K.ARun   10 years AGO

x+x+3+x+6=48
3x=39
x=13
so 1st 3sons 13,16,19 respectively
eldest son=19 father=48..
3years before
eldest son 16 and father=45
so.. 45/16

Like? Yes (12) | No (3)  

Sanjay Bhatt   10 years AGO

Let the present age of father be X.
Let the present age of eldest son be s1.
Let the present age of second son be s2.
Let the age of youngest son be s3.

X=s1+s2+s3.
Also, s1=s2+3
s2=s3+3
then,
X=3*s3+9
s3=13
&s1=19

Before 3 years,
Age of Father=45
Age of Eldest Son=16(s1-3)

So Ratio,
45/16

Like? Yes (2) | No   

sailash prasad chowdhury   10 years AGO

x+x+3+x+6=48,so x=13
now the age of the elder son is x+6=19,3 years ago his age is 16. fathers age 3yrs ago is 45....so the answer is 45:16

Like? Yes (2) | No   

Sanu Panji   10 years AGO

Say three sons age is (x-3), x and (x+3)
so, (x-3)+x+(x+3)=48
or, x=16
elder son's age = 16+3= 19

3 yrs before elder son's age = 19-16
3 yrs before father's age = 48-3 =45

so ratio is 45/16

so, correct option is (4)

Like? Yes (3) | No (2)  

Pramod Gaikwad   10 years AGO

suppose present age of man=48
suppose middle son age is x
48=x+(x+3)+(x+3)
x=16
so age of sons 13,16,19
age of eldest son 3 year before 48-3=45
so ratio is 45/16
answer is 4)45/16

Like? Yes (4) | No (3)  

veeranjaneyulu   10 years AGO

48=19+16+13
m/e=48-3/19-3
m/e=45/16

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

Let, Father's age = a
and his son's age are x, y, z, where x is the eldest one.
Now, a/q, a = x + y + z
so, 48 = (x+3) + x + (x-3)
so x = 16
so, eldest son's age = 16 + 3 = 19 years.

3 years ago, a = 45 and x = 16
so ratio = 45/16.........

Like? Yes (3) | No (2)  

CHANDAN KUMAR   10 years AGO

m=x+y+z
48=x+x-3+x-6
x=19
m-3/x-3=48-3/19-3=45/16

Like? Yes (1) | No   

shireesha chinthagunta   10 years AGO

19+16+13=48
3 yrs ago eldest son age=16
father's age 45
ratio of father and eldest son=45/16

Like? Yes (1) | No   

vibhor   10 years AGO

Let x be the age of his youngest son,
then the age of other son's as x+3,x+6
now,
(x)+ (x+3)+(x+6)=48
3x+9=48
3x=39
x=13

so the present age of his sons
13,16,19

now we have to find the ratio of age af father and eldest son at 3 years before,

father's age at 3 years before=48-3=>45
eldest son's age at 3 years before=19-3=>16

so the ratio is 45/16
option 4

Like? Yes (2) | No (1)  

santosh kumar patel   10 years AGO

man age (48) = his son age()
diff of his son = 3
so son age is - 13 , 16, 19
father and eldest son ratio before 3 year=45/16
ans: 45/16

Like? Yes (2) | No (1)  

nikhil pogale   10 years AGO

m=s1+s2+s3
s1=s3+6
S2=s3+3
3*s3+9=48
s3=13
s1=19
ratio befor 3 yr
f-3/s1-3=45/16

Like? Yes (1) | No   

Shravya   10 years AGO

let agesbe x,x+3,x+6
3x+9=48
48:16(x+6+3)

Like? Yes (1) | No   

Anoop Tiwari   10 years AGO

let son's ages =x+3,x,x-3
so sum=x+3+x+x-3=48
3x=48
x=16
ages=19,16,13
elder son's age =19
3 years before= father's age=45,eldest son's age=16
ratio=45/16
hence 4) is correct

Like? Yes (1) | No   

prem   10 years AGO

if current age of eldest son is x+9
then other two son's age is x+6 and x+3
and current age of father is 48
3year before father age is 45 and their son's age is x,x+3,x+6
since current age of father =sum of son's age
48=x+3+x+6+x+9
x=10
hence ratio of 3year before father age and eldest son age is 45/16
hence option 4 is currect

Like? Yes (1) | No   

pushpa   10 years AGO

sum of ages of his 3 sons= his present age=48
n difference of age of his sons is 3
so ages of his 3 sons can be
(19+16+13)=48
so the age of his elder son is 19 at present
therefore the ratio of his age & his eldest son's age 3 year before,
(48-3)/(19-3)=45/16
ans- 4

