In an examination, it is required to get 36% of maximum marks to pass. A student got 113 marks and w

prem kumar   10 years AGO

pass marks=113+85=198
for 36%=198
for 100%=?
198*100/36=550 marks

Like? Yes (33) | No (5)  

Kushagra Tiwari   10 years AGO

since 36% of x = (113+85) = 198

therefore x = (100*198)/36
that is = 550

which is in 3rd option

Like? Yes (16) | No (4)  

Bhagyashree Bhatt   10 years AGO

Let us assume that the maximum marks for thr examination is x.

Then the equation we get as per simple linear equation:

36% of x = 113 + 85

36x/100 = 198

36x = 19800

x = 19800/36 = 550 marks.

Like? Yes (11) | No   

poojasaisri   10 years AGO

total pass marks=113+85=198
36% marks =198
110%-36%=64%
then 64% marks=(64*198)/36=352
therefore maximum marks=352+198=550

Like? Yes (6) | No   

Shashank Kapoor   10 years AGO

Since the student got 113 marks and was declared failed by 85 marks, therefore minimum passing marks are 113+85=198
this is 36% of total marks so 36/100 * X =198 on solving we get X=550 (X= TOTAL MARKS)

Like? Yes (4) | No (1)  

harini   10 years AGO

let max marks=x
then the min marks required=9x/25
but according to given information 9x/25=113+85=>x=550

Like? Yes (3) | No   

Gitanjali K   10 years AGO

100*198/36=550

Like? Yes (2) | No   

dhanaseelan   10 years AGO

Total marks to get pass is 113+85=198
This is 36 % of total marks
so total marks will be (100/36)*198=550

Like? Yes (2) | No   

NAVEEN KUMAR   10 years AGO

LET MAXIMUM MARKS=X
A/Q
36% 0F X=(113+85)
=>X=550

Like? Yes (3) | No (1)  

shreya sagar   10 years AGO

pass marks=113+85=198
let maxm marks be x.
Then given
36% of x=198
x=(198*100)/36=550

Like? Yes (3) | No (1)  

Abhimanyu kumar   10 years AGO

let max marks be x
pass marks is 36% of max marks =36x/100
student got 113 marks and failed by 85
so 113+85=36x/100
x=550

Like? Yes (2) | No   

Pooja Sandeep Shah   10 years AGO

36% of 550 is 198 which equals 113+85

Like? Yes (2) | No   

Soniya Jain   10 years AGO

113+85=198
36/100×MM=198
MM=198×100/36
MM=550

Like? Yes (2) | No   

Ankit Pandey   10 years AGO

Let us max marks = X
(36/100)X=113+85
X=550

Like? Yes (1) | No   

Kethineni Vinodh   10 years AGO

113+85=198
36%=198 then
100%=550

Like? Yes (1) | No   

ragini   10 years AGO

36% of x=113+85

x=(100*198)/36
x=550

Like? Yes (1) | No   

BHASKAR MANDAL   10 years AGO

he got 113
he is failed by 85
so, if he had got 113+85 = 198 then he would have passed.
given : 36% pass marks

so the total marks for getting 198 as pass marks
= (198/36)*100 = 550

Like? Yes (1) | No   

Aj   10 years AGO

Passing marks=113+85
(36/100)Max=Passing marks
Max=(113+85)*(100/36)
Therefore Max=550

Like? Yes (1) | No   

RAKESH   10 years AGO

(113+85)*100 / 36 = 550

Like? Yes (2) | No (1)  

Neel Patel   10 years AGO

113+85=198
36%-->198
100%-->?
198*100/36=550

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

ans = option 3

Like? Yes (1) | No   

Shreya Tiwari   10 years AGO

since 36% of x = (113+85) = 198

therefore x = (100*198)/36
that is = 550

550 is the ans

Like? Yes (1) | No   

Abhishek Vishwakarma   10 years AGO

since 36% of x = (113+85) = 198

therefore x = (100*198)/36
that is = 550

ans is 550

Like? Yes (1) | No   

poojitha   10 years AGO

36% of x=113+85
x=(100*198)/36
x=550

Like? Yes (1) | No   

Aastha   10 years AGO

given to pass exam 36% required.
113 and fails by 85
so he required 113+85=198 to pass
let x be ma. marks
36*x/100=198
x=550

