

Like? Yes (3) | No   

PAWAN KUMAR   10 years AGO

Let the fare be Rs x and reservation charge be Rs y respectively.
Then , x+y = 362
1.5x+2y= 554
on solving the above equations, we get
x= Rs 170 and y = Rs 22 Ans.

Like? Yes (3) | No   

Syed Atamish Ali   10 years AGO

Cost of ticket=x
Cost of reservation=y
for one ticket, x+y=362
for one plus half ticket, (x+y)+ (x/2+y)=554
Solving 2 equations..
y=22..

Like? Yes (5) | No (2)  

RAKESH   10 years AGO

f+r = 362
3f/2 + 2r = 554

solve, r = 22

Like? Yes (5) | No (2)  

Pooja P   10 years AGO

f+r=362
f+f/2+r+r=554
solving these two equation we get r=22
ans=9)

Like? Yes (3) | No   

ANKITA prasad   10 years AGO

H=F/2
F+H+2R=552
F+R=362..SOLVING FOR H, WE GET H+R=192 AND H=170
SO R=22

Like? Yes (3) | No   

Neel Patel   10 years AGO

we can make equesions
x+ y=362. x is price of 1 full ticket
1.5x+2y=554. y is reservation charges
by solvig this we get
x=340 y=22
so Ans is 22

Like? Yes (3) | No   

Gitanjali K   10 years AGO

let reservation charges = x Rs.
for full ticket first class charges = y Rs.

given, x+y=362 .....(1)
y+1/2y+2x=554 ......(2)

solving eq (1) & (2) we get,
y=340 and x=22
therefore option (9) is the answer...

Like? Yes (3) | No   

suganya   10 years AGO

x+r=362
(x+r)+(x/2+r)=554..
to solve.. r=22

Like? Yes (3) | No   

Durgesh Tripathi   10 years AGO

suppose Ticket cost =X and reservation charge=R
then half ticket= X/2+R
Full ticket= X+R
According to given-
X+R=362 ---------------eq1
(X/2+R)+(X+R)=554------eq2
after solving eq1&2 we get the value of R=22

Like? Yes (3) | No   

Mogilipuri.Harish   10 years AGO

x+y =362
and 1 1/2x+2y=554

=>3x+4y=1108

and then
x=340
y=22

ans: 22

Like? Yes (3) | No   

Sudipta   10 years AGO

If Cost of ticket is y and reservation charge is x then,
Y+X=362, 3/2 .Y+2.X=554
Y=340 & X=22

Like? Yes (3) | No   

vartika    10 years AGO

full reserve ticket be x+r
then, half reserve ticket= (x/2)+r
also, (x+r)+(x/2+r)=554
substituting x= r-362 in above equation, we get
r=Rs.22

Like? Yes (3) | No (1)  

sumit   10 years AGO

x+y=362 ---(1)
3x/2 +2y=554 ------(2)
eqn. (2) - 3/2 * eqn (1):
y/2=11
y=22 option(9) ans

Like? Yes (9) | No (7)  

Manikumar R   10 years AGO

x+y=362
y+1/2y+2x=554
3y/2+2x=554
3y+4x=1108
and 4y+4x=1448
y=340
x=362-340=22

Like? Yes (2) | No   

Phani Raaj   10 years AGO

f+r=362
f+r+f/2+r=562
on solving, we get r=22

Like? Yes (4) | No (2)  

Thalamanchi Kishan Kumar   10 years AGO

1 full=362
1 full+ 1 half=554
1 half=554-1 full=554-362=192
check the options one by one
1 full-reservation charge=some value
that some value divided by 2 gives 1 half ticket charge with out reservation charge
if u add this reservation charge the ans should be 192
which ever option satisfies this that is the ans.

Like? Yes (3) | No (1)  

Ajinkya Kulkarni   10 years AGO

Let X be the reservation charge ..

Full fair=362-X

Half fair=(362-X)/2
Reservation charges of a full and a half fair is X+X=2X

So equation becomes
(362-X)+(362-X)/2 + 2X=554
1086+X=1108
X=22

Ans :- Reservation charge is 22.

