The distance between two stations A and B is given as 623 km. A train moving at a speed of 36 m/s will reach the station B after time

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05 Nov 2014 Time and Distance The distance between two stations A and B is given as 623 km. A train moving at a speed of 36 m/s will reach the station B after time: OPtion
1) 4 hour 18 min 46 sec
2) 4 hour 40 min 24 sec
3) 4 hour 44 min 28 sec
4) 4 hour 38 min 16 sec
5) 4 hour 32 min 27 sec
6) 4 hour 48 min 26 sec
7) 4 hour 08 min 25 sec
8) 4 hour 33 min 25 sec
9) 4 hour 28 min 25 sec
10) 4 hour 46 min 24 sec; Correct Option: 6 Best Solution (41)

Kushagra Tiwari 10 years AGO

Time = distance / velocity
623 / (36 * 3.6) hours
= 4 hour 48 min 26 sec

Like? Yes (16) | No (8)

NAGARAJ R M 10 years AGO

A TRAIN IS MOVING AT A SPEED OF 36 M/S

CONVERT IT INTO KM/H

36*18/5=129.6KM/H

NOW

TOTAL DISTANCE/SPEED
623/129.6=4.80709877

NOW WE CAME TO KNOW THAT 4 HOURS +X MINUTES+ X SECONDS

CONVERTING THIS INTO MINUTES

0.80709877*60/100=0.48425926

NOW WE CAME TO KNOW THAT 4HOURS+48MINUTES+X SECONDS

CONVERTING THIS INTO SECONDS

0.425926*60/100=0.2555556 APRROX .26

THAT IS 26 SECONDS

SO THE TRAIN WILL REACH THE B STATION AFTER 4H 48M 26S //

Like? Yes (7) | No

Shreya Tiwari 10 years AGO

Time = distance / velocity
623 / (36 * 3.6) hours
= 4 hour 48 min 26 sec

Like? Yes (4) | No (2)

Amit Kumar Pal 10 years AGO

Time = distance / velocity
623 / (36 * 3.6) hours
= 4 hour 48 min 26 sec

Like? Yes (2) | No

Gagandeep Singh Chhabra 10 years AGO

first convert the speed in unit of km/h
=36*18/5 km/h
=129.6km/h
time taken to cover 623km=623/129.6 hr
=4.807hr
4 hours 48 minutes 26 secs

Like? Yes (2) | No (1)

RAKESH 10 years AGO

t = 623 *5 / 36*18 = 3115/648

= 4h + 523/648 *60 min

= 4h + 48min + 26sec

Like? Yes (2) | No (1)

Narasapu Hari prasad 10 years AGO

Ans is option 6.
The speed of train is 36*60*60/1000=129.6 km/h.
So it takes 623/129.6=4.8.798 which is in 4 hours 48 minits 26 sec

Like? Yes (2) | No (1)

Yogeshkumar 10 years AGO

Distance=623km=623000m. speed=36m/s=36*60m/min=2160m/min. Time=distance/speed=623000/2160=288.425925925min. so 288min and 0.425925925*60=25.55555=26seconds. 288/60=4.8hrs. so 4hrs and 0.8*60=48min. so answer is 4hrs 48min 26sec.

Like? Yes (2) | No (1)

Anubhav jain 10 years AGO

T = D/S
T= 623*5/36*18
T=4 HOUR 48 MIN 26 SEC

Like? Yes (1) | No

anuj gupta 10 years AGO

623*1000/3600=4 H 48 Min 26 Sec

Like? Yes (1) | No

vineesha p 10 years AGO

dist=623km
vel=36m/s=36*(18/5) km/hr
time=dist/vel=4.807...
4.807*60=288.42..which is equal to 4hr 48min
288.42-4*(60)=48.42 minutes

Like? Yes (1) | No

ravikant kumar 10 years AGO

time= (623*1000)/36=4 hour 48 minute 26 minute

Like? Yes (1) | No

saimeera 10 years AGO

623*1000/36*60*60=4 hr 48 min 26 sec

Like? Yes (1) | No (1)

dhanaseelan 10 years AGO

speed=36*18/5 kmph
distance=623 km
time=4.807=4hrs 48 min 26 sec

Like? Yes (1) | No (1)

Arijit Acharyya 10 years AGO

36m/s = 36*3.6 km/hr =129.6 km/hr
623/129.6 = 4.807 hr = 4 hour 48 min 26 sec (approx)

Like? Yes (1) | No (1)

Abhishek Vishwakarma 10 years AGO

Time = distance / velocity
623 / (36 * 3.6) hours
= 4 hour 48 min 26 sec

Like? Yes (1) | No (1)

NAVEEN KUMAR 10 years AGO

speed of train=36m/s=36*(18/5)km/h
The distance between two stations A and B is given as 623 km
so time req. for reach the station B=623/(36*(18/5))
=4.81 hrs=4h 48 m 26 s (approx)
option(6)

Like? Yes (3) | No (3)

Tark Patel 10 years AGO

Distance d = 623 km = 623000 m,
Speed s = 32 m / s

Time t = d / s = ( 623000 / 32 ) sec = 17305.555555... sec

Converting into hour , minute and seconds we get
answer as 4 hour 48 min 26 sec.

