3 men and 4 women do a work in 10 days as 2 men and 6 women do. 4 men and 8 women starts the same work and after 2 days only women remains in the work for completing it. How many days are required to complete the work.
3 men + 4 women = 2 men + 6 women
1 men = 2 women
Now 4 men + 8 women = 16 women
according to given condition
3 men + 4 women = 10 women do the work in 10 days
So 1 day work of 1 women = 1/100 part
In 2 days work completed = 2*16* 1/100
= 32/100 part
Remaining work = 68/100 part
and Remaining women for work = 8
So number of days required = (68/100)/(8/100) = 68/8 = 17/2
= 8.5
Option 4)
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