Like? Yes (3) | No (1)  

murali krishn   10 years AGO

let x be the full fare and y be the reservation charge .
x+y=362
x+y+(x/2)+y=554
by solving these equations u will get reservation charge rs 22.

Like? Yes (3) | No (1)  

Prashant Agrawal   10 years AGO

x+y=362
x+y+x/2+y=554
Solve them.

Like? Yes (2) | No   

Rashmi bharti   10 years AGO

362-x=384-2x
x=22

Like? Yes (2) | No   

nootan singh   10 years AGO

ans is 22.
let x be reservation charges. and y be cost of full ticket
then,
x+y=384---------------i
x+y/2=554-384------ii
so x=22

Like? Yes (2) | No   

Tamal Chakraborty   10 years AGO

[ y+x ] = 362 ;
[ (y+x)+(y/2+x) ] = 554 ;

{where X = reservation charge and Y= charge of full ticket without reservation}

solving these we get x=22
so ans = 22

option 9) 22

Like? Yes (2) | No   

lakshmi nalluri   10 years AGO

x+t=362
x+x/2+2t=554
onsolving above we get,t=22

Like? Yes (3) | No (1)  

Akshay Sheelvant   10 years AGO

resrvatn chrges=x, tckt chrgs=y

x+y=362
2x+y+(y/2)=554

solve the two n u will get x=22

Like? Yes (2) | No   

shubhi garg   10 years AGO

let reservation charges be y and full ticket cost be x then
x+y= 362
x+ y+1/2x+y=554
1/2x+y=192
1/2x=170
x=340
y=22
solving the two equations
y=22 and x=340
thus reservation charges =22

Like? Yes (2) | No   

vikash kumar   10 years AGO

22 is the ans

Like? Yes (2) | No   

Ritesh Kumar   10 years AGO

554-362=192
so half ticket cost 192
full ticket 192*2
reservation charge is 384-362=22

Like? Yes (5) | No (3)  

smita paul   10 years AGO

Let reservation charge=r
cost of full fare=x
half fare=x/2
x+x/2+2r=554--------------(1)
x+r=362-----------------------(2)
solving this we will get r=22

Like? Yes (2) | No   

NISHANT VERMA   10 years AGO

B + R = 362 .......................................... (1)
B + R + B/2 + R = 554 .................................(2)
FROM (1) AND (2)
A = 340 AND R = 22

Like? Yes (2) | No   

Kethineni Vinodh   10 years AGO

Let the Reservation charge be Rs.x and first class full ticket charge for full ticket be Rs.y
i.e.,x+y=362
And y+(y/2)+2x=554=>3y+4x=1108
By solving these two equations we get x=22 and y=340

Like? Yes (2) | No   

surya   10 years AGO

LET X IS TICKET CHARGES AND Y IS RESERVATION CHARGES X+X/2+2Y=554
X+Y=362
SOLVING 1 AND 2 WE GET X=340
Y=362-340=22 IS RESRVATION CHARGES...

Like? Yes (2) | No   

DEEPAK GOSWAMI   10 years AGO

resrvation charge is 22

Like? Yes (2) | No   

Ashish Kumar gupta   10 years AGO

lets say full fare price of one ticket= x rs
and reservation charges= y rs

then according to ques....

( x+y)=362-----(1)
and
(x+y)+(x/2+y)=554---- (2)

on solving both the equation we will get

(1/2*y)=11

ans) y=22;

Like? Yes (2) | No   

Sukanya   10 years AGO

340 + 22= 362(one full ticket)
340+170+22+22=554(one full and one half ticket)

Like? Yes (2) | No   

v pavan   10 years AGO

let reservation charge be Rs. x
Let base charge for a full ticket between two stations is Rs. y
x+y=362
2*x+1.5*y=554
solving above 2 equations we get
x=22,y=340
answer is 22

