M4maths Previous Puzzles

29 Dec 2014 Sequence

What is the next number of the following sequence.
4, 48, 384, 2560, ......

OPtion

1) 15390
2) 18530
3) 15300
4) 18076
5) 15050
6) 16750
7) 17360
8) 15860
9) 15360
10)15450

Solution

1*4 = 4
(1+2)*4^2 = 3*16 = 48
(1+2+3)*4^3 = 6*64 = 384
(1+2+3+4)*4^4 = 10*256 = 2560
Similarly
(1+2+3+4+5)*4^5 = 15*1024 = 15360

Option 9)

Correct Option: 9 Best Solution (23)

~Sandeep~   10 years AGO

nth term = 4^n * (n(n+1)/2)
5th Term = 4^5*(5*6/2) = 4^5*15 = 15360

Like? Yes (9) | No (3)  

Surit Datta   10 years AGO

The series is like :-
4^1 * 1 = 4
4^2 * 3 = 48
4^3 * 6 = 384
4^4 * 10 = 2560
4^5 * 15 = 15360
So option 9
That's it.

Like? Yes (11) | No (5)  

Ashwin Dinesh   10 years AGO

[m*sqrt(n)]^2
where m = 2, 4, 8, 16, 32 i.e. next m = 2m
and n = 1, 3, 6, 10, 15 i.e next n = n+1
so [32*sqrt(15)]^2 = 15360
which is option 9)

Like? Yes (2) | No   

Supriya Mondal   10 years AGO

We can write,
1st number as 4^1*1
2nd number as 4^2*3
3rd number as 4^3*6
4th number as 4^4*10
so 5th number will be 4^5*15=15360
As power of 4 increased by 1 and multiplication number increased like at first 1 then 2 then 3 and so on.
So option 9)15360 is the right answer

Like? Yes (2) | No   

NITHYA   10 years AGO

4^1, 4^2*3,4^3*2,4^4*10,4^5*15.....

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lavanya   10 years AGO

4, 48, 384, 2560,
4^0*1,4*4^1*3,4*4^2*6,4*4^3*10,4*4^4*10
diff between no 1,3,6 10,15 is 2,3,4,5,...
so answer is 15360

Like? Yes (2) | No   

MRITUNJAY   10 years AGO

2^2*1=4
2^4*3=48
2^6*6=384
2^8*10=2560
2^10*15=15360

Like? Yes (2) | No   

sravani   10 years AGO

4* (4^2 * 3) = 48
4* (4^3 *6) =384
4* (4^4 *10) =2560
4* (4^5 *15) =15360

Like? Yes (2) | No (1)  

bikash samanta   10 years AGO

2560×6=15360

Like? Yes (1) | No   

Preethi   10 years AGO

1*2^2 , 3*2^4 , 6*2^6 , 10*2^8 Is the given sequence where 1,3,6,10 are 1,1+2,1+2+3,1+2+3+4
so next is 15*2^10=15360

Like? Yes (1) | No   

Sanu Panji   10 years AGO

(4^1)*1= 4
(4^2)*3= 48
(4^3)*6=384
(4^4)*10=2560
(4^5)*15= 15360

Like? Yes (1) | No   

guru   10 years AGO

4=1x2^2

48=3x2^4

384=6x2^6

2560=10x2^8

So the next number is 15x2^10=15x1024=15360

Like? Yes (1) | No   

BODHU NISHITHA   10 years AGO

4x1=4,4^2*3=48,4^3*6=384,4^4*10=2560,4^5*15=15360

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sanjeev kumar   10 years AGO

Ans 9

Like? Yes (1) | No   

Sravanthi   10 years AGO

4
4^2*3
4^3*6
4^4*10
4^5*15=15360

Like? Yes (1) | No   

payal vyas   10 years AGO

1)4=4X1
2)48=4X4X3
3)384=4x4x4x6
4)2560=4x4x4x4x10
5)4x4x4x4x4x15=15360
as for next no power of 4 is incresed 1 and ending no. series 1,3,6,10,15

Like? Yes (1) | No   

llamar   10 years AGO

4=(2^2)*1
48=(2^4)*3
384=(2^6)*6
2560=(2^8)*10
?? =(2^10)*15
----->1024*15=15360
(the multiplier 1,3,6,10,15 follow the following rule
i.e. the difference b/w consecutive term increases by 1 every time 3-1=2, 6-3=3, 10-6=4, 15-10=5)

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Chandra chur anand   10 years AGO

4^2*3=48
4^3*6=384
4^4*10=2560
4^5*15=15360

Like? Yes (1) | No   

Yuvaraju D   10 years AGO

4*1*1=4
4^2*1*3=48
4^3*2*3=384
4^4*2*5=2560
4^5*3*5=15360

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

Series is (4^1*1), (4^2*3), (4^3*6), (4^4*10), (4^5*15=15360)

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tejaswi vadali   10 years AGO

4=2*2*1
48=4*4*3
384=8*8*6
2560=16*16*10
therefore next sequence should be 32*32*15 because every number is twice its previous number multiple which comes twice.
and the last digits are 1,3(1+2),6(3+3),10(6+4),15(10+5)

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venkatesh.p   10 years AGO

Answer:.
The series is like :-
4^1 * 1 = 4
4^2 * 3 = 48
4^3 * 6 = 384
4^4 * 10 = 2560
4^5 * 15 = 15360

Like? Yes (1) | No   

Jigyasa Kumar   10 years AGO

4^5* 15 = 15360

Like? Yes (1) | No