K.ARun   10 years AGO

x^2 + x^2 = (50sq.rt(2))^2=5000
2x^2=5000--> x=50
perimeter of triangle = 50+50+50sq.rt(2)
=10+50*1.4146=170.73m
Cost of fencing=170.73*3=512.19

Like? Yes (7) | No (3)  

Prerna   10 years AGO

A plot of land is in the shape of a right angled isosceles triangle. The length of the hypotenuse is 50*sqrt(2). Base and height will be 50 mtrs. Perimeter of triangular plot will be 50+50 +50 *sqrt(2) i.e. approx 170 mtrs.
The cost of fencing it at Rs.3 per metre will be: approx 170*3= Rs 510. means more than Rs 500.

Like? Yes (3) | No   

Gagan Raj M   10 years AGO

For a Right angled triangle of side 'a', then length of hypotenuse is a*sqrt(2).
Hence Total length of plot (i.e perimeter of Right angled triangle) = 50+50+50*sqrt(2) = 170.71 mtrs
Therefore Cost of fencing = 3*170.71 = Rs.512.13(i.e > 500)

Like? Yes (3) | No (1)  

Jaspalsingh Parmar   10 years AGO

Firstly we have to find the length of each side of right angled isosceles triangle
Let the side of isosceles triangle be s

so according to given condition

(s)^2+(s)^2=(50sqrt2)^2

2(s)^2=5000

(s)^2=2500

so,
s=50

For facing we require all the side of triangles=s+s+50sqrt2
=s+s+70.71

Putting the value of s we get=50+50+70.71=170.71 m

Now The cost of fencing it at Rs.3 per metre will be=170.71*3 = 512.13Rs

So it is more than Rs 500
So option 6 is correct

Like? Yes (2) | No (1)  

Ajinkya Kulkarni   10 years AGO

512

Like? Yes (2) | No (1)  

sonu ram   10 years AGO

Here, The h=50sqrt(2).
Let other two sides will be-a:
then,
using pythagorus theorem:
a=50:
so total:50+50+50sqrt(2)=170.7m
Total cost will be=170.7*3=Rs 512.10.
Which is more than 500.

Like? Yes (2) | No (1)  

pallavi kumbhar   10 years AGO

length of side=50
total perimeter= 170.7
cost=170*3= 512

Like? Yes (1) | No   

Sai Siddartha   10 years AGO

The perimeter of the triangle with the said dimensions would be 50+50+50sqrt(2) = 170 (Approximately). Cost of fencing at Rs.3/Meter = 170*3 = Rs.510.

Like? Yes (1) | No   

shivali   10 years AGO

perimeter is 172
then 172*3=516Rs

Like? Yes (1) | No   

Mohit Garg   10 years AGO

Hypotenus of Right angled isoceles triangle is a*sqrt(2) = 50*sqrt(2)

So the Side of traignle is = 50

Now According to Pythagorus 3rd side Will be = sqrt(50*50 + 50*50) ~ 71

So Perimeter of plot is = 50+50+71 = 171

Now as Per 3 Rs/m total cost will be = 171*3 = 513 Rs.

Like? Yes (1) | No   

dilip   10 years AGO

perimeter is nearly 180,so perimeter*3 is the cost

Like? Yes (1) | No   

swarupa nuggu   10 years AGO

6

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lavanya   10 years AGO

let each one of the equal sides of the triangle in piece of land is x m
x^2+x^2=(50*sqrt(2))^2=>x=50 m
the perimeter of the land=x+x+50*sqrt(2)=100+50*sqrt(2)
the cost of fencing is
3(100+50*sqrt(2))=300+150*sqrt(2)=512

Like? Yes (1) | No   

Sanu Panji   10 years AGO

512.1

Like? Yes (1) | No   

Chirag Ranjan Lahiri   10 years AGO

Perimeter of the triangle
= 50 + 50 + 50*root2
= 100 + 50 x 1.4146 = 170.73 m
So, Cost of fencing = Rs(170.73 x 3) = Rs 512.19

Like? Yes (1) | No   

sneha sri   10 years AGO

other two sides are 50
perimeter=100+50×1.414
cost=perimeter×3=512.64

Like? Yes (1) | No   

KAUSHIK DAS   10 years AGO

The sides will be calculated as x=50.
total length=50+50+50*sqrt(2)
price = total length *3 =512.1

Like? Yes (1) | No   

Supriya Mondal   10 years AGO

let one edge is a meter
then
2a^2=5000
then a=50
so perimeter=(50+50+50*sqrt(2))
so cost needed =3*perimeter
which is more than 500
so option 6)more than 500 is the right answer

Like? Yes (1) | No   

Surit Datta   10 years AGO

If the hypotenuse of a right angled isosceles triangle is
50*sqrt(2)
Then its other two sides will be 50 miter each.
so perimeter is 150*sqrt(2)
so fencing it at Rs.3 per metre will be
150*sqrt(2)*3
which is Rs 636 (almost)
which is greater than 600
so option 7
That's it.

Like? Yes (1) | No   

mayank   10 years AGO

{50+50+50*sqrt(2)}*3

Like? Yes (1) | No   

MRITUNJAY   10 years AGO

perimeter of right angled issoceles triangle is 2a+b
by pythagoras theorem
a^2+a^2=5000
a=50
perimeter=2*50+70.7=170.7
cost of fencing =170.7*3
which is more than 500.