Like? Yes (2) | No   

ganesh babu   10 years AGO

x+r=362 ----(1)
x+x/2+2r=554
3x+4r=1108----(2)
r=22

Like? Yes (2) | No   

SHUBHAM KUMAR   10 years AGO

x+y=362
3/2x+2y=554
on solving x & y ,we get x=340
y=22

Like? Yes (2) | No   

Ashish Shende   10 years AGO

ans 22

Like? Yes (2) | No   

Anant Bhosale   10 years AGO

let x be full ticket
therefore half ticket
let y be reservtion charges
ATQ
x+y=362
x+y+x/2+y=554
on solving the two equations u get y=22
reservation charges =22
option 9

Like? Yes (2) | No   

Suganya   10 years AGO

2x+y=362
3x+2y=554
solving both we get x=170
y=22
reservation charge is Rs.22

Like? Yes (2) | No   

Manish Singhal   10 years AGO

fare for 1 full ticket=x
reservation charge = y
x+y= 362..... {i}
x+x/2+2y=554 ==> 3x+4y=1108 ... {ii}
solving i and ii
we get .. y=22 and x=340
reservation charge = Rs 22 Ans

Like? Yes (2) | No   

Rohan   10 years AGO

Let half ticket cost =x
Then full ticket cost=2x
Also let reservation charge = y
So, 2x+y=362
And (x+y)+(2x+y)=554 I;e- 3x +2y =554
After solving this we get y= 22 ans

Like? Yes (2) | No   

Ajay Kumar Gupta   10 years AGO

reservation charge a,ticket charge b
so a+b=362

and 2a+b+b/2=554
on solving this equation a=22.
i.e reservation charge=22.

Like? Yes (2) | No   

Piyush   10 years AGO

Let x be the price for full ticket and y be the reservation charges

x+y=362 and 3/2x+2y=554
By solving both the equation we get ans as 22

Like? Yes (2) | No   

Grishma Shah   10 years AGO

Let the full ticket be : f
Reservation charges be: r
Half ticket be : h

As per given:
f+r+h+r=554..........(1)
also, f+r = 362
Hence F = 362-r......(2)

Putting 2 in 1

h + r = 190....(3)

subtracting 3 from 2

f-h=170
f=2h
h = 170
f = 2h = 340
Hence putting value in 3
Reservation charges r = 22

Like? Yes (2) | No   

Tania Chatterjee   10 years AGO

x+y=362....(i)
y+1/2y+2x=554....(ii)
So, solving (i) and (ii)
y=340;x=22

Like? Yes (2) | No   

shree   10 years AGO

170 & 340

Like? Yes (2) | No   

Rahul shaw   10 years AGO

ans. is 22

Like? Yes (1) | No   

Aakash Jain   10 years AGO

Answer is 22

Like? Yes (2) | No (1)  

Tejaswini   10 years AGO

resrv+t=362
2rsrv+t+t/2=554
by solving this we get resrv value 22

Like? Yes (1) | No   

gautam gaurav   10 years AGO

solving x+y=362
and 3x+4y=1108
we get y as 22

Like? Yes (1) | No   

selvakumar   10 years AGO

ans is 22

Like? Yes (1) | No   

sudhakar   10 years AGO

ans is 22

Like? Yes (1) | No   

Ravi Kumar   10 years AGO

let ticket price be t and reservation charge be r then 2 equations will be formed :
t+r=362 (1)
3/2t+2r=554 (2)
solving these two we get r=22.

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

x+y=362
1.5x+2y=552
x=340
y=22

Like? Yes (1) | No   

Tark Patel   10 years AGO

Let the reservation charges will be x Rs. and the first class charge for one full ticket will be y Rs. ,
given > x+y = 362 and y + (1/2)y + 2*x = 554
By solving this we get y = 340 Rs. and x = 22 Rs.
Hence Reservation charges will be 22 Rs.