Like? Yes (1) | No   

sanjeev kumar   10 years AGO

ans 4

Like? Yes (1) | No   

VIVEK KUMAR BARANWAL   10 years AGO

LET AGES OF SONS ARE X-3, X, X+3
BY PROBLEM
(X-3)+X+X+3=48
X=16
THEREFORE ELDEST SONS PRESENT AGE=16+3=19
THEREFORE REQUIRED RATIO=(48-3):(19-3)=45:16

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

ages of the suns is 13 16 19.
ratio of father and his eldest son three years back is 45/16

Like? Yes (1) | No   

Deepak prajapati   10 years AGO

let age of eldest son=x+6
then age of second son=x+3
age of younger son=x
so
ATQ
3x+9=48
x=13
now
(48-3)/(x+6-3)=45/16
option 4 is correct

Like? Yes (2) | No (1)  

abhishek narayan   10 years AGO

f=e1+e2+e3
=>48 =3e1-9
=>e1=19
f-3/e1-3=45/16

Like? Yes (1) | No   

PRANAV PRAKASH   10 years AGO

Suppose younger son age is A...
Then A+(A+3)+(A+6)=48....SO A=13...
Eldest son age is 13+6=19...A/q ratio of father to the eldest son age 3 years before=(48-3)/(19-3)=45/16

Like? Yes (1) | No   

Deepak Kumar   10 years AGO

let x be the age of the eldest son
then
48= x + (x - 3) + (x - 6)
then
x = 19
father age is 48
three years before
eldest son's age was 16
and father's age was 45
then the ratio is
45/16

Like? Yes (1) | No   

AMREEN   10 years AGO

Let the age of eldest son is A
the age of second son =A-3
age of 3rd son=A-6
Then A+A-3+A-6=48
A=19
Then ratio of eldest son and fathe before 3 years is=(48-3)/(19-3)
=45/16 ans.

Like? Yes (1) | No   

vaitesh mudaliar   10 years AGO

sum of ages of 3 sons =48
x1+x2+x3= 48
x1-x2=3
x2-x3=3
solving these 3 equn v get values of x1=19, x2=16, x3=13
ratio =(X-3)/(x1-3)=48-3/19-3 =45/16

Like? Yes (1) | No   

shubham   10 years AGO

43434

Like? Yes (1) | No   

Jayanta Dutta   10 years AGO

x+x+3+x+6=48

so x+6=19;

now 3 years before

dad was 48-3=45
eldest son was=19-3=16
so ratio is: 45/16

Like? Yes (1) | No   

Sourabh Prasad   10 years AGO

Let son's age be x, y and z.
We have considered x is the youngest son.

Given,
Present age of father is 48.
x+y+z=48 -----------------(1)

Also Given, Age difference of his sons is 3 years.
x=y+3 -----------------(2)
y=z+3 -----------------(3)


So we have 3 equation & 3 variable,

Soving we get x=19

Therefore, Ratio before 3 years is (48-3)/(19-3)
=45/16

Like? Yes (1) | No   

Yekollu Muneeswar   10 years AGO

given age of father at present =48 & sons age difference is 3 yrs
let age of young son be X ,middle X+3 , and Elder be X+6
then given that at present, sum of ages of sons=father age
---> X+X+3+X+6=48
3X+9=48
x=13.

before 3 yrs Father age=45 and Elder Son Age=16
so Ratio is 45/16

Like? Yes (2) | No (1)  

ARJUN PRASAD   10 years AGO

let present age of three sons are x,x+3,x+6 ;
atp....
x+(x+3)+(x+6)=48
so x=13.
present age of elder son=19
before 3 ys
age of father=45 and age of elder son=16
so ratio=45/16

Like? Yes (1) | No   

Praneet   10 years AGO

At Present
let smallest son age be x the
x+x+3+x+6=48
so, x=13
therefore age of son is 13,16,19


Now 3 years ago age of eldest son is 19-3=16
so, ratio of their ages is 45/16

Like? Yes (1) | No   

Hemadri   10 years AGO

present age of man=48
His 3 sons ages having difference of 3
So the ages of his sons are 19 16 13(19+16+13)=48
Ratio of his eldest son to his age before 3 years is
48-3=45 and 19-3=16
Ratio =45/16

Like? Yes (1) | No   

nitin Maheshwari   10 years AGO

Let the age of children are x,x-3,x-6
given,
x+x-3+x-6=48,
x=19


ratio 45/16 ans.