Like? Yes (5) | No (4)  

shekhar suman   10 years AGO

after getting 113 marks he failed by 85
so passing marks =113+85=198
now, 198=36%of x
thus x=(198*100)/36=550

Like? Yes (1) | No   

Simranjit Singh   10 years AGO

(3) is the correct answer

Let the total marks be x
Pass marks= 0.36*x

The student gets 113 and it is less by 85
So 0.36*x=113+85
=> x=198/0.36= 550

Like? Yes (1) | No   

Arijit Acharyya   10 years AGO

let the maximum marks=x
x*(36/100)=(113+85)
x=550

Like? Yes (1) | No   

Sahana   10 years AGO

36% of 550 is 198

Like? Yes (1) | No   

Deepu Kumar   10 years AGO

A/q
Its is being told that students got 113 marks but failed by 85 marks ..
so total marks that he obtained not to fail is 113+85=198 marks
and percent given to pass is 36%.
so for 1 percent it is 198/36=5.5 marks
so for 100 marks its multiplied by 100 that is 5.5*100=550 marks.

Like? Yes (1) | No   

Vibha   10 years AGO

max marks = (113+85)100/36
= 550

Like? Yes (1) | No   

PAWAN KUMAR   10 years AGO

The min marks to pass the exam = 113+85 = 198.
Let the max marks of the exam be x.
Then, 36% of x = 198
=> 36*x/100 = 198
=> x = 198*100/36 = 11*50 = 550 Ans.

Like? Yes (1) | No   

anupriya sinha   10 years AGO

36%ofx =113+85 =>x = 198*100*/36 => x = 550

Like? Yes (1) | No   

jitendra varshney   10 years AGO

answer is 113+85=198
so198/36*100=550
so option 3 is correct

Like? Yes (2) | No (1)  

Sundar Kumar   10 years AGO

113 + 85 = 198 = 36% of the aggregate marks
Therefore, the aggregate marks = 198 × 100/36 = 550. Ans.
Answer: Option 3)550

Like? Yes (1) | No   

pawan kumar   10 years AGO

36x/100= 198
so, x=550

Like? Yes (1) | No   

Mahendra Jakka   10 years AGO

let x be total marks
36% of x =113+85=198
x=[198*100]/36=550

Like? Yes (1) | No   

santosh kumar patel   10 years AGO

let thr max mark x
then 36% of x=113+85
36x/100=198
x=19800/36
x=550

Like? Yes (1) | No   

sohini maity   10 years AGO

the student requires 85 marks more to pass which is equal to 36% of max marks.so if max marks is x,then
113+85=36% of x
x=550.
so the correct option is 3.

Like? Yes (1) | No   

kumar   10 years AGO

after getting 113 mark fail by 85 mark
mean pass mark= 113+83 =198 marks

pass mark=36% of max mark
mean 36%=198
then 100%=198*100/36=550 mark

Like? Yes (1) | No   

AJAY KUMAR   10 years AGO

let total marks=x
pass marks=(36/100)x
marks obtained by student=113
therefore,
(36/100)x=(113+85)
x=550

Like? Yes (1) | No   

anuj gupta   10 years AGO

113+85=198*100/36==>550

Like? Yes (1) | No   

sahanashree H N   10 years AGO

X-Max marks
Passing marks=X*(36/100)
Passing marks=113+85=198
So substitute the value of passing marks
198=X*(36/100)
X=550

Option 3)

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

550

Like? Yes (1) | No   

shubham tyagi   10 years AGO

let max marks be x
36% of x -85 =113
36% of x=198
x=198*100/36
x=550

Like? Yes (2) | No (1)  

Rahul Kumar Singh   10 years AGO

(113+85)*100/36

Like? Yes (1) | No   

Ashok   10 years AGO

198*100/36

Like? Yes (1) | No   

ADARSH GAURAV   10 years AGO

550 is the answer.

