A four digit number has all non zero different even digits. What is the probability that first three

Anuradha   9 years AGO

possible digits are 2,4,6,8
increasing order- 246,248,268,468=4
total 3 digit numbers that can be formed=4 * 3* 2=24
Probability=4/24(numbers in increasing order/total number that can be formed)=1/6

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Supriya Mondal   9 years AGO

Four different even digits are 2,4,6,8.
There are total 4*3!=24 numbers of 4 digit number can be form using the above 4 digits.
Only 4 four digits numbers are possible whose first 3 digits are in increasing order.
They are-
i)2468
ii)2486
iii)2684
iv)4682
so, probability that first three digits are in increasing order will be=4/24=1/6
so, option 4)1/6 is the right answer

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moumita   9 years AGO

total no of ways (without repetation) =4! = 24
possibility of first 3 digits in increasing order is-
(i) fixing 8 at the third position , no of ways 3C2 = 3 ways
(ii) fixing 6 at the third position , no of ways 2C2 = 1 way
total possibilities = 3 +1 =4 ways
therefore, probability = 4/24 = 1/6
Ans ( 4) 1/6

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aman aditya   9 years AGO

Total no. possible=4*3*2*1=24
numbers which satisfy the condition are 4 i.e 2468,2486,2684,4682
so 4/24=1/6

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neha gupta   9 years AGO

First we will find total numbers that can be formed using digits 2,4,6,8. they are 4!=24
As first three digits should be in increasing order thus the following four combinations are favourable:
2468
2486
2684
4682
So probability=4/24=1/6

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SAURABH KUMAR SINHA   9 years AGO

The even digits that will form numbers are 2,4,6,8.
So, 4! numbers can be formed using these digits.

Out of which 2468,2684,2486,4682 are those numbers in which first three digits are in increasing number.
So,the required probability = 4÷4!=4÷24=1/6. Ans.

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deepak   9 years AGO

even digits are 2,4,6,8
possible combinations for the 1st 3 digits are 246,248,268,468
and total no. of arrangements possible are 4!
so probability = 4/4!=(1/6)

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Neha Shahi   9 years AGO

first three even digits can be arranged in 4 ways
total no of ways in which 4 non zero even digits can be arranged= 4! =24
so, answer is 1/6

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Yathiraj   9 years AGO

From the below 24 combinations,
2468 4682 6824 8246
2486 4628 6842 8264
2648 4862 6284 8426
2684 4826 6248 8462
2846 4268 6428 8624
2864 4286 6482 8642

the only probabilities are 2468, 2486, 2684 and 4682

so, probability = 4/24 = 1/6

Option 4.

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Adesh   9 years AGO

Total occurence = 4! = 24.
Favourable occurence - 4(2468,2486,2684,4682).

Hence,
Probability= 4/24=1/6.

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vivek raj   9 years AGO

no of favorable outcomes = 2(2468,4682)

total outcomes= 4*3*2=12

p(e)=1/6

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vivek   9 years AGO

total 4 digit no. having all different even number is 4*3*2*1=24
and, desire no. with first three digit in increasing order is 2468,2684,2486,4682=4
so, required probability is 4/24= 1/6

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ksrn theja   9 years AGO

Number starts with only 2 and 4.

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Dileepkumar Palli   9 years AGO

Total number of possibilities =24
Required possibilities are
2468
2684
2684
4682
So probability =4/24=1/6

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Ramesh Sriram   9 years AGO

4 such combinations
4/4!=1/6

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Sirisha   9 years AGO

total no of ways= 4!
favourable cases in frst 3 digits are 246,248,268,468, and last digit is 8 it is 4/24 = 1/6

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atmakuri jagadish   9 years AGO

total samples are 24.
Incresing digits samples are :
2684
2468
2486
4682
which is total 4
so probability is 4/24 - 1/6

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prabhat kumar sharma   9 years AGO

only 4 even digit are available i.e
2,4,6,8
thus total no of ways to arrange them is 4!=24
accrdng to question we can arrange these no in 4 different ways i.e
2468
2486
2684
4682

therefore required probability is = 4/24=1/6

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B Harish Babu   9 years AGO

non zero different even numbers-2,4,6,8
number of ways selecting 3 numbers from the 4 possible numbers=number of ways of arranging first 3 numbers in increasing order=4c3=4
the last number being the remaining number after selecting 3 numbers.'
number of possible 4digit numbers with these conditions=4c3*1=4
total number of 4-digit numbers with non zero different even digits=4*3*2*1=24
probability=4/24=1/6
so option 4 is correct.

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ankit kamboj   9 years AGO

2468 , 2486, 2684 , 4682 are four favourable case out of 24 case so probability = 4/24= 1/6

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ashvini kumar   9 years AGO

no. of ways of forming 4 digit nos with 2,4,6,8=24
no of ways when first three digit in increasing order=4 (2468,2486,2684,4682)
required probability=4/24=1/6

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Mithun Kumar Kesari   9 years AGO

1/6.
let numbers are 1,2,3,4
now possible combinations are (1,2,3), (1,2,4), (1,3,4), (2,3,4)
so total ways = 4
probability = 4/24= 1/6

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kalyani   9 years AGO

first of all, we do have 2468,2486,2684,4682 as the favorable cases satisfying the requirement(first three even digits should maintain increasing order). the total possible cases of getting a 4 digit number with distinct even digits apart from 0 are 4! so finally the probability is 4/4!=1/6

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shaik sharina   9 years AGO

no of possibilities=4[(2,4,6)(2,6,8)(2,4,8)(4,6,8)]
total no of possibilities=24
probability=4/24=1/6

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a.k.gayathridevi   9 years AGO

possibilities
{2 4 6},{2 4 8},{2 6 8},{4 6 8} among 24 combinations
4/24=1/6

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Math Lovers   9 years AGO

Total four digit number = 9*8*7*6

Now first three digits are in increasing order
Number starts from 1 = [7*8/2]*6
Number starts from 2 = [6*7/2]*6
Number starts from 3 = [5*6/2]*6
Number starts from 4 = [4*5/2]*6
Number starts from 5 = [3*4/2]*6
Number starts from 6 = [2*3/2]*6
Number starts from 7 = [1*2/2]*6

so total such number = 84*6

hence prob = (84*6)/( 9*8*7*6 ) = 1/6

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SAGNIK DATTA   9 years AGO

Total possibility =(4*3*2*1)
Favourable cases ; (2,4,6) (2,4,8) (2,6,8) (4,6,8)
so probability =4/24=1/6

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SUSHANT KUMAR   9 years AGO

probability =1/6
total such word possible =1
and total arrangements =6

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