Like? Yes (1) | No   

A M ANKIT KALLURAYA   10 years AGO

45/16
x+x-3+x-6=48
x=19
three years before
x=x-3=16
fathers present age=48
three yrs ago father was 45
=>45/16

Like? Yes (1) | No   

Pankaj Malik   10 years AGO

Present age of father=sum of ages of his sons…n difference b/w age of sons is 3...
So 48=13+16+19
At present the age of eldest son is 19.
Before 3 years...eldest son's age=16 & father's age=45
Ratio=45/16

Like? Yes (1) | No   

vootukoori laxman   10 years AGO

let the ages are x, x+3,x+6 from young to elder
now x+x+3+x+6=48
then x=13
x+3=16
x+6=19
then ratio before 3 years is 48-3 /19-3 =45/16

Like? Yes (1) | No   

MAHARAJAN.G   10 years AGO

now father age is 48
no. of sons=3
they have difference of 3 in their ages
so,
first son age is 19
second son age is 16
third son age is 13
first son age before 3 years is 16
father age before three years is 45
ratio is=45/16
ans ) 4

Like? Yes (1) | No   

rajkaran singh   10 years AGO

we are given : present age of father=48
differences b/w sons ages=3
therefore sons ages must be = 13,16, 19(as 13+16+19=48 and differences b/w their ages=3)
now
3 years back father's age=45
and eldest son = 19-3=16
therefore ratio of their ages=45/16

Like? Yes (1) | No   

Biswajit Saha   10 years AGO

let the age of youngest son is x.
differences of ages of his son is 3.
man's present age is 48.
x+(x+3)+(x+6)=48
x=13
hence age of eldest son is (x+6)=13+6=19
3 years before the age of father and eldest son was (48-3)=45 and (19-3)=16.
the ratio of father's age & his eldest son's age 3 year before is = 45/16.

Like? Yes (1) | No   

Gagan   10 years AGO

before 3 years the age of father is 45 and the of eldest son is 16 because the age of eldest son is after 3 years 19 and age of other son's are 13 & 16 so difference between ages are 3

Like? Yes (1) | No   

sravani rachakonda   10 years AGO

M=s1+s2+s3
Given s1-s2=3
S2-s3=3
48=s1+s1-3+s1-6------->>s1=19
M-3:s1-3=45:16

Like? Yes (1) | No   

ayushi   10 years AGO

Let a be the age of eldest son :
48=a+(a-3)+(a-6)
=>a=19;
=>age of father/age of eldest son is(3 yrs ago )=(48-3)/(19-3)
=>45/16

Like? Yes (1) | No   

Sonam Gupta   10 years AGO

given x+y+z = 48
let x be the eldest son , y mid son and z youngest son
hence , x= y+3 or y = x-3
y = z+3 or z = y-3 or z= x-3 -3 = x-6

hence , x + x-3 +x - 6 = 48
3x -9 =48
3x = 57
x = 19

3 years before , x = 16
and father was = 45
hence ratio was 45 / 16

Like? Yes (1) | No   

niraj   10 years AGO

48-3/19-3=45/16

Like? Yes (1) | No   

Y V S Chandrakanth   10 years AGO

x,x-3,x-6
given x+x-3+x-6=48
x=19
ratio=(48-3)/(19-3)=45/16

Like? Yes (1) | No   

Tark Patel   10 years AGO

Let age of man = M
age of his 3 sons like S1, S2. S3 (S3 is eldest)

Given M = S1 + S2 + S3
Sons' age difference is 3
so M = (S1) + (S1+3) + (S1+6)

48 = 3S1 + 9
S1 = 13

->S3 = 19
Hence 3 years before ratio of man's age and his eldest son (S3) is,

48 - 3 / 19 - 3 = 45 / 16

Like? Yes (1) | No   

khushboo goenka   10 years AGO

let son ages are x,x-3,x-6
thn father age =x+x-3+x-6=48
so x=19
3 year before father age=45
and eldest son age= 16,13,10

Like? Yes (1) | No   

ANKIT GABA   10 years AGO

48=(x-6)+(x-3)+x
x=19
3year ago
48-3=45 father age
19-3=16 elder son age
45/16

Like? Yes (1) | No   

Manoj Chouhan   10 years AGO

a+b+c= 48
a+(a-3)+(a-6)=48
3a-9 =48
a=19.
so b=16; c=13
now,

48 = 13+16+19 //*

48-3/19-3 ratio

45/16 ans (4)

Like? Yes (1) | No   

vikaskumar   10 years AGO

father age=48;elder son age=x
As there is a difference of 3 between the brother's ages
48=x+(x-3)+(x-6)
48=3x-9
x=57/3=19;
As in que it is asked before 3 years father's age=45 and eldest son=16
::Answer is 45/16

Like? Yes (1) | No   

SUMAN SAURAV   10 years AGO

48 = s + (s-3) + (s-6)
s = 19

age of man 3 yrs ago = 45
age of elder son 3 yrs ago = 16
ratio = 45/16

Like? Yes (1) | No   

Udhaya kumar   10 years AGO

48 = (x + x-3 + x-6)
x = 19
3 years before 16 , 45
45 / 16......