Like? Yes (1) | No   

shree   10 years AGO

(x*36)/100=113+85
x=19800/36
x=550

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

36% *x = 113+ 85
x= 550

Like? Yes (1) | No   

abhilasha   10 years AGO

36% *x = 113+ 85
x= 550

Like? Yes (1) | No   

Aarush Singh   10 years AGO

36% *x = 113+ 85
x= 550

Like? Yes (1) | No   

kadambari   10 years AGO

36100*x=198
36x=19800
x=19800/36
x=550
therefore answer is 550.

Like? Yes (1) | No   

abhash kumar ranjan   10 years AGO

36*x/100=198
x=550

Like? Yes (1) | No   

Urvashi Verma   10 years AGO

Passing marks will be=113+85=198
let x be maximum marks
Thus 36% of x=198
x=550

Like? Yes (1) | No   

Ankan Biswas   10 years AGO

he has got 113 marks and is declared failed by 85 marks
therefore, pass marks = 85 + 113 = 218
pass marks is 36% of maximum marks.
Let the maximum marks in the exam be x.
Therefore, 36/100*x = 218
=>x = 218*100/36 => x = 550
Ans. 550 (option 3)

Like? Yes (1) | No   

mohit gupta   10 years AGO

113+85= 36%of x
x=550

Like? Yes (1) | No   

Sanjit Kumar Sharma   10 years AGO

36%=113+85=198
1%=198/36
100%=198/36*100=550

Like? Yes (1) | No   

Sabyasachi Pahari   10 years AGO

36% marks = (113+85) = 198
So, maximum marks = 198 x (100/36) = 550.

Like? Yes (1) | No   

Anvesh   10 years AGO

3

Like? Yes (1) | No   

Ritika Shrivastava   10 years AGO

No acquired by student =113
No required for passing=113+85=198
198=36%of total marks
198=36/100 of total marks
Total marks =550
Option 3 is the answer

Like? Yes (1) | No   

mahesh   10 years AGO

(36/100)*x=198
.: x=550

Like? Yes (1) | No   

T.Rami Reddy   10 years AGO

113+85=0.36*X where X is maximum marks
Solving for X
We get X=550

Like? Yes (1) | No   

Hemavathy Nangan   10 years AGO

(100/36)*8=550

Like? Yes (1) | No   

mamta garkoti   10 years AGO

marks obtained by him are 113 had he got 85 more, he woul have passed, so passing marks= 113+85= 198,
if max marks are x, then we have,
36/100 * x =198
on solving we have x= 550
hence max marks = 550

Like? Yes (1) | No   

DEEPAK GOSWAMI   10 years AGO

let x be the total marks then x*36/100=198
and x =550

Like? Yes (1) | No   

Ramesh Sriram   10 years AGO

36% MARKS IS=113+85=198
36----198
100-----?
198*100/36
=550

Like? Yes (1) | No   

Bheem Reddy Ravendra Reddy   10 years AGO

total marks are 550 because in this 36% of marks are 198

Like? Yes (1) | No   

Tania Chatterjee   10 years AGO

Let us assume that the maximum
marks for thr examination is x.
36% of x = 113 + 85
36x/100 = 198
36x = 19800
x = 19800/36 = 550 marks.
Ans: 550 marks.

Like? Yes (1) | No   

kanchan kumar   10 years AGO

{(113+85)*100}/36=550

Like? Yes (1) | No   

Anand Dwivedi   10 years AGO

Total markes Required For pass:-
113+85=198 are the passing marks.

198*100/36 = 550 marks

Like? Yes (1) | No   

sai kumari   10 years AGO

let max marks be x. given pass % is 36% therefore pass%=36%ofx. given he got 113 and still failed y 85 therefore total=113+85=198..therefore (36/100)x=198 hence x=550.