Like? Yes (1) | No   

sriharsha   10 years AGO

(50+50+50*sqrt(2))*3=510.3 approximate

Like? Yes (1) | No   

Pradyumna K S   10 years AGO

Let each one of the equal sides of the triangular piece of land be xm.Then, x 2 + x 2 = (50√2) 2 ⇒ x = 50 m⇒ The perimeter of the land = x + x + 50√2 = 100 + 50√2∴ The cost of fencing = Rs.3 (100 + 50√2) = Rs.(300 + 150√2) = ₹.512.1

Like? Yes (1) | No   

ABHINAV PUSHPAM   10 years AGO

Use paythagorous theorm.

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MRITUNJAY KUMAR   10 years AGO

Option)6

Like? Yes (1) | No (1)  

Md.Sultan Khichi   10 years AGO

Let x be this other side of isosceles right angle triangle.
So x^2+x^2=(50√2)^2
x=50
So premeter =50+50+50√2=50(2+√2)
Cost=3*50(2+√2)=512.13
Ans. Ob 6

Like? Yes (2) | No (2)  

Vinay Sipani    10 years AGO

Unit of hypotenuse isn't mentioned in the question

If it is assumed to be 50 sqrt (2) metre
For isosceles right angled triangle,remaining two sides are equal.
=> 2 * x^2 = (50 sqrt 2 )^2
=> x = 50 m

Hence,the perimeter of triangle = (100 + 50 sqrt 2 )m
=> Cost = Rs 512.132
=> option 6

Like? Yes (2) | No (2)  

kakali sarkar   10 years AGO

perimeter will be(s)= 50+50+50sqrt2
so the answer = s*3

Like? Yes (1) | No (1)  

Sundar Kumar   10 years AGO

Let the length of each of equal side of the triangle be x m. then,x^2+x^2+(50*sqrt(2))^2=5000
=>2x^2=5000
=>x=50
Perimeter of triangle=50+50+50*sqrt(2)
=100+50+1.4146=170.73m
coin of fencing=Rs.(170.73*3)=Rs.512.16
Answer: Option 6) More than Rs.500

Like? Yes (3) | No (3)  

nikhil   10 years AGO

a^2+a^2=(50*1.4)^2
=>a=50
total perameter=100+50*1.41
total cost=512

Like? Yes (1) | No (1)  

ranjithreddy   10 years AGO

perimeter=170mts
cost of fencing will be 170*3=510

Like? Yes (1) | No (1)  

sasidhar   10 years AGO

since it is an isosceles triangle the sides will b of 50mts. so as given Rs3/mt. hence the fencing for the three sides will be roughly 150(2+sqrt(2)). hence the value will be nearly Rs.512.45.

Like? Yes (1) | No (1)  

CHANDAN   10 years AGO

sides are: 50+50+50sqrt(2) =170.70 m.
cost= 170.70*3= Rs 512.10
so, answer is (6)

Like? Yes (1) | No (1)  

Devendra Marghade   10 years AGO

If the side of the triangular plot=x, then
x^2 + x^2 =[50*Sqrt(2)]^2
x^2=2500, x=50
So perimeter of the plot=2x+50*Sqrt(2)
=100+50*1.414= 170.71
The cost of fencing it at Rs.3 =3*170.71=512.13

Like? Yes (1) | No (1)  

shree   10 years AGO

sides of triangle=50m
perimeter of triangle=50+70.7+50=170.7
cost of fencing=3*170.7=512.1
cost is more than 500Rs.

Like? Yes (1) | No (1)  

Rahul Sharma    10 years AGO

if hypotenuse= 50*sqrt(2)
and triangle is right angled isosceles triangle.
then other two sides = 50, 50

so perimeter = 50+50+50*sqrt(2)
so cost = 3*(50+50+50*sqrt(2)) = 510.15

Like? Yes (1) | No (1)  

PAWAN KUMAR   10 years AGO

Hypotenuse = 50*sqrt(2)
So, p=b= 50m
Perimeter = 50 + 50 + 50*1.414 = 170.7m
Therefore, cost of fencing = Rs 170.7*3 = Rs 512.10 >500. Ans.

Like? Yes (1) | No (1)  

A M ANKIT KALLURAYA   10 years AGO

we know that in an isoceles trialngle any two of the sides are eqal....by tht hypothesis in the right angled triangle,we can conclude tht the three sides are 50sqrt2,50,50.....total length will become 170.41.....cost of the fencing is given by rs3 for every square metre...so the final cost is 512.22 which is more than 500

Like? Yes (1) | No (1)  

Ashwin Dinesh   10 years AGO

[50 + 50 + 50sqrt(2)] * 3 = Rs. 512.13
which is more than Rs 500
which is option 6)

Like? Yes (1) | No (1)  

Tania Chatterjee   10 years AGO

(50+50+50sqrt2)*3=512.13

Like? Yes (1) | No (2)  

Anil Kumar Telikicherla   10 years AGO

The perimeter of the triangle with the said dimensions would be 50+50+50sqrt(2) = 170.7 (Approximately). Cost of fencing at Rs.3/Meter = 170.7*3 = Rs.510.21, greater than 500

Like? Yes (1) | No (2)