Like? Yes (1) | No   

amol tarude   10 years AGO

assume ticket fare=x and its charge is y
price of 1 ticket x+y= 362
one full+one half=554
x+y+x/2+y=510
by solving thew two equation
we can get reservation chrge
y=22

Like? Yes (1) | No   

Anvesh   10 years AGO

full charge for single Ticket:362------1
single and half ticket : 554------------2

suppose reservation cost: 22-------3

1-3 340
single ticket 340
half ticket 170
resevation 44 (one and half ticket 22+22 )
---------
554

Like? Yes (2) | No (1)  

Aishwary Rastogi   10 years AGO

full ticket = c;
half ticket = c/2;
reservation charge =r;
c+r=362;
(c+r) +(c/2+r) = 554;
c=340;
r=22 (ans);

Like? Yes (1) | No   

adarshankit   10 years AGO

let x be price of reservation and y be of full reservation.
2x+y+y/2=554
x+y=362
after solving x=22 and y=340

Like? Yes (2) | No (1)  

MOHIT REDDY    10 years AGO

x + y =362
(x + y)+( x/2+y) = 554
solve the 2 equations
y = 22; x=340
x:fare of full ticket
y:reservation fare

Like? Yes (1) | No   

g lokesh   10 years AGO

let assume fare is x,reservation charge is y.
x+y=362
(x+y)+x/2+y=554
by solving we get x=340
y=22
hence reservation charge is 22.

Like? Yes (1) | No   

sujeet kumar   10 years AGO

becoz ful fare+ reservation charges =362
and half fare= 181
so 362+181=543
hence 554-543=11
which is 11+11=22 so option(9)

Like? Yes (1) | No   

Sohidul Islam   10 years AGO

If we take ticket charge x and reservation charge y then we get
x+y=362
x+x/2+2y=554
Solving the 2 equations we get y=22

Like? Yes (1) | No   

sreekanth   10 years AGO

340+170+(2*22)=554
so res charge is 22

Like? Yes (1) | No   

Surit Datta   10 years AGO

for Full ticket 340+22=362
for half ticket 170+22=192
as a total a half and a full ticket is Rs (362+192)=Rs 554
thats it...

Like? Yes (1) | No   

santhosh bachu   10 years AGO

x+y=362
(3/2)x+y=554
y=reservation chargers =22

Like? Yes (1) | No   

Ch Goutham srinivas   10 years AGO

given half = fullticket/2 (with out reservation charge)
full ticket + reservation(R) = 362 and
1(fullticket +R) + 1(halfticket + R) = 554.
now it becomes,
1(362) + 1(halfticket + R) = 554
=> 1(halfticket+R) = 192
given( halfticket = fullticket/2),
so,
1(fullticket/2 +R) = 192
=> fullticket +2R = 384
we no fullticket +R = 362,
so,
=> 362 + R = 384
=> R = 22
ans: 9) Rs.22

Like? Yes (1) | No   

ankit sharma   10 years AGO

let x and be is the ticket fare and reservesation charge respectively..
362=x+y;
554-362=(x/2)+y;
on solving both
x=340and hence y=22
so the ans is 22

Like? Yes (1) | No   

Pranav Bharti   10 years AGO

let full fare =x
half=x/2
let reservation charge =y
so for Ist condition....
x+y=362 and
second.......
x+(x/2)+y=554
solving these we get
y=22

Like? Yes (1) | No   

akriti mishra   10 years AGO

by solving equations:
let reservation charges be y
normal fare charges be x
x+y=362
(3/2)x+2y=554
on solving x=170 and y= 22
rs.22 reservation charges

Like? Yes (1) | No   

rajani   10 years AGO

let full ticket cost=x
and reservation charges =y
then from the data x+y=362,
and x+x/2+2y=554

on solving this we will get y=22 which is the reservation charge.