Like? Yes (1) | No   

pratima gupta   10 years AGO

113+85=198
198=x*36/100
x=550

Like? Yes (1) | No   

MOHIT GARG   10 years AGO

Let Max marks are M.
And 36*M/100 = 113+85
M=550

Like? Yes (1) | No   

sudeep   10 years AGO

let max marks be X
36% of X = Sum of 113 & 85
0.36*X = 198
Therefore X = 550.

Like? Yes (1) | No   

Sandeep Kumar   10 years AGO

113+85=198
(198/36)*100=550

Like? Yes (1) | No   

Shital Saste   10 years AGO

suppose max marks is x,
so, (36/100)*x=190
=> x=550

Like? Yes (1) | No   

Souvik Datta   10 years AGO

Let us assume that the maximum
marks for the examination is x.
36% of x = 113 + 85
36x/100 = 198
36x = 19800
x = 19800/36 = 550
so maximum marks 550

Like? Yes (1) | No   

Sutanu Shit   10 years AGO

pass mark = 113+85 =198

maximum marks = (100*198)/36 = 550

Like? Yes (1) | No   

arun kumar   10 years AGO

let x be total marks.
he failed by 85 and got 113 .
hence pass marks =198
198=36*x/100
x=550

Like? Yes (1) | No   

bilbo   10 years AGO

36% passed percentage
student got 113 marks and failedby 85 marks so total marks for passing is 113+85=198 i.e 36% so 1% appr is5.5 so the max marks be 550

Like? Yes (1) | No   

nishu kumar   10 years AGO

let total marks be X.
then to pass 9X/25 is required,
student get 113 marks and failed by 85 marks ,so if he got (113+85=198)marks then he will be pass.
so
9x/25=198
x=550=(total marks)

Like? Yes (1) | No   

DILBAG SINGH   10 years AGO

113+85*100/36

Like? Yes (1) | No   

Aishwary Tiwari   10 years AGO

passing marks= 113+85=198
let max marks be x
36x/100 = 198
x=550

Like? Yes (1) | No   

RISHABH SHARMA   10 years AGO

let total marks x so 36 * x/100 =113+85

Like? Yes (1) | No   

CHANDAN KUMAR   10 years AGO

let maxm marks=x
passing marks=36x/100
passing marks=113+85=198
now 36x/100=198
x=198*100/36=550
so maximum marks=550(answer)

Like? Yes (1) | No   

Inline Geek   10 years AGO

(113+85)*100/36= 550

Like? Yes (1) | No   

Kritika Joshi   10 years AGO

36%x=(113+85)
x=550

Like? Yes (1) | No   

MRITUNJAY KUMAR   10 years AGO

ans-550

Like? Yes (1) | No   

siddhartha sadhu   10 years AGO

36/100=(113+85)/x;
x=550

Like? Yes (1) | No   

shweta   10 years AGO

as minimum passing marks is 198 and this is given that 36% of maximum marks then we have to calculate 198=36%x and then obtain the value of x i.e the answer

Like? Yes (1) | No   

chavali nikhita   10 years AGO

198*100/36

Like? Yes (1) | No   

Kamal Rajput   10 years AGO

36% of x=(113+85)=198
x=550

Like? Yes (1) | No   

prabhat   10 years AGO

X%of 36=passing mark
(x/100)*36=113+85
x=550
maximam mark is 550

Like? Yes (1) | No   

mukesh kumar   10 years AGO

assume full marks is x
then, x*0.36=113+85
so x=550

Like? Yes (1) | No   

Grishma Shah   10 years AGO

To passing marks should be 113+85 = 198
36% of x = 198
Hence, x = 198/0.36 = 550

Like? Yes (1) | No   

Bhanu Pratap Singh   10 years AGO

total passing marks let be ' X '
minimum passing marks 113+85=198
maximum marks = ( 198*100)/36 = 550

Like? Yes (1) | No   

Darpan Shah   10 years AGO

Let total marks x.
Required no to clear exam is 36%.
Student get 113 but he has to score 113+85=198
so who get 198 then it is 36% of x.
So,
X * 36% = 198
X * 36/100 = 198
X = 198*100/33
X = 550
So 3

Like? Yes (1) | No   

David Raj   10 years AGO

36% of x is equal to 113+85
so x is 550 which is total marks

Like? Yes (1) | No   

Sneha   10 years AGO

113 + 85 = 198 = 36% of the aggregate marks
Therefore, the aggregate marks = 198 × 100/36 = 550.