Like? Yes (1) | No (1)

urvish 10 years AGO

623km =623000m
so 36 m->1 sec
623000-> 4 hr- 48min-some sec..

Like? Yes (1) | No (1)

vaitesh mudaliar 10 years AGO

speed = dist/time
time =dist/speed
=623000/36
=17305.556
converting it into time v get 4 hrs 48 min 26 sec

Like? Yes (1) | No (1)

Sanu Panji 10 years AGO

required time
=(623*1000)/60
=288 min 26 sec
=4 hr 48 min 26 sec

Like? Yes (1) | No (1)

Rishikesh Ranjan 10 years AGO

t= d/s

4 hr 48 mnt 26 sec

Like? Yes (1) | No (1)

HANU YADAV 10 years AGO

Total distance are=625*1000=625000meter
and speed of train is=36 m/s
so the time taken by the train is=625000/36 second
on solving it=4 hour 48 minute 26 sec

Like? Yes (1) | No (1)

A M ANKIT KALLURAYA 10 years AGO

62300/(36)*(3.6)=ans......

Like? Yes (1) | No (1)

vibhor 10 years AGO

Time= Distance /speed
Distance= 623 km
=623000 m
speed =36 m/s

time =623000/36
=17305.56 s => 4 hour 48 min 26 sec

so answer will be otion 6

Like? Yes (2) | No (2)

Aparna Bhattacharya 10 years AGO

36m/s=36*(18/5)=129.6 km/s.
The train will reach station B at the time=(623/129.6)=4.8070= 4hr 48min 26sec.

Like? Yes (1) | No (1)

PAWAN KUMAR 10 years AGO

SPEED IN KMPH = 36*18/5 = 648/5 KMPH
THEREFORE, TIME TAKEN = 623*5/648 = 4.80 HR
= 4 HR 0.80*60 MIN
= 4 HR 48 MIN

Like? Yes (1) | No (1)

Rashi Bansal 10 years AGO

speed of train= 36*18/5 km/hr
distance = 623 km
time taken = distance/speed = 4.8071 hours
= 4hr 48 min 26 sec

Like? Yes (1) | No (1)

Dinesh Kumar 10 years AGO

speed=36*18/5kmhr
t=623*5/36*18=4hr48min 26sec

Like? Yes (1) | No (1)

Abhishake Agarwal 10 years AGO

t=((623*1000)/36)
t=17305.55 second
t=4 hour 48 min 26 sec

Like? Yes (1) | No (1)

VIKAS KUMAR THAKUR 10 years AGO

distance=623km=623000 m
speed=36m/s
time=623000/36=17305.556 sec~17306 sec=4h48m26sec

Like? Yes (1) | No (1)

khushboo goenka 10 years AGO

coz tym= 623/36=4.807sec
= 4hr 48 min 26 sec

Like? Yes (1) | No (1)

tirupathi reddy 10 years AGO

Time = 623000/36
= 155750/9
For Hours = 155750/(9*60*60) = 4h (4*(2615/3240))
Minutes = 2615/54 = 48m (48*(23/54)) (3240/60= 54)
Seconds = 230/9 = 25.5556s (26)

Like? Yes (1) | No (1)

Deepak Kumar 10 years AGO

Distance in meter 623000 m
speed 36 m/s
time = 623000/36
= 17305.56 second
= 4 hour 48 min 26 sec

Like? Yes (1) | No (1)

alok meher 10 years AGO

623000/36=17305.5 sec
17305.5 sec=4 hr 48 min 26 sec

Like? Yes (1) | No (1)

Sandeep Kumar 10 years AGO

36*60/1000=54/25 km/m
Now.. 623/(54/25)=288.5 minute
= ~~ 4 hour 48 minute's 30 seconds

Like? Yes (1) | No (1)

Arun Kumar 10 years AGO

calculation
total seconds taken to cover the distance is 17305.55
if we convert the seconds into hours and minutes we 4 hours 48 minutes approximate 26 seconds

Like? Yes (1) | No (1)

SOURABH 10 years AGO

time =d/s
d=623000m
s=36m/s

Like? Yes (1) | No (1)

shefali jain 10 years AGO

36m/s=129.6km/hr

time=distance/speed
=623/129.6=4.8070hr

.8070*60*60=48.26

so the answer is 4hr 48min 26sec

Like? Yes (2) | No (2)

BHASKAR MANDAL 10 years AGO

36 m/s = 36 * 18/5 km/hr
time = distance/speed = 623*5/36*18 = 4.80709 hr
= 4 hr 48 min 26 sec
option 6

Like? Yes (2) | No (3)

sachin 10 years AGO

train travels total 623 km.
speed of train is 36 m/s . so the speed in km/hr will be
36 x (18/5)= 129.6 km/hr

time taken to reach at 'B' = totlal distance/speed
= >623/129.6 = 4.8070
so 4 hrs 48 min 26 sec approx

Like? Yes (1) | No (2)

Dimple

India

Punjab

Time: 00:01:33

Points

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The distance between two stations A and B is given as 623 km. A train moving at a speed of 36 m/s wi

M4maths Previous Puzzles

05 Nov 2014 Time and Distance