Like? Yes (2) | No (1)  

Amit Kumar   10 years AGO

age of son's are x, x+3,x+6
so
x+x+3+x+6=48
x=13
age of father before 3 years=45
age of the eldest son is=19-3=16

Like? Yes (1) | No   

Rajat Rokade   10 years AGO

Suppose Present age of eldest son = x
Difference between age=3
So,
(x-6) + (x-3) + x=48
(age of eldest son) x=19
Before 3 years,
father's age=45 and eldest son's age=16
So ratio = 45/16.
Option 4 is correct.

Like? Yes (3) | No (3)  

Rahul Rathod   10 years AGO

let ages of sons are=x-3 , x , x+3
present age of man =48
so 48=(x-3)+(x)+(x+3)
x=16
so ages of sons are: 13,16,19
age of eldest son 3 years before=19-3=16
age of man before 3 years=48-3=45
so
ratio=(45/16)
answer is option 4 =45/16

Like? Yes (3) | No (3)  

sravani   10 years AGO

Let the age of elder son be X
given diff between the sons is 3 years each and mans age is 48 at present .
so the eq is x+x-3+x-3-3 =48
3x-9=48
x=19
3 years before
father's age is 45
elder sons age is 16
ratio is 45:16.

Like? Yes (2) | No (2)  

BHASKAR MANDAL   10 years AGO

let father present age be p
age of older = x
p = x + x-3 + x-6
= 3x-9
48 = 3x-9
=> x =19
ratio of father age to son 3 years before = 45/16
option 4

Like? Yes (2) | No (2)  

Md.Sultan Khichi   10 years AGO

Present age of father is 48.
So sum of ages of sons is 48.
Diff of their ages is 3. So eldest son's age is 19.
3 years before fathers age was 45 and eldest sons was 16.
Ratio=45/16
Ans..ob 4

Like? Yes (1) | No (1)  

Azhar Syed   10 years AGO

Because x+x+3+x+6=48;
solving we get x=13 i.e present age of younger son & present age of eldest son is 19.
Before 3 years fathers age was 45 and eldest son's age was 16

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

Age of father = 48
let ages of sons be x, x+3 and x+6 respectively.
Then, sum = 3x+9 = 48 =>x= 13
Therefore, ratio = 45/16 Ans.

Like? Yes (1) | No (1)  

RAKESH   10 years AGO

13+16+19 = 48

req. ratio = 48-3 / 19-3 = 45/16

Like? Yes (1) | No (1)  

ganesh babu   10 years AGO

F+S+T=man
F is elder son , S second son, T third son
F+(F-3)+(F-6)=48 Given that the difference of age of his sons is 3
3F=48+9
F=19
What was the ratio of his age & his eldest son's age 3 year before
45/16

Like? Yes (1) | No (1)  

Sukanya   10 years AGO

Age of man= sum of his sons ages= 48
Dif bw the sons ages is 3
x-3+x+x+3=48
x=16
sons ages=13,16,19.

3 years before
father's age =45
elder son age= 16
so the ratio =45/16.

Like? Yes (1) | No (1)  

susheela   10 years AGO

father=sum of age of 3 sons
at present father's age is =48
48=19+16+13
48=19 (age of eldest son)
three year before
45=16
45/16

Like? Yes (1) | No (1)  

Ranjit Somisetty   10 years AGO

48=(x+x+3+x+6) x is age of youngest
x=13
3 years ago fathers age is 45 and eldest sons age is x+6-3=16
Hence ratio becomes 45/16

Like? Yes (1) | No (1)  

Manju Prakash R   10 years AGO

Let ages of sons be x-3,x,x+3 in the order.
So, x-3 + x+ x+3 =48

So age of eldest =19
Ratio 45 :16

Like? Yes (1) | No (1)  

Jeyadev    10 years AGO

given 48=x+(x=3)=((x+3)+3) ==> 48=3x+9 ==> x=13
before 3 yrs their ratio will be ((48-3)/(x+6-3)) ==> 45/(13+6-3)
==> 45/16

Like? Yes (1) | No (1)