Like? Yes (1) | No   

IMRAN AKHTAR   10 years AGO

Let max. marks be x
total pass marks=113+85=198
36% of x=198
x=550 (option 3)

Like? Yes (1) | No   

Ajay   10 years AGO

(113+85)/x=36
x=550

Like? Yes (1) | No   

Dinesh thatti   10 years AGO

add 85 t o113 we get 198
if 36% = 198
then 100%=?
100*198/36=550

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

LET us suppose total is x then
pass mark=113+85=198
x*36%=198
x=550

Like? Yes (1) | No   

niraj   10 years AGO

let maximum marks is x
a/c to qn.
113+85=36x/100
x=550(ans)

Like? Yes (1) | No   

Ashit Kumar   10 years AGO

Simple 35/100 *x= 113+85

solve for x

Like? Yes (1) | No   

urvish   10 years AGO

36 to 198
then 100- ??
19800/36=550

Like? Yes (1) | No   

senthilkumar47   10 years AGO

(198/36)*100=550

Like? Yes (1) | No   

harshit gupta   10 years AGO

if he got 85 more then he wud pass
113+85=198 , which is 36% of maximum marks
thus 0.36x=198
on solving we get
550=x

Like? Yes (1) | No   

RAJESH   10 years AGO

113+85=198
36%=198
100%= 198/36*100=550

Like? Yes (1) | No   

V.Mahesh   10 years AGO

for 36% = 113+85=198
by checking options 550*36/100=198
so option 3 is correct

Like? Yes (1) | No   

Y V S Chandrakanth   10 years AGO

36% of Maximum marks=113+85

Maximum marks=(198*100)/36=550

Like? Yes (1) | No   

Rashi Agarwal   10 years AGO

113+85=198 will be passing marks
198=36%of x where x is max marks
x=550 Ans.

Like? Yes (1) | No   

Mohan   10 years AGO

(113+85)*(100/36)=550

Like? Yes (1) | No   

Udit Kumar   10 years AGO

passing marks=113+85=198
36% of what is 198=198/36*100=550

Like? Yes (1) | No   

Kunal Jaiswal   10 years AGO

Let x be the maximum marks.
Then, 36% of x is the passing mark. Here a student got 113 marks but he failed by 85 marks, means
113+85 (=198) is the passing marks.
Which means (36/100)x=198
x=198/0.36
x=550.
So, option 3.

Like? Yes (1) | No   

Akshay   10 years AGO

x*.36=198
x=550

Like? Yes (1) | No   

subodh   10 years AGO

(198*100)/36

Like? Yes (1) | No   

T.Aravinth kumar   10 years AGO

((113+85)/0.36)*1=550

Like? Yes (1) | No   

Hemadri   10 years AGO

36%=113+85=198
1%=198/36=11/2
100%=11/2*100=550

Like? Yes (1) | No   

Priya Dharshini   10 years AGO

take min % to pass tat is 36%,

here this student needs 85 marks to reach this 36%,
now,consider total marks as x


36/100(x) -85=113

36/100(x)=113+85;

solving we get x=550;

Like? Yes (1) | No   

Ajinkya Kulkarni   10 years AGO

Let Max marks = m

That means marks required to be passed are 0.36m

So as per the condition equation become 0.36m-85=113
Solve it .
Ans is Max marks are 550