Like? Yes (1) | No   

ANAND SAKPAL   10 years AGO

R+T=362
R+t/2 = 192
where R is reservation cost and t is cost of ticket
After solving R=22

Like? Yes (1) | No   

Neeraj kumar   10 years AGO

3x/2+2(362-x)equals 554
Where x is the cost of ticket without reservation charge

Like? Yes (1) | No   

Ritankar Das   10 years AGO

Full cost + reservation= Rs. 362
Full cost + reservation + half cost + reservation= Rs. 554
Thus, half cost + reservation= Rs. (554-362) = Rs. 192

Let half cost be Rs. x and reservation cost be Rs. y
Then,
x+y=192
2x+y=362

Thus x= Rs. (362-192)= Rs. 170
y= Rs. (192-170)= Rs. 22

Like? Yes (1) | No   

Soham Ghosh Hazra   10 years AGO

step1: full fare - half fare = 362-554 = 192
let assume,
for full ticket, ticket cost is x and reservation charge is y
so, for half ticket, ticket cost is x/2 and reservation charge is y
step2: x+y=362, x/2+y=192
now x+y-x/2-y=362-192=170
therfore, x/2=170
so y=192-170=22
the reservation charges is 22 (Ans)

Like? Yes (1) | No   

Urvashi Jain   10 years AGO

letfare be x and reaservation charges be y
x+y=362...(1)
x+y+x/2+y=554...(2)
y=22

Like? Yes (1) | No   

yagnik pandya   10 years AGO

We don't know the fair so let us assume that it is x =22
which is option given
Now,
362-x=340 one full ticket without reservation charge
181-x=159 one half ticket without reservation charge
Now difference between 340 -159 is
Which is same as the difference between one half ticket and full ticket as 362-181=181
Hence reservation charge is 22 rupees.
So option 9 is right

Like? Yes (1) | No   

Anshul Kashyap   10 years AGO

full ticket cost + half ticket cost = 554
half ticket cost = 554-362 = 192
actual cost of half ticket = 362/2 = 181
reservation charge = 192-181= 11
total reservation charge = 11+11 = 22

Like? Yes (1) | No   

urvish   10 years AGO

mskclksm

Like? Yes (1) | No   

Shivakumar K Avadhani   10 years AGO

subtract 22 from 362 so that we will get actual price of one person (about full charge) then divide it by 2 so we will get actuall price of half charge then compute with the 554 we will get same answer as after subtracting 22 from 362 i.e 362-22= 340 and 340/2= 170 554-44=510 , 510-170=340 so 22 is the answer....

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

let x be the half ticket charge without reservation charge
y, full ticket charge without reservation charge
r, reservation charge
x= 0.5*y
y+r=362
x+y+2r=554
=> r=22

Like? Yes (1) | No   

vivek   10 years AGO

4x+3(362-x)=554*2...........(362-x=y)
so, x=22

Like? Yes (1) | No   

PRANEETH   10 years AGO

full ticket cost = f
reservation cost = r
half ticket cost = h
then according to the given information
f+r=362
f+r+h+r= 554
362+h+r = 554
h+r = 192
h=f/2
f/2 + r = 192
r=192-(362/2)
r=11

Like? Yes (1) | No   

neha kumari   10 years AGO

x+y=362
x+x/2+2y=554

Like? Yes (1) | No   

Shahrukh   10 years AGO

x+c=362
x+x/2+c=554
c=22

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

Ans 9

Like? Yes (1) | No   

Priyanshi Agarwal   10 years AGO

Full ticket without reservation charge= 362-22=340 therefore, half ticket= 170 since sum of half and full ticket= 554 Hence, 340+170+22+22=554

Like? Yes (1) | No   

anuj gupta   10 years AGO

(362-x)/2+(362-x)+2x=554
on solving----x=22.

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POTHEDAR PRAMODKUMAR   10 years AGO

1.5(362-x)=554-2x
solve for x
we get Rs.22

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Avinash Aryan   10 years AGO

X+y=362,
(x+y)+((x/2)+y)=554
x real charge and y reservation charge
gives y=22.

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gouthamdaneti   10 years AGO

let reservation cost be x;
half ticket without reservation be y;
half ticket cost is 554-362=192;
therefore x+2y=362 & x+y=192;
solving equations we get value of x;

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swetha .k   10 years AGO

x- ticket charge
y- reservation charge
x+y= 362
x+y+x/2+y= 554
solving , x=340 and y =22

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Anshul   10 years AGO

Let one ticket = Rs x
and reservation charges = Rs y
Eq 1 , x + y = 362
Eq 2 , 3x/2 + 2y = 554.
This gives y = Rs 22

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Gundla Bharathi   10 years AGO

let reservation charges be Y and the full tckt price is X+Y and half tckt price is X/2+Y. but given that X+Y=362 and (X+Y)+(X/2+Y)=554 substitute X+Y value in dis u get X value from dat u can get Y value dat is reservation cost

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ADARSH GAURAV   10 years AGO

22 is the answer.

