Surit Datta   10 years AGO

We know
pi*r*r*h is the area volume of
circular pipe
so,
pi*r*r*h = 11
here h = 7
so,
pi*r*r*7 = 11
solving this we get,
r = 1/sqrt(2)
so option 3
that's it.

Like? Yes (29) | No (5)  

Sarabeshwar   10 years AGO

Formula to be used, pi* r^2 *h

(22/7)*r^2 * 7 = 11

r^2 = 1/2

r =1/sqrt(2)

Like? Yes (3) | No   

Supriya Mondal   10 years AGO

Let, inner radius of the pipe is r metre
Then, according the question we can write,
π×r^2×7=11
So, r=1/√2
So, option 3)1/√2 is the right answer

Like? Yes (3) | No   

Jaspalsingh Parmar   10 years AGO

Formula : pi * radius * radius * height
R^2 * 22/7*7 = 11
R^2 = 11/22 = 1/2
R = 1/ (sqrt(2)) answer.

Like? Yes (3) | No   

sheikh shahrukh   10 years AGO

just see the units....
11 m^3/minute=7m/minute * m^2 ( to balance m^3/minute on both sides we multiplied m^2 and m^2 is area so...)
11/7=area of pipe
11/7=22/7 * radius^2
on solving
radius^2=1/2
so radius= 1/sqrt(2 meter)........
answer is option 3 thats it

Like? Yes (3) | No   

JANARTHANAN RAM   10 years AGO

volume of cylinder==pi *(r^2) * h
r^2 * 22/7*7 = 11
r^2 = 11/22 = 1/2
r = 1/ (sqrt(2))

Like? Yes (3) | No   

nitin kishore   10 years AGO

Volume of water flowing through the pipe per minute= pi*(radius)^2 * velocity = 11
so,
radius = 1/sqrt(2) m

Like? Yes (2) | No   

Jay parmar   10 years AGO

Formula : pi * radius * radius * height
R^2 * 22/7*7 = 11
R^2 = 11/22 = 1/2
R = 1/ (sqrt(2)) answer.

Like? Yes (3) | No (1)  

Samyak   10 years AGO

surfacre * velocity = rate

pi*r2 *7 = 11
therefor, r = 0.707

So 1/sqrt(2) = 0.707

Like? Yes (2) | No   

ABHINAV PUSHPAM   10 years AGO

22/7.r^2.h=11
R^2*22/7*7=11
R^2=11/22
R= 1/sqrt(2)
Option 3)

Like? Yes (2) | No   

Meenakshi   10 years AGO

volume=pi*r*r*h
given,h=7 m per min
volume=11 cubic metre per min
11=22/7*r^2*7
11=22*r^2
11/22=r^2
1/2=r^2
1/sqrt(2)=r

Like? Yes (2) | No   

tasho k   10 years AGO

Pi*r^2*h=11
22/7*r*r*7=11
So r=1/sqrt (2

Like? Yes (2) | No   

NANGINEDI RAVITEJA   10 years AGO

area*7=11 so opt 3

Like? Yes (2) | No   

J.DHANDAPANI   10 years AGO

(pi) r^2 (7) = 11 =>r=1/Sqrt(2) m.

Like? Yes (2) | No   

MUKKA ARUN KUMAR   10 years AGO

flow rate=(1/4)*(22/7)*(pipe diameter)*(pipe diameter)*(velocity)

Like? Yes (2) | No   

mandeep   10 years AGO

Area*7=11

Like? Yes (1) | No   

RAKESH   10 years AGO

22/7 * r^2 * 7 = 11

r = 1/Sqrt(2) m

Like? Yes (1) | No   

Anshul Garg   10 years AGO

7*pi*r^2 = 11

Solving for r we get r =1/sqrt(2)

Like? Yes (1) | No   

KALYAN KUMAR REDDY VALLURU   10 years AGO

1/sqrt(2)

Like? Yes (1) | No   

arush gupta   10 years AGO

ans 1/Sqrt(2)

Like? Yes (1) | No   

Sachit Kwatra   10 years AGO

PIE*r^2=VOlume/speed=Area
22/7*r^2=11/7
r=1/sqrt(2)

Like? Yes (1) | No   

KUMAR HARSH   10 years AGO

h=7,r=?
22/7.r^2.h=11
R^2*22/7*7=11
R^2=11/22
R= 1/sqrt(2)

Like? Yes (1) | No   

darshana kumrawat   10 years AGO

let length of pipe = l
radius of pipe = r
volume of pipe = pi*r^2*l
water flowing out in 1 min = (pi*r^2*l)*(7/l) = pi*r^2*7
pi*r^2*7=11
therefore, r = 1/sqrt(2)

Like? Yes (1) | No   

Math Lovers   10 years AGO

Circular pipe is a Cylinder.
Outflow/minute = Volume of cylinder/minute
Volume of cylinder = pi * radius * radius * height

R^2 * 22/7*7 = 11

R^2 = 11/22 = 1/2

R = 1/ (sqrt(2)) answer.

Like? Yes (1) | No   

praveen kumar   10 years AGO

Q=a v
11 = 3.14*7*d^2/4
D= 2^(1/2)

Like? Yes (1) | No   

Sweta Gupta   10 years AGO

(22/7)*r^2*h=11
22/7*r^2=11/7

r= 1/sqrt. 2

Like? Yes (1) | No   

aman aditya   10 years AGO

(22/7)*r^2*7=1
r^2=1/2
r=1/sqrt(2)

Like? Yes (1) | No   

suraj gupta   10 years AGO

area=11/7
22/7 *r*r=11/7
r=1/sqrt(2)

Like? Yes (1) | No   

PRASHANT KUMAR   10 years AGO

pi*r*r*h=11
So as h=v=7
So r=1/sqrt2

Like? Yes (1) | No   

RAVISH KUMAR   10 years AGO

volume of pipe=pi*r^2*h
h=7m
volume=11m^3
11=pi*r^2*7

Like? Yes (1) | No   

sandeep ramchandra pawaskar   10 years AGO

option 3 is correct

Like? Yes (1) | No   

SAGNIK PAL   10 years AGO

(22/7)*(r^2)*7=11
r^2=11/22=1/2
r=1/?(2)

Like? Yes (1) | No   

NESAB JAFAR   10 years AGO

11=(22/7)*7*r^2

Like? Yes (1) | No   

saikiran   10 years AGO

Q=AV
((Phi)*r^2)*7=11
find r

Like? Yes (1) | No   

Abhishek   10 years AGO

Vol of water collected / min = 11
Pi* R^2 * 7 = 11
On solving
R = 1/Rt2

Like? Yes (1) | No   

Devendra Marghade   10 years AGO

If r=radius of the pipe(in m.), then
Flow Rate= Velocity*Cross Sectional Area
11=7*Pi*r^2
r^2=11*7/(22*7)
r=1/Sqrt(2)

Like? Yes (1) | No   

devendrachary   10 years AGO

1/sqrt(2) m

Like? Yes (1) | No   

sompon temtheerakij   10 years AGO

v = 22/7*r^2*h
r^2 = 11*7/22*7 = 1/2
r = 1/sqrt (2) m.

Like? Yes (1) | No   

Pawan Kumar Nag   10 years AGO

Formula : pi * radius * radius * height
R^2 * 22/7*7 = 11
R^2 = 11/22 = 1/2

Like? Yes (1) | No   

shivom pandey   10 years AGO

area*velocity will be equal to water collected outside

Like? Yes (1) | No   

phani krishna   10 years AGO

r=((11*7)/(22*7))^0.5

Like? Yes (1) | No