Like? Yes (1) | No   

BIKRAM KUMAR PANDA   10 years AGO

1oo(113+85)/36

Like? Yes (1) | No   

lakshmi nalluri   10 years AGO

.36(max.marks)=113+85
max marks=550

Like? Yes (1) | No   

Sandhya Goud   10 years AGO

113+85=198
198/550=36%

Like? Yes (1) | No   

gouthamdaneti   10 years AGO

x=(113+85)*100/36

Like? Yes (1) | No   

Anandh   10 years AGO

If 198 is 36% then 550 is 100%:

113+85=198
then x=(190x100)/36
=550

Like? Yes (1) | No   

SURAJIT KUNDU   10 years AGO

Total marks has to achieved (113+85)=198

so, 36% of 550=198

Hence, Ans=550

Like? Yes (1) | No   

rajeev chaubey   10 years AGO

x*36%=36x/100=.36x
.36x=113+85=198
x=550

Like? Yes (1) | No   

RAJU KUMAR MAHATO   10 years AGO

since the pass marks is 198 which can be seen by us in question which is 36% of max. marks i.e. 198

Like? Yes (1) | No   

RABI KR. SHAW   10 years AGO

36x/100=113+85
x=550

Like? Yes (1) | No   

akriti mishra   10 years AGO

let x be total marks
113+85=198
36%of x=198
then x=550

Like? Yes (1) | No   

nassarshahab   10 years AGO

113+85=198
36% of x=198
x=550

Like? Yes (1) | No   

neha kumari   10 years AGO

113+85=198
36x/100=198
x=550

Like? Yes (1) | No   

Devesh Gupta   10 years AGO

passing marks = 36% of maximum = 113+85

maximum marks=(198*100)/36=550

Like? Yes (1) | No   

Rahul Gupta   10 years AGO

Student got 113 mark and he was failed from 85 marks so Passing marks is = 113 + 85 = 198
Passing percent is 36% = 198
so for 100% = 198 * 100/ 36 = 550

Like? Yes (1) | No   

Ankit Sirohi   10 years AGO

36/100 *x= 113+85
=> x=198*100/36= 550 ..option 3.

Like? Yes (1) | No   

Anand   10 years AGO

let max marks= x
acc to ques 113= x*36% - 85
we get x= 550

Like? Yes (1) | No   

vinit   10 years AGO

since
113 marks he obtained and failled by 85 marks
and pass per=36%
113+85=198 which shuld be 36per of total marks
550*36/100=198

Like? Yes (1) | No   

shanmukha pradeep   10 years AGO

case 1:let x be the maximum marks and a minimum of 36% marks are the pass marks so 36% of x is the pass mark in the exam
case2:a student got 113 marks and failed by 85 marks it means he would have passed if he will get that 85 marks too so the sum of 113 and 85(total=198) will make him pass.
from case 1 and case 2 we can say that the pass % is 36% and the pass marks are 198.so 36% of x=198
36/100*x=198 by solving this we get x=550 marks

Like? Yes (1) | No   

nehal   10 years AGO

36/1oo *x=113+85

Like? Yes (1) | No   

swasthika   10 years AGO

pass mark =113+85
=198
let x be the maximum marks,
36% of x =198
x=550

Like? Yes (1) | No   

posirajesh   10 years AGO

19800÷36=550

Like? Yes (1) | No   

Mayank Joshi   10 years AGO

113+85=198
198=(36/100)*x
x=19800/36
x=550

Like? Yes (1) | No   

Raminder   10 years AGO

113+85=198 ie = 36%


then 100 %= ?

(198*100)/36=550

Like? Yes (1) | No   

Priya Verma   10 years AGO

(x*36)/100=113+85
x=550

Like? Yes (1) | No   

Shahrukh   10 years AGO

113+85=198
36=198/m.m*100
m.m=550

Like? Yes (1) | No   

SAMRIDHI GIRI   10 years AGO

36%100*x=113+85

Like? Yes (1) | No   

Sagar Kumar Subudhi   10 years AGO

36%=113+85
1%=198/36
100%=(198/36)*100
maximum mark is 550

Like? Yes (1) | No   

Harish   10 years AGO

196 is 36% so 100% is 550

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anitha   10 years AGO

36%x=198
x=198*100/36
x=550

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Abhinav Arpanam   10 years AGO