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Sutanu Shit   10 years AGO

assume full ticket price= Rs. x and reservation charge = Rs. r

x + r = 362
x + x/2 + 2r =554

so, r = 22

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RATHINA PRAKASH   10 years AGO

kk

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Vanika   10 years AGO

Let full ticket charge rs.x
and reservation charge rs.y
then x+y = 362
and x+x/2+2y = 554
3x+4y = 1108
solving this y=22

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posirajesh   10 years AGO

As res charges are same
22rs

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rajendra singh   10 years AGO

let,fare of full ticket=x and fare of half ticket=x/2
since reservation charge for both are same. let reservation charge R
then we get x+R=362 and x/2+R+x+R=554
after solving these equations we get value of R equal to 22

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virendra tiwari   10 years AGO

32x+2y=554
3x+4y=1108
we want last digit 8
4*2=8
4*2=28
go to option and check,0nly 22 have 2 so ans 22

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m.kusuma priyanka   10 years AGO

362=x+y
554=2x+[y+y/2]
x=22

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harika challagolla   10 years AGO

given
h=(1/2)f,f+r=362
(f+r)+(h+r)=554
solving for r
r=22

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AMIT SARKAR   10 years AGO

H.T COST WITH RESV. CHG=554-362=192
H.T COST WITH OUT RESV. CHG=362-192=170
RESV. CHG=192-170=22

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ashwani soni   10 years AGO

2 full and 1 half ticket in two ways 362+362+362
or 554+554.
difference gives 22

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padma   10 years AGO

let the ticket cost be = x
half ticket cost be = x/2

reservation charge = same for both
so, since x+r = 362
x= 362-r
x/2+r+362-r= 554
x+724 = 1108
x=1108-724
=>384
so, the reservation charge would be 384-362 = 22

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rajkumar mukherjee   10 years AGO

1 full fare(f)+reservation(r)=362;
1 half(h)+1 f+2 r=554
from this two equation we get .5 f=170 so,full fare=340;
now using equation 1, we get reservation cost=362-340=22;(ans)

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Md.Sultan Khichi   10 years AGO

let x be the charge of reservation and y be the charge of full ticket .
so x+y=362
2x+y+y/2=554
after solving this we get
x=22..
Ans..22

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MP    10 years AGO

One reserved first class ticket for a journey between two stations is Rs. 362(340+22) and one full and one half reserved first class tickets cost Rs. 554 (340*1.5+22*2).

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suman kumar pan   10 years AGO

x+y=362
(x/2+y) + (x+y)=554


y=22

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Aman   10 years AGO

(362-X)*1.5+2X= 554
543+0.5X=554
0.5X= 11
X=22

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sudhanshu kumar   10 years AGO

try to solve using hit and trial method if we calculate 1&1/2 ticket cost using 1 ticket 362 then resv. charge is divided into two part so find using hit and trial method

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RISHABH RAJ   10 years AGO

there will be two eqns x+y = 362 and 3x/2 +2y = 554...solve them to get y = 22

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saira fatma   10 years AGO

y=22

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MOHIT GARG   10 years AGO

F -> Full fair excluding reservation charges.
R -> Reservation charges
F+R = 362
F + R + F/2 + R =554
Solving these two equations we get R=22 and F = 340
hence 22 is the answer

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anandhakumar   10 years AGO

answer is 22

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sujit Reddy   10 years AGO

x+y = 362
x+y+(x/2)+y=554

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arvind khatri   10 years AGO

let x=simplle fare without reservation charge
y=only reservation charge
x+y=362
3/2x+2y=554
so after the solve this equation we will get y =22 rs.

Like? Yes (1) | No (1)