[x * (36/100)] - 85 = 113

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vishal shanker polowalia   10 years AGO

36%of x = 113+85

After solve
x = 550

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TUSHAR    10 years AGO

550

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Rabindranath Giri   10 years AGO

Marks need to pass 113+85 =198
So, maximum marks is (100*198)/36=550

Like? Yes (1) | No   

Arkja tiwari   10 years AGO

he got 113 marks
passing criteria 36%=(x*0.36)
failed by 85 marks
then 113+85=198
now 198=0.36*x
x=550

Like? Yes (1) | No   

Priyanshi Agarwal   10 years AGO

36% of max. marks 550= (550*36)/100=198
&
113+85=198
hence max. marks =550

Like? Yes (1) | No   

ruchika   10 years AGO

36*x=198*100

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jyoti   10 years AGO

The answer is 550marks because as the student failed by 85 marks (113+85)marks=36 percent.
=198marks=36percent.
Then as we are doing it by unitary method we take the value of 1 percent=198/36=5.5marks.
Then we multiply our answer by 100 to get 5.5*100=550

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phoenix    10 years AGO

36% = 113 + 85 = 198
so 100%= (198*100)/36
= 550

Like? Yes (1) | No   

Sohar Lal Singh   10 years AGO

let assume total marks require to pass=x marks
then he need to pass exam was=36% of total
=x*36/100
but he could score only =113 and fail by 85
so 36% of toal=113+85
x*36/100=198
then x=550; ans

Like? Yes (1) | No   

Namrata Gupta   10 years AGO

113+85=198
let us assume max marks=x
36% of x = x*(36/100)=198
x=(198*100)/36=550

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Vishal Chugh   10 years AGO

113+85=36%

36%=198;
100= 550

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Muthu Kumar M   10 years AGO

36%=113+85=198
100%=(198*100)/36=550 marks

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Masudur Rahaman   10 years AGO

assume, max marks = x
36x/100 = 113+85
=> x = 550

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RUPALI KUMARI   10 years AGO

113+85=198
let passing marks be 'x'
then , 36x/100=198
x=550

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SANTOSH SAHOO   10 years AGO

36%=198mark
100%=(198/36)*100

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k.madhu sudhan reddy   10 years AGO

verify the option failed by 85 marks & got 113 marks, so total marks need to pass the exam is 198 so in option we can verify that 550*36/100=198

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Annu Kumari   10 years AGO

36x/100=(113+85)
x=19800/36
x=550

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Pradip G Giri   10 years AGO

36*550/100

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Chandra chur anand   10 years AGO

let x be total no.
so 36x/100=113+85
or 36x/100=198
or x=550 so max mark ll be 550

Like? Yes (1) | No   

Subhash Singh Kushwaha   10 years AGO

let the max. marks be x then 36% of x=passing marks
where passing marks=113+85=198
(36*x)/100=(98)
which gives x=550

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Ranjeet singh   10 years AGO

36% of 550 is 198 i.e.(113+85)

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Mahesh   10 years AGO

198 marks is 36%
For finding the maximum markss, it should be 198*100/36=550

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prabhat kumar   10 years AGO

36%=198
hence 100%=550

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vartika    10 years AGO

let max marks be x
then 36% of x- 113=85
solving we get x=550

Like? Yes (2) | No (2)  

Sourojit Dhua   10 years AGO

Let us assume that the maximum marks for thr examination is x.
Then the equation we get as per simple linear equation:
36% of x = 113 + 85
36x/100 = 198
36x = 19800
x = 19800/36 = 550 marks.
Ans: 550 marks

Like? Yes (1) | No (1)  

pragati rathore   10 years AGO

113=85=198
198=(36/100)*x
x=550

Like? Yes (3) | No (3)  

Abhishek Kumar   10 years AGO

113+85=36% of total marks
if total marks=x
36x/100=198
x=550

Like? Yes (